Model 7 Working with individual wages Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 7 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on time & work topic of quantitative aptitude

Questions : 20 men or 24 women can complete a piece of work in 20 days. If 30 men and 12 women undertake to complete the work, the work will be completed in

(a) 16 days

(b) 15 days

(c) 10 days

(d) 12 days

The correct answers to the above question in:

Answer: (c)

20 men ≡ 24 women

5 men ≡ 6 women

30 men + 12 women = 40 men

$M_1D_1 = M_2D_2$

20 × 20 = 40 × $D_2$

$D_2 = {20 × 20}/40$ = 10 days

Using Rule 12
If A men or B boys can do a certain work in 'a' days, then $A_1$ men and $B_1$ boys can do the same work in
Time taken = $a/{A_1/A + B_1/B} = {a(A . B)}/{A_1B + B_1A}$ days

Here, A = 20, B = 24, a = 20

$A_1 = 30, B_1$ = 12

Required time = ${a(A . B)}/{A_1B + B_1A}$

= ${20(20 × 24)}/{30 × 24 + 12 × 20}$

= $9600/{720 + 240} = 9600/960$ = 10 days

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Read more working with individual wages Based Quantitative Aptitude Questions and Answers

Question : 1

7 men can complete a piece of work in 12 days. How many additional men will be required to complete double the work in 8 days ?

a) 7

b) 14

c) 28

d) 21

Answer: (b)

WorkDaysMen
1127
28x

∴ ${1 : 2}/{8 : 12}]$ : : 7 : x

where, x is no. of men

1 × 8 × x = 2 × 12 × 7

$x = {7 × 12 × 2}/8 = 21$

Number of additional men = 21 - 7 = 14

Metod 2 : Using Rule 1,

$M_1D_1W_2 = M_2D_2W_1$

7 × 12 × 2 = $M_2$ × 8 × 1

$M_2 = {7 × 12 × 2}/8 = 21$

No. of additional men = 21 - 7 = 14

Question : 2

Two persons can complete a piece of work in 9 days. How many more persons are needed to complete double the work in 12 days?

a) 1

b) 4

c) 3

d) 2

Answer: (c)

WorkDaysPersons
192
212x

where x = number of persons

∴ ${1 : 2}/{12 : 9}]$ : : 2 : x

1×12 × x = 2 × 9 × 2

$x = {2 × 9 × 2}/12$ = 3

Using Rule 1,

Here, $M_1 = 2, W_1 = 1, D_1$ = 9

$M_2 = ?, W_2 = 2, D_2$ = 12

$M_1D_1W_2 = M_2D_2W_1$

2 × 9 × 2 = $M_2$ × 12 × 1

$M_2 = 36/12$ = 3

Question : 3

If 72 men can build a wall of 280 m length in 21 days, how many men could take 18 days to build a similar type of wall of length 100 m?

a) 28

b) 18

c) 30

d) 10

Answer: (c)

Using Rule 1,

We know that

$W_1/{M_1D_1} = W_2/{M_2D_2}$

$280/{72 × 21} = 100/{x × 18}$

Where x = number of men

x × 18 × 280 = 100 × 72 × 21

$x = {100 × 72 × 21}/{18 × 280}$ = 30

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