type 4 income & expenditure based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on ratio & proportion topic of quantitative aptitude
(a) 99 : 56 : 69
(b) 99 : 69 : 56
(c) 69 : 56 : 99
(d) 56 : 99 : 69
The correct answers to the above question in:
Answer: (d)
Income of A = Rs.7x ;
B = Rs.9x and C = Rs.12x
Expenses of A = Rs.8y ;
B = Rs.9y and C = Rs.15y
7x - 8y = $1/4$ × 7x
7x - ${7x}/4$ = 8y
${21x}/4 = 8y$
21x = 32y.
A’s saving = $1/4 × 7x$
= $1/4 × 32/3 y = 8/3 y$
B’s saving = 9x - 9y
= $9 × 32/21 y - 9y$
= ${96y - 63y}/7 = {33y}/7$
C’s saving = 12 x - 15 y
= 12 × $32/21$ y - 15y
= ${128y - 105y}/7 = {23y}/7$
Required ratio
= $8/3y : 33/7y : 23/7y$
= 56 : 99 : 69
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Read more income and expenditure based ratio and proportion Based Quantitative Aptitude Questions and Answers
Question : 1
The ratio of the income to the expenditure of a family is 10 : 7. If the family’s expenses are Rs.10,500, then savings of the family is
a) Rs.4, 000
b) Rs.5, 000
c) Rs.10, 000
d) Rs.4, 500
Answer »Answer: (d)
Income of the family
= $10/7 × 10500$ = Rs.15000
Savings = 15000 - 10500
= Rs.4500
Question : 2
Incomes of x and y are in the ratio 4:3. Their expenditures are in the ratio 12:7. Both save Rs.3200 at the end of the month, then the income of x is
a) Rs.2000
b) Rs.4000
c) Rs.6000
d) Rs.8000
Answer »Answer: (d)
x’s income = Rs.4a
y’s income = Rs.3a
x’s expenditure = Rs.12b
y’s expenditure = Rs.7b
4a - 12b = 3200
a - 3b = 800 ...(i)
Again, 3a - 7b = 3200 ...(ii)
By equation (i) × 7 - (ii) × 3,
| 7a | - | 21b | = | 5600 |
| 9a | - | 21b | = | 9600 |
| - | + | - | ||
| -2a | = | -4000 |
a = 2000
x’s income = 4a
= 4 × 2000 = Rs.8000
Question : 3
The incomes of A and B are in the ratio 3 : 2 and their expenditures are in the ratio 5 : 3. If each saves Rs.1000, then A’s income is
a) Rs.2000
b) Rs.5000
c) Rs.4000
d) Rs.6000
Answer »Answer: (d)
Let incomes of A and B be Rs.3x and Rs.2x respectively.
Let the expenditures of A and B be Rs.5y and Rs.3y respectively.
According to the question,
3x - 5y = Rs. 1000 ... (i)
2x - 3y = Rs. 1000 ... (ii)
By equation (i) × 2 - (ii) × 3,
| 6x | - | 10y | = | 2000 |
| 6x | - | 9y | = | 3000 |
| - | + | - | ||
| -y | = | -1000 |
y = 1000
From equation (i),
3x - 5 × 1000 = 1000
3x = 1000 + 5000
= Rs.6000 = A’s income
GET ratio & proportion PRACTICE TEST EXERCISES
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
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