model 4 mixed discount problems of marked price Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

Let the marked price of the article be x.

Equivalent discount for successive discounts of 30% and 20%

= $(30 + 20 - {30 × 20}/100)$%

= (50 - 6)% = 44%

(100 - 44)% of x = 2240

${x × 56}/100 = 2240$

$x = {2240 × 100}/56$ = Rs.4000

Answer: (b)

Let the CP of article be x and its marked price be y.

According to the question,

90% of y = 115% of x

${y × 90}/100 = {x × 115}/100$

$x/y =90/115 = 18/23$ ⇒ 18 : 23

Using Rule 6,

Here, r = 15%, D = 10%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

= ${100 + 15}/{100 - 10}$

$\text"M.P."/ \text"C.P."= 115/90$

$\text"C.P."/ \text"M.P."= 90/115$

$\text"C.P."/ \text"M.P."= 18/23$

C.P. : M.P. = 18 : 23

Answer: (d)

Let the printed price of the article be Rs.100

Discount = 40%

C.P. = Rs.(100 - 40) = Rs.60

S.P. = Rs.100

Gain % = $40/60 × 100$

= $200/3 = 66{2}/3$%

Answer: (d)

Marked price

= $100/{100 - 12} × 880$ = Rs.1000

Using Rule 2,

Here, S.P. = Rs.880, D = 12%, M.P. = ?

M.P. = $\text"S.P. × 100"/{100 - D}$

= ${880 × 100}/{100 - 12}$ = Rs.1000