Model 3 Man leaves & joins Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on time & work topic of quantitative aptitude
(a) 24
(b) 30
(c) 22
(d) 17
The correct answers to the above question in:
Answer: (a)
Originally, let there be x men
Now, more men, less days
(x + 6) : x : : 55 : 44
So, ${x + 6}/x = 55/44 = 5/4$
or 5x = 4x + 24 ⇒ x = 24
Using Rule 23Some people finish a certain work in 'D' days. If there were 'a' less people, then the work would be completed in 'd'days more, what was the number of people initially?Required number = $\text"a(D - d)"/\text"d"$ people
Here, D = 55, a = 6, d = 11
No of people initially = $\text"a(D - d)"/\text"d"$
= ${6(55 - 11)}/11$ = 24
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Read more man leaves and joins Based Quantitative Aptitude Questions and Answers
Question : 1
A and B can do a job in 6 and 12 days respectively. They began the work together but A leaves after 3 days. Then the total number of days needed for the completion of the work is :
a) 5 days
b) 6 days
c) 9 days
d) 4 days
Answer »Answer: (b)
A’s one day’s work = $1/6$
B’s one day’s work = $1/12$
(A + B)’s one day’s work = $1/6 + 1/12 = {2 + 1}/12 = 1/4$
(A + B)’s three day’s work = $3/4$
Remaining work = $1 - 3/4 = 1/4$
Total required number of days
= $1/4 × 12/1 + 3$ = 3 + 3 = 6 days
Using Rule 20,
Here, m = 6, n= 12, and p = 3
Time taken by B = $\text"mn - p(m+n)"/ \text"m"$
= ${6 × 12 - (6 + 12) × 3}/6 = {72 - 54}/6$ = 3 days
Total number of days taken to finish the works = 6 days
Question : 2
A and B together can complete a work in 8 days. B alone can complete that work in 12 days. B alone worked for four days. After that how long will A alone take to complete the work ?
a) 18 days
b) 16 days
c) 20 days
d) 15 days
Answer »Answer: (b)
Time taken by A
= ${8 × 12}/128 = {8 × 12}/4 = 24$ days
Work done of by B = $4/12 = 1/3$
Remaining work = $1 - 1/3 = 2/3$
Since, A can complete a work in 24 days
A can complete $2/3$ part of work in 24 × $2/3$ = 16 days
Question : 3
A can do a piece of work in 12 days and B can do it in 18 days. They work together for 2 days and then A leaves. How long will B take to finish the remaining work ?
a) 8 days
b) 10 days
c) 13 days
d) 6 days
Answer »Answer: (c)
(A+B)’s 2 days’ work = $2(1/12 + 1/18) = 10/36$
Remaining work = $1 - 10/36 = 26/36$
Time taken by B to complete $26/36$ part of work
= $26/36$ × 18 = 13 days
Using Rule 20,
Here, m = 12, n = 18, p = 2
Time taken by B = $\text"mn - p(m+n)"/ \text"m"$
= ${12 × 18 - 2(12 + 18)}/12$
= ${216 - 60}/12$ = 13 days
Question : 4
A can complete a piece of work in 18 days, B in 20 days and C in 30 days. B and C together start the work and are forced to leave after 2 days. The time taken by A alone to complete the remaining work is
a) 12 days
b) 15 days
c) 16 days
d) 10 days
Answer »Answer: (b)
(B + C)’s 2 days’ work = $2(1/20 + 1/30)$
= $2({3 + 2}/60) = 1/6$ part
Remaining work = $1 - 1/6 = 5/6$ part
Time taken by A to complete this part of work
= $5/6$ × 18 = 15 days
Question : 5
A man and a boy can complete a work together in 24 days. If for the last six days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone ?
a) 20 days
b) 24 days
c) 36 days
d) 72 days
Answer »Answer: (d)
Suppose a man can complete the work in x days and that boys in y days.
According to question
$24/x + 24/y$ = 1 … (i) × 13
$26/x + 20/y = 1$ … (ii) × 12
$312/x + 312/y = 13$
$312/x + 240/y = 12$
Solving these two equations we get,
$72/y$ = 1 ⇒ y = 72 days
Boys alone can complete the work in 72 days
Using Rule 9If A and B together can finish a certain work in 'a' days. They worked together for 'b' days and then 'B'(or A) left the work. A (or B) finished the rest work in 'd' days, thenTotal time taken by A (or B) alone to complete the work= $\text"ad"/ \text"a - b"$ or $\text"bd"/ \text"a - b"$ days
Here, a = 24, b = 24 - 6 = 18, d = 26 days
Total time taken by B alone to complete the work
= $\text"bd"/ \text"a - b"- 6$
(Since, man has work d or 6 days)
= ${18 × 26}/{24 - 18} - 6$ = 78 - 6 = 72 days
Question : 6
A and B can do a piece of work in 28 and 35 days respectively. They began to work together but A leaves after sometime and B completed remaining work in 17 days. After how many days did A leave ?
a) 9 days
b) 8 days
c) 7$5/9$ days
d) 14$2/5$ days
Answer »Answer: (b)
Let A worked for x days.
According to question
$x/28 + (x + 17)/35 = 1$
${5x + 4(x + 17)}/140 = 1$
5x + 4x + 68 = 140
9x = 140 - 68 = 72
x = 8
∴ A worked for 8 days
time & work Shortcuts and Techniques with Examples
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Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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