Model 1 Simplification using VBODMAS Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

? = 5 - [4 - {3 - (3– 3 - 6)}]

= 5 - [4 - { 3 - (– 6)}]

= 5 - [4 - {3 + 6}]

= 5 - [4 - 9]

= 5 + 5 = 10

Answer: (b)

Using Rule 1,

$2/3 × 3/{5/6 ÷ {2/3} of 1{1/4}}$

$2/3 × 3/{5/6 ÷ {2/3} of {5/4}}$

$2/3 × 3/{{5/6} ÷ {10/12}}$

= $2/3 × 3/{5/6 × 12/10} = 2/3 × 3/1 = 2$

Answer: (c)

80 × $√{P}$ = 1120

$√{P} = 1120/80 = 14$

P = $(14)^2 = 196$

Answer: (a)

Using Rule 2,

$1/{5×6} + 1/{6×7} + 1/{7×8} + 1/{8×9} + 1/{9×10} + 1/{10×11}$

= $1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 +1/9 - 1/10 +1/10 - 1/11 +1/11$

= $1/5 - 1/11 ={11 - 5}/55 = 6/55$

Answer: (d)

Using Rule 1,

I. = $3/4 × 6/5 = 9/10$

II. = 3 ÷ $[4/5 × 1/6] = 3 ÷ {2/15} = 45/2$

III. = $[3 ÷ {4/5}] ÷ 6 = {15/4} ÷ 6 = 5/8$

IV. =$3 ÷ {4} × 5/6 = 3 ÷ {10/3} = 9/10$

Obviously, (I) and (IV) are equal

Answer: (d)

Using (x) of Basic Formulae

Let 0.1 = a, 0.2 = b and 0.3 = c

Then, we have,

${a×a×a+b×b×b+c×c×c-3abc}/{a×a+b×b+c×c - ab - bc - ac}$

= ${a^3+b^3+c^3 - 3abc}/{a^2+b^2+c^2 - ab -bc - ac}$

= a + b + c

= 0.1 + 0.2 + 0.3 = 0.6