mensuration area volumes Model Questions & Answers, Practice Test for ibps po prelims 2023
ibps po prelims 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Surds & Indices
Ratio & Proportion
Profit & Loss
Time & Work
Simple Interest & Compound Interest
Mensuration: Area & Volumes
A cylinder of height 2x is circumscribed by a sphere of radius 2x such that the circular ends of the cylinder are two small circles on the sphere. What is the ratio of the curved surface area of the cylinder to the surface area of the sphere?
Answer: (b)
In ΔOAB, by Pythagoras theorem,
Radius of cylinder
= $√{OB^2 - OA^2} = √{(2x)^2 - x^2} = √{4x^2 - x^2}$
= $√{3x^2} = √3x$
CSA of the cylinder
= 2πrh = 2.π.$√3x. 2x = 4√3 πx^2$
Surface area of the sphere
= $4πr^2 = 4.π.4x^2 = 16 πx^2$
Ratio of CSA of the cylinder and surface area of the sphere
= ${4√3 πx^2}/{16 π x^2} = √3/4 = √3 : 4$
ABCD is a square, P, Q, R and S are points on the sides AB, BC, CD and DA respectively such that AP = BQ = CR = DS. What is ∠SPQ equal to?
Answer: (d)
In ΔAPS and ΔPBQ,
AS = PB (given)
AP = BQ (given)
and ∠A= ∠B = 90°
(since, ABCD is square)
Therefore, ΔAPS ≅ ΔBQP are congruent.
∴ SP = PQ
∠SPA= ∠BQP and ∠ASP = ∠BPQ
∴ ∠SPQ = 90° (by RHS rule)
30 metallic cylinders of same size are melted and cast in the form of cones having the same radius and height as those of the cylinders.
Consider the following statements :
Statement I : A maximum of 90 cones will be obtained.
Statement II : The curved surface of the cylinder can be flattened in the shape of a rectangle but the curved surface of the cone when flattened has the shape of triangle.
Which one of the following is correct in respect of the above?
Answer: (a)
Let the radius and height of each cylinder be 'r' and 'h' respectively.
Volume of 30 metallic cylinders
= 30 × $π^2$h
Let the no. of cones casted be 'N'
N × $1/3 π r^2h = 30 πr^2h$
N = 90
The curved surface of cylinder in rectangle and curved surface of cone is semi-circle when they are flattened.
So, option (a) is correct.
The perimeter of a triangle is 22 cm. Through each vertex of the triangle, a straight line parallel to the opposite side is drawn. What is the perimeter of triangle formed by these lines?
Answer: (c)
Perimeter of ΔABC = 22
Perimeter of ΔPQR
= 2(AB + BC + AC)
= 2 × 22 = 44
Two circles, each of radius r, with centres P and Q, are such that each circle passes through the centre of the other circle. Then the area common to the circles is less than one-third of the sum of the areas of the two circles by
Answer: (a)
Area of common circle.
< 2 × Area of equilateral triangle APQ
< 2 × $√3/4 r^2 < √3/2 r^2$
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