Model 7 Working with individual wages Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (c)

where x = number of persons

∴ ${1 : 2}/{12 : 9}]$ : : 2 : x

1×12 × x = 2 × 9 × 2

$x = {2 × 9 × 2}/12$ = 3

Using Rule 1,

Here, $M_1 = 2, W_1 = 1, D_1$ = 9

$M_2 = ?, W_2 = 2, D_2$ = 12

$M_1D_1W_2 = M_2D_2W_1$

2 × 9 × 2 = $M_2$ × 12 × 1

$M_2 = 36/12$ = 3

Answer: (c)

Using Rule 1,

We know that

$W_1/{M_1D_1} = W_2/{M_2D_2}$

$280/{72 × 21} = 100/{x × 18}$

Where x = number of men

x × 18 × 280 = 100 × 72 × 21

$x = {100 × 72 × 21}/{18 × 280}$ = 30

Answer: (d)

4 men ≡ 8 women

1 man ≡ 2 women

6 men + 12 women

≡ 12 women + 12 women ≡ 24 women

$M_1D_1 = M_2D_2$

8 × 15 = 24 × $D_2$

$D_2 = {8 × 15}/24$ = 5 days

Using Rule 12,

Here, A = 4, B = 8, a = 15

$A_1 = 6, B_1$ = 12

Required number of days = ${a(A . B)}/{A_1B + B_1A}$

= ${15(4 × 8)}/{6 × 8 + 12 × 4}$

= ${15 × 32}/96$ = 5 days

Answer: (c)

20 men ≡ 24 women

5 men ≡ 6 women

30 men + 12 women = 40 men

$M_1D_1 = M_2D_2$

20 × 20 = 40 × $D_2$

$D_2 = {20 × 20}/40$ = 10 days

Here, A = 20, B = 24, a = 20

$A_1 = 30, B_1$ = 12

Required time = ${a(A . B)}/{A_1B + B_1A}$

= ${20(20 × 24)}/{30 × 24 + 12 × 20}$

= $9600/{720 + 240} = 9600/960$ = 10 days