Model 7 Working with individual wages Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 7 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on time & work topic of quantitative aptitude

Questions : If 4 men or 8 women can do a piece of work in 15 days, in how many days can 6 men and 12 women do the same piece of work ?

(a) 30 days

(b) 15 days

(c) 20 days

(d) 5 days

The correct answers to the above question in:

Answer: (d)

4 men ≡ 8 women

1 man ≡ 2 women

6 men + 12 women

≡ 12 women + 12 women ≡ 24 women

$M_1D_1 = M_2D_2$

8 × 15 = 24 × $D_2$

$D_2 = {8 × 15}/24$ = 5 days

Using Rule 12,

Here, A = 4, B = 8, a = 15

$A_1 = 6, B_1$ = 12

Required number of days = ${a(A . B)}/{A_1B + B_1A}$

= ${15(4 × 8)}/{6 × 8 + 12 × 4}$

= ${15 × 32}/96$ = 5 days

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Read more working with individual wages Based Quantitative Aptitude Questions and Answers

Question : 1

3 men and 7 women can do a job in 5 days, while 4 men and 6 women can do it in 4 days. The number of days required for a group of 10 women working together, at the same rate as before, to finish the same job is :

a) 20 days

b) 40 days

c) 30 days

d) 36 days

Answer: (a)

3 × 5 men + 7 × 5 women

= 4 × 4 men + 6 × 4 women

16 men - 15 men

= 35 women - 24 women

1 man = 11 women

3 men + 7 women = 40 women

$M_1D_1 = M_2D_2$

40 × 5 = 10 × $D_2$

$D_2$ = 20 days

Using Rule 11
If $A_1$ men and $B_1$ boys can do a certain work in $D_1$ days, Again, $A_2$ men and $B_2$ boys can do the same work in $D_2$ days, then, $A_3$ men and $B_3$ boys can do the same work in
Required time = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days

Here, $A_1 = 3, B_1 = 7, D_1$ = 5

$A_2 = 4, B_2 = 6, D_2$ = 4

$A_3 = 0, B_3$ = 10

Required days = ${D_1D_2(A_1B_2 - A_2B_1)}/{D_1(A_1B_3 - A_3B_1) - D_2(A_2B_3 - A_3 B_2)}$ days

= ${5 × 4(3 × 6 - 4 × 7)}/{5 × (3 × 10 - 0) - 4(4 × 10 - 0)}$

= ${20 × (-10)}/{150 - 160}$ = 20 days

Question : 2

Working 8 hours a day, Anu can copy a book in 18 days. How many hours a day should she work so as to finish the work in 12 days ?

a) 13 hours

b) 11 hours

c) 12 hours

d) 10 hours

Answer: (c)

DaysWorking hours/day
188
12x

$12/18 = 8/x$

where x is hours/days

12x = 18 × 8

$x = {18 × 8}/12$ = 12 hours

Using Rule 1,

Here, $M_1 = 1, D_1 = 18, T_1$ = 8

$M_2 = 1, D_2 = 12, T_2$ = ?

$M_1D_1T_1 = M_2D_2T_2$

1 × 18 × 8 = 1 × 12 × $T_2$

$T_2 = {18 × 8}/12 = 12$ hours

Question : 3

24 men can do a piece of work in 17 days. How many men will be able to do it in 51 days ?

a) 6

b) 12

c) 8

d) 10

Answer: (c)

$M_1D_1 = M_2D_2$

24 × 17 = $M_2$ × 51

$M_2 = {24 × 17}/51$ = 8 men

Question : 4

If 72 men can build a wall of 280 m length in 21 days, how many men could take 18 days to build a similar type of wall of length 100 m?

a) 28

b) 18

c) 30

d) 10

Answer: (c)

Using Rule 1,

We know that

$W_1/{M_1D_1} = W_2/{M_2D_2}$

$280/{72 × 21} = 100/{x × 18}$

Where x = number of men

x × 18 × 280 = 100 × 72 × 21

$x = {100 × 72 × 21}/{18 × 280}$ = 30

Question : 5

Two persons can complete a piece of work in 9 days. How many more persons are needed to complete double the work in 12 days?

a) 1

b) 4

c) 3

d) 2

Answer: (c)

WorkDaysPersons
192
212x

where x = number of persons

∴ ${1 : 2}/{12 : 9}]$ : : 2 : x

1×12 × x = 2 × 9 × 2

$x = {2 × 9 × 2}/12$ = 3

Using Rule 1,

Here, $M_1 = 2, W_1 = 1, D_1$ = 9

$M_2 = ?, W_2 = 2, D_2$ = 12

$M_1D_1W_2 = M_2D_2W_1$

2 × 9 × 2 = $M_2$ × 12 × 1

$M_2 = 36/12$ = 3

Question : 6

7 men can complete a piece of work in 12 days. How many additional men will be required to complete double the work in 8 days ?

a) 7

b) 14

c) 28

d) 21

Answer: (b)

WorkDaysMen
1127
28x

∴ ${1 : 2}/{8 : 12}]$ : : 7 : x

where, x is no. of men

1 × 8 × x = 2 × 12 × 7

$x = {7 × 12 × 2}/8 = 21$

Number of additional men = 21 - 7 = 14

Metod 2 : Using Rule 1,

$M_1D_1W_2 = M_2D_2W_1$

7 × 12 × 2 = $M_2$ × 8 × 1

$M_2 = {7 × 12 × 2}/8 = 21$

No. of additional men = 21 - 7 = 14

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