Model 5 Problems with Races Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & distance topic of quantitative aptitude

Questions : A jeep is chasing a car which is 5km ahead. Their respective speed are 90 km/hr and 75 km/ hr. After how many minutes will the jeep catch the car ?

(a) 20 min.

(b) 25 min.

(c) 24 min.

(d) 18 min.

The correct answers to the above question in:

Answer: (a)

Relative speed

= 95 - 75 = 15 kmph

Required time

= $\text"Distance"/ \text"Relative speed"$

= $5/15$ hours = $5/15 × 60$ minutes

= 20 minutes

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Question : 1

Sarthak completed a marathon in 4 hours and 35 minutes. The marathon consisted of a 10 km run followed by 20 km cycle ride and the remaining distance again a run. He ran the first stage at 6 km/hr and then cycled at 16 km/ hr. How much distance did Sarthak cover in total, if his speed in the last run was just half that of his first run?

a) 35 km.

b) 45 km.

c) 40 km.

d) 5 km.

Answer: (a)

Let the total distance be x km.

Time = $\text"Distance"/ \text"Speed"$

According to the question,

$10/6 + 20/16 + {x - 30}/3$

= 4$35/60 = 4{7}/12$

$5/3 + 5/4 + x/3 - 10 = 55/12$

$x/3 + 5/3 + 5/4 - 10 = 55/12$

$x/3 + ({20 + 15 - 120}/12) = 55/12$

$x/3 - 85/12 = 55/12$

$x/3 = 85/12 + 55/12 = 140/12$

$x = 140/12 × 3$ = 35 km.

Question : 2

Two persons ride towards each other from two places 55 km apart, one riding at 12km/hr and the other at 10 km/hr. In what time will they be 11 km apart?

a) 1 hour and 30 minutes

b) 2 hours and 45 minutes

c) 2 hours

d) 2 hours and 30 minutes

Answer: (c)

Relative speed

= 12 + 10 = 22 kmph

Distance covered

= 55 - 11 = 44 km

∴ Required time

= $(44/22)$ hours = 2 hours

Question : 3

A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then A's speed is equal to:

a) 4 km/hr.

b) 7 km/hr.

c) 5 km/hr.

d) 3 km/hr.

Answer: (a)

Let, A's speed = x kmph.

B's speed = (7 - x) kmph

Time = $\text"Distance"/ \text"Speed"$

According to the question,

$24/x + 24/{7 - x} = 14$

$24({7 - x + x}/{x(7 - x)})$ = 14

${24 × 7}/{x(7 - x)}$ = 14

x (7 - x) = 12 = 4 × 3 or 3 × 4

x (7 - x) = 4 (7 - 4) or 3 (7 - 3)

x = 4 or 3

A's speed = 4 kmph.

Question : 4

A can give 40 metres start to B and 70 metres to C in a race of one kilometre How many metres start can B give to C in a race of one kilometre ?

a) 31$1/4$ metre

b) 32 metre

c) 31$3/4$ metre

d) 30 metre

Answer: (a)

According to the question,

When A covers 1000m, B covers

= 1000 - 40 = 960 m

and C covers =1000 - 70 = 930 m

When B covers 960m, C covers 930 m.

When B covers 1000m, C covers

= $930/960 × 1000$ = 968.75 metre

Hence, B gives C a start of

= 1000 - 968.75 = 31.25 metre

Question : 5

Walking at $3/4$ of his usual speed, a man reaches his office 20 minutes late. Then his usual time for walking to his office is :

a) 30 minutes

b) 40 minutes

c) 45 minutes

d) 1 hour

Answer: (d)

Usual time = x minutes

New time = ${4x}/3$ minutes

$(Since, \text"Speed ∞ "\text"1"/\text"Time")$

According to the question,

${4x}/3 - x = 20$

$x/3 = 20$

x = 60 minutes i.e. 1 hour.

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