model 4 mixed discount problems of marked price Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (d)

Let the C.P. of each article be Rs.1

For 15 books, the tradesman gives 1 book free.

C.P. of 15 books = Rs.16

S.P. of 15 books

= $16 × 135/100$ = Rs.$108/5$

S.P. of 1 book

= $108/{5 × 15}$ = Rs.$36/25$

Now, 96% of marked price = $36/25$

Marked price

= ${36 × 100}/{25 × 96} = 3/2 = Rs.1.5$

The required % increase

= ${0.5}/1 × 100$ = 50%

Answer: (b)

First discount = 20%

Price after first discount

= Rs.$(1500 - 20/100 × 1500)$

= Rs.(1500 - 300) = Rs.1200

Let the additional discount be x%

$(1200 - {x × 1200}/100)$ = 1104

1200 - 12x = 1104

12x = 1200 - 1104 = 96

$x = 96/12 = 8%$

Answer: (d)

Printed price = Rs.900

On 40% discount

= $900 - {900 × 40}/100$ = 900 - 360

C.P. for retailer = 540

S.P. = 900

Profit = 900 - 540 = 360

Gain % = ${360 × 100}/540$

= $200/3 = 66{2}/3$%

Answer: (c)

Discount = $120 × 40/100$ = Rs.48

S.P. = Rs.(120 - 48) = Rs.72

Loss = 80 - 72 = Rs.8

Loss % = $8/80 × 100 = 10$%

Here, C.P. = Rs.80, M.P. = Rs.120, D = 40%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$120/80 = {100 + r}/{100 - 40}$

$3/2 = {100 + r}/60$

90 = 100 + r

r =–10% (–ve sign shows loss)

Loss = 10%

Answer: (b)

Let the marked price be x

86% of x = 387

$x = {387 × 100}/86$ = Rs.450

Here, D = 14%, S.P. = Rs.387, M.P. = ?

M.P. = ${\text"SP" × 100}/{100 - D}$

= ${387 × 100}/{100 - 14}$

= $38700/86$ = Rs.450

Answer: (d)

Let the marked price of the article be x

According to the question,

96% of x = 120% of 100

$x × 96/100 = {100 × 120}/100$

$x = {100 × 120}/100$ = Rs.125

Using Rule 6,

Here, r = 20%, D = 4%,

C.P. = Rs.100, M.P. = ?

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$\text"MP"/100 = {100 + 20}/{100 - 4}$

M.P. = ${120 × 100}/96$

= $1000/8$ = Rs.125