Mensuration Model Questions Set 1 Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 2 EXERCISES

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The following question based on Mensuration topic of quantitative aptitude

Questions : In the figure given below, PQ is parallel to RS and PR is parallel to QS. If ∠LPR = 35° and ∠ UST = 70°, then what is ∠MPQ equal to ?
mensuration area and volume aptitude mcq 21 50

(a) 75°

(b) 55°

(c) 70°

(d) 80°

The correct answers to the above question in:

Answer: (a)

mensuration-area-and-volume-aptitude-mcq

PQ || RS

PR|| QS

∴ PQRS is a || gm

∠LPR = 35° and ∠UST = 70°

∠UST = ∠RSQ (Vertically opposite)

∠RSQ = ∠RPQ (opposite angle of 11 gm)

∠LPR + ∠RPQ + ∠MPQ = 180°

35° + 70° + ∠MPQ = 180°

∠MPQ = 180 – 105

∠MPQ = 75°

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Read more model questions set 1 Based Quantitative Aptitude Questions and Answers

Question : 1

Consider an equilateral triangle of a side of unit length. A new equilateral triangle is formed by joining the midpoints of one, then a third equilateral triangle is formed by joining the mid-points of second. The process is continued. The perimeter of all triangles, thus formed is

a) 6 units

b) 2 units

c) 3 units

d) Infinity

Answer: (a)

Sides of equilateral triangle are follows:

3, $3/2, 3/4, 3/8$ ... so on

These sequence formed a GP serves.

So sum of GP for Infinite terms.

S = $a/{1 - r}$

Here a = 3, r = $1/2$

S = $3/{1 - 1/2}$ =6 units

Question : 2

Two straight lines AB and AC include an angle. A circle is drawn in this angle which touches both these lines. One more circle is drawn which touches both these lines as well as the previous circle. If the area of the bigger circle is 9 times the area of the smaller circle, then what must be the angle A?

a) 75°

b) 45°

c) 60°

d) 90°

Answer: (c)

mensuration-area-and-volume-aptitude-mcq

Let the radius of the bigger circle be a and radius of the smaller circle be b.

Then the angle made by direct common tangents when two circles of radius a and b touch externally is given by θ = $2sin^{- 1}({a - b}/{a + b})$

We are given that area of the bigger circle = 9 area of the smaller circle

⇒ $πa^2 = 9πb^2 ⇒ a^2 = 9b^2 ⇒ a = 3b$

Let us consider ∠BAC = θ

Thus,

θ = $2 sin^{-1} ({a - b}/{a + b}) = 2 sin^{-1} ({3b - b}/{3b + b}) = 2sin^{-1} ({2b}/{4b})$

= $2 sin^{-1} (1/2) = 2 sin^{-1}$ (sin 30°) = 2 × 30° = 60°

Question : 3

mensuration-area-and-volume-aptitude-mcq
In the figure given above, LM is parallel to QR. If LM divides the ΔPQR such that area of trapezium LMRQ is two times the area of ΔPLM, then what is ${PL}/{PO}$ equal to?

a) $1/2$

b) $1/√2$

c) $1/√3$

d) $1/3$

Answer: (c)

In the given figure.

ar MRQL = 2 ar ΔPLM

Let area of ΔPLM be x, then

∴ the area of trapezium = 2x

∴ ar ΔPQR = 2x + x = 3x

Here it is clear from the given figure that ΔPQR ∼ ΔPLM

mensuration-area-and-volume-aptitude-mcq

∴ ${\text"ar ΔPQR"}/{\text"ar ΔPLM"} = {3x}/x$

${PL^2}/{PQ^2} = 1/3 ∴ = {PL}/{PQ} = 1/√3$

Question : 4

The medians of ΔABC intersect at G. Which one of the following is correct?

a) Three times the area of ΔAGB is equal to the area of ΔABC

b) Five times the area of ΔAGB is equal to four times the area of ΔABC

c) Four times the area of ΔAGB is equal to three times the area of ΔABC

d) None of the above

Answer: (a)

Suppose ΔABC is an equilateral triangle.

A median divides an equilateral triangle into the three equal area of triangles.

ΔAGB = ar ${(ΔABC)}/3$ = ar BGC = ar ΔAGC

∴ ar ΔAGB = $1/3$ ΔABC.

Question : 5

Consider a circle C of radius 6 cm with centre at O. What is the difference in the area of the circle C and the area of the sector of C subtending an angle of 80º at O?

a) 28π $cm^2$

b) 26π $cm^2$

c) 16π $cm^2$

d) 30π$cm^2$

Answer: (a)

mensuration-area-and-volume-aptitude-mcq

Radius of circle, r = 6 cm

∴ Area of circle = $πr^2 = π × 6^2 = 36π cm^2$

and Area of sector subtending an angle of 80° at O

= ${π r^2 θ}/{360°} = {π × 6^2 × 80°}/{360°} = 8 π cm^2$

∴ Required difference = 36π – 8π = 28π $cm^2$

Question : 6

A horse is tethered to one corner of a rectangular grassy field 40 m by 24 m with a rope 14 m long. Over how much area of the field can it graze ?

a) 150 $m^2$

b) 154 $cm^2$

c) 308 $m^2$

d) None of these

Answer: (b)

mensuration-aptitude-mcq

Area of the shaded portion

= $1/4 × π (14)^2$

= 154 $m^2$

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