Model 7 Working with individual wages Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 7 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on time & work topic of quantitative aptitude

Questions : ‘x’ number of men can finish a piece of work in 30 days. If there were 6 men more, the work could be finished in 10 days less. The original number of men is

(a) 15

(b) 12

(c) 6

(d) 10

The correct answers to the above question in:

Answer: (b)

MenDays
x30
x + 620

x + 6 : x : : 30 : 20

${x + 6}/x = 30/20 = 3/2$

2x + 12 = 3x

3x - 2x = 12 ⇒ x = 12

Using Rule 1,

Here, $M_1 = x, D_1 = 30, M_2 = x + 6, D_2$ = 20

$M_1D_1 = M_2D_2$

x × 30 = (x + 6) × 20

$3x = 2x + 12$ ⇒ x = 12

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Read more working with individual wages Based Quantitative Aptitude Questions and Answers

Question : 1

Some carpenters promised to do a job in 9 days but 5 of them were absent and remaining men did the job in 12 days. The original number of carpenters was

a) 18

b) 16

c) 24

d) 20

Answer: (d)

Using Rule 1,

Let the original number of carpenters be x.

$M_1D_1 = M_2D_2$

x × 9 = (x - 5) × 12

9x = 12x - 60

3x = 60 ⇒ x = 20

Question : 2

If x men can do a piece of work in x days, then the number of days in which y men can do the same work is

a) $x^2y$ days

b) $x^2/y$ days

c) xy days

d) $y^2/x$ days

Answer: (b)

Using Rule 1,

$M_1D_1 = M_2D_2$

$x . x = y . D_2$

$D_2 = x^2/y$ days

Question : 3

If 7 men working 7 hrs a day for each of 7 days produce 7 units of work, then the units of work produced by 5 men working 5 hrs a day for each of 5 days is

a) $343/25$

b) $49/125$

c) $25/343$

d) $125/49$

Answer: (d)

Using Rule 1,

${M_1D_1T_1}/W_1 = {M_2D_2T_2}/W_2$

${7 × 7 × 7}/7 = {5 × 5 × 5}/W_2$

49 × $W_2$ = 125

$W_2 = 125/49$

Question : 4

If the work done by (x –1) men in (x + 1) days is to the work done by (x + 2) men in (x - 1) days are in the ratio 9 : 10, then the value of x is equal to :

a) 8

b) 7

c) 5

d) 6

Answer: (a)

Using Rule 1,

${M_1D_1}/W_1 = {M_2D_2}/W_2$

$W_1/W_2 = {M_1D_1}/{M_2D_2}$

$9/10 = {(x - 1)(x + 1)}/{(x + 2)(x - 1)} = {x + 1}/{x + 2}$

10x + 10 = 9x + 18

x = 18 - 10 = 8

Question : 5

10 men working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the same work in 12 days ?

a) 15 days

b) 12 days

c) 6 days

d) 10 days

Answer: (c)

Using Rule 1,

MenDaysWorking hours
10186
1512x

where, x is working hrs/days

∴ ${15 : 10}/{12 : 18}]$ : : 6 : x

15 × 12 × x = 10 × 18 × 6

$x = {10 × 18 × 6}/{15 × 12} = 6$ hours

Question : 6

If 80 persons can finish a work within 16 days by working 6 hours a day, the number of hours a day, should 64 persons work to finish that very job within 15 days is :

a) 6 hrs.

b) 8 hrs.

c) 5 hrs.

d) 7 hrs.

Answer: (b)

Using Rule 1,

$M_1D_1T_1 = M_2D_2T_2$

80 × 16 × 6 = 64 × 15 × $T_2$

$T_2 = {80 × 16 × 6}/{64 × 15} = 8$ hours

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