Model 3 Man leaves & joins Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 7 EXERCISES

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The following question based on time & work topic of quantitative aptitude

Questions : A certain number of persons can complete a piece of work in 55 days. If there were 6 persons more, the work could be finished in 11 days less. How many persons were originally there ?

(a) 24

(b) 30

(c) 22

(d) 17

The correct answers to the above question in:

Answer: (a)

Originally, let there be x men

Now, more men, less days

(x + 6) : x : : 55 : 44

So, ${x + 6}/x = 55/44 = 5/4$

or 5x = 4x + 24 ⇒ x = 24

Using Rule 23
Some people finish a certain work in 'D' days. If there were 'a' less people, then the work would be completed in 'd'days more, what was the number of people initially?
Required number = $\text"a(D - d)"/\text"d"$ people

Here, D = 55, a = 6, d = 11

No of people initially = $\text"a(D - d)"/\text"d"$

= ${6(55 - 11)}/11$ = 24

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Read more man leaves and joins Based Quantitative Aptitude Questions and Answers

Question : 1

A and B can do a job in 6 and 12 days respectively. They began the work together but A leaves after 3 days. Then the total number of days needed for the completion of the work is :

a) 5 days

b) 6 days

c) 9 days

d) 4 days

Answer: (b)

A’s one day’s work = $1/6$

B’s one day’s work = $1/12$

(A + B)’s one day’s work = $1/6 + 1/12 = {2 + 1}/12 = 1/4$

(A + B)’s three day’s work = $3/4$

Remaining work = $1 - 3/4 = 1/4$

Total required number of days

= $1/4 × 12/1 + 3$ = 3 + 3 = 6 days

Using Rule 20,

Here, m = 6, n= 12, and p = 3

Time taken by B = $\text"mn - p(m+n)"/ \text"m"$

= ${6 × 12 - (6 + 12) × 3}/6 = {72 - 54}/6$ = 3 days

Total number of days taken to finish the works = 6 days

Question : 2

A and B together can complete a work in 8 days. B alone can complete that work in 12 days. B alone worked for four days. After that how long will A alone take to complete the work ?

a) 18 days

b) 16 days

c) 20 days

d) 15 days

Answer: (b)

Time taken by A

= ${8 × 12}/128 = {8 × 12}/4 = 24$ days

Work done of by B = $4/12 = 1/3$

Remaining work = $1 - 1/3 = 2/3$

Since, A can complete a work in 24 days

A can complete $2/3$ part of work in 24 × $2/3$ = 16 days

Question : 3

A can do a piece of work in 12 days and B can do it in 18 days. They work together for 2 days and then A leaves. How long will B take to finish the remaining work ?

a) 8 days

b) 10 days

c) 13 days

d) 6 days

Answer: (c)

(A+B)’s 2 days’ work = $2(1/12 + 1/18) = 10/36$

Remaining work = $1 - 10/36 = 26/36$

Time taken by B to complete $26/36$ part of work

= $26/36$ × 18 = 13 days

Using Rule 20,

Here, m = 12, n = 18, p = 2

Time taken by B = $\text"mn - p(m+n)"/ \text"m"$

= ${12 × 18 - 2(12 + 18)}/12$

= ${216 - 60}/12$ = 13 days

Question : 4

A can complete a piece of work in 18 days, B in 20 days and C in 30 days. B and C together start the work and are forced to leave after 2 days. The time taken by A alone to complete the remaining work is

a) 12 days

b) 15 days

c) 16 days

d) 10 days

Answer: (b)

(B + C)’s 2 days’ work = $2(1/20 + 1/30)$

= $2({3 + 2}/60) = 1/6$ part

Remaining work = $1 - 1/6 = 5/6$ part

Time taken by A to complete this part of work

= $5/6$ × 18 = 15 days

Question : 5

A man and a boy can complete a work together in 24 days. If for the last six days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone ?

a) 20 days

b) 24 days

c) 36 days

d) 72 days

Answer: (d)

Suppose a man can complete the work in x days and that boys in y days.

According to question

$24/x + 24/y$ = 1 … (i) × 13

$26/x + 20/y = 1$ … (ii) × 12

$312/x + 312/y = 13$

$312/x + 240/y = 12$

Solving these two equations we get,

$72/y$ = 1 ⇒ y = 72 days

Boys alone can complete the work in 72 days

Using Rule 9
If A and B together can finish a certain work in 'a' days. They worked together for 'b' days and then 'B'(or A) left the work. A (or B) finished the rest work in 'd' days, then
Total time taken by A (or B) alone to complete the work
= $\text"ad"/ \text"a - b"$ or $\text"bd"/ \text"a - b"$ days

Here, a = 24, b = 24 - 6 = 18, d = 26 days

Total time taken by B alone to complete the work

= $\text"bd"/ \text"a - b"- 6$

(Since, man has work d or 6 days)

= ${18 × 26}/{24 - 18} - 6$ = 78 - 6 = 72 days

Question : 6

A and B can do a piece of work in 28 and 35 days respectively. They began to work together but A leaves after sometime and B completed remaining work in 17 days. After how many days did A leave ?

a) 9 days

b) 8 days

c) 7$5/9$ days

d) 14$2/5$ days

Answer: (b)

Let A worked for x days.

According to question

$x/28 + (x + 17)/35 = 1$

${5x + 4(x + 17)}/140 = 1$

5x + 4x + 68 = 140

9x = 140 - 68 = 72

x = 8

∴ A worked for 8 days

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