Model 7 Working with individual wages Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 7 EXERCISES
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Top 200+ Time and Work Problem Solving By Formula Method »
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New 189+ Time & Work MCQs Practice Test for BANK Exams »
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Top 199+ Time & Work MCQs: Men Women Child for BANK Exam »
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Top 199+ Time and Work Efficiency Based Aptitude MCQ Quiz »
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New 299+ Time and Work Aptitude Test On Individual Wages »
The following question based on time & work topic of quantitative aptitude
(a) 18
(b) 16
(c) 24
(d) 20
The correct answers to the above question in:
Answer: (d)
Using Rule 1,
Let the original number of carpenters be x.
$M_1D_1 = M_2D_2$
x × 9 = (x - 5) × 12
9x = 12x - 60
3x = 60 ⇒ x = 20
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Read more working with individual wages Based Quantitative Aptitude Questions and Answers
Question : 1
If x men can do a piece of work in x days, then the number of days in which y men can do the same work is
a) $x^2y$ days
b) $x^2/y$ days
c) xy days
d) $y^2/x$ days
Answer »Answer: (b)
Using Rule 1,
$M_1D_1 = M_2D_2$
$x . x = y . D_2$
$D_2 = x^2/y$ days
Question : 2
If 7 men working 7 hrs a day for each of 7 days produce 7 units of work, then the units of work produced by 5 men working 5 hrs a day for each of 5 days is
a) $343/25$
b) $49/125$
c) $25/343$
d) $125/49$
Answer »Answer: (d)
Using Rule 1,
${M_1D_1T_1}/W_1 = {M_2D_2T_2}/W_2$
${7 × 7 × 7}/7 = {5 × 5 × 5}/W_2$
49 × $W_2$ = 125
$W_2 = 125/49$
Question : 3
Seventy-five men are employed to lay down a railway line in 3 months. Due to certain emergency conditions, the work was to be finished in 18 days. How many more men should be employed to complete the work in the desired time ?
a) 375
b) 350
c) 300
d) 325
Answer »Answer: (c)
Using Rule 1,
$M_1D_1 = M_2D_2$
75 × 90 = $M_2$ × 18
$M_2 = {75 × 90}/18 = 375$
Number of additional men
= 375 - 75 = 300
Question : 4
‘x’ number of men can finish a piece of work in 30 days. If there were 6 men more, the work could be finished in 10 days less. The original number of men is
a) 15
b) 12
c) 6
d) 10
Answer »Answer: (b)
Men | Days |
x | 30 |
↑ | ↓ |
x + 6 | 20 |
x + 6 : x : : 30 : 20
${x + 6}/x = 30/20 = 3/2$
2x + 12 = 3x
3x - 2x = 12 ⇒ x = 12
Using Rule 1,
Here, $M_1 = x, D_1 = 30, M_2 = x + 6, D_2$ = 20
$M_1D_1 = M_2D_2$
x × 30 = (x + 6) × 20
$3x = 2x + 12$ ⇒ x = 12
Question : 5
If the work done by (x –1) men in (x + 1) days is to the work done by (x + 2) men in (x - 1) days are in the ratio 9 : 10, then the value of x is equal to :
a) 8
b) 7
c) 5
d) 6
Answer »Answer: (a)
Using Rule 1,
${M_1D_1}/W_1 = {M_2D_2}/W_2$
$W_1/W_2 = {M_1D_1}/{M_2D_2}$
$9/10 = {(x - 1)(x + 1)}/{(x + 2)(x - 1)} = {x + 1}/{x + 2}$
10x + 10 = 9x + 18
x = 18 - 10 = 8
Question : 6
10 men working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the same work in 12 days ?
a) 15 days
b) 12 days
c) 6 days
d) 10 days
Answer »Answer: (c)
Using Rule 1,
Men | Days | Working hours |
10 | 18 | 6 |
↑ | ↑ | ↓ |
15 | 12 | x |
where, x is working hrs/days
∴ ${15 : 10}/{12 : 18}]$ : : 6 : x
15 × 12 × x = 10 × 18 × 6
$x = {10 × 18 × 6}/{15 × 12} = 6$ hours
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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