Practice Income and expenditure based ratio and proportion - quantitative aptitude Online Quiz (set-1) For All Competitive Exams

Q-1)   The ratio of monthly incomes of A, B is 6 : 5 and their monthly expenditures are in the ratio 4 : 3. If each of them saves Rs.400 per month, find the sum of their monthly incomes.

(a)

(b)

(c)

(d)

Explanation:

Income of A and B

= Rs.6x and 5x

Expenses of A and B

= Rs.4y and 3y

6x - 4y = 400 ...(i)

5x - 3y = 400 ...(ii)

By equation (i)× 3 - (ii) × 4

18x - 12y - 20x + 12y

= 1200 - 1600

2x = 400 ⇒ x = 200

Total income

= 6x + 5x = 11x = Rs.2200


Q-2)   The ratio of the incomes of A and B as well as of B and C is 3 : 2. If one third of A’s income exceeds one fourth of C's income by Rs.1000, what is B’s income in ?

(a)

(b)

(c)

(d)

Explanation:

A : B = 3 : 2 = 9 : 6

B : C = 3 : 2 = 6 : 4

A : B : C = 9 : 6 : 4

${9x}/3 - {4x}/4$= 1000

3x - x = 1000

2x = 1000

x = 500

B’s income = 6x

= 6 × 500 = Rs.3000


Q-3)   A man spends a part of his monthly income and saves the rest. The ratio of his expenditure to the savings is 61 : 6. If his monthly income is Rs.8710, the amount of his monthly savings is

(a)

(b)

(c)

(d)

Explanation:

Expenditure : Savings

= 61 : 6

Sum of the terms of ratio

= 61 + 6 = 67

Total monthly salary

= Rs.8710

Monthly savings

= Rs.$(6/67 × 8710)$ = Rs.780


Q-4)   The ratio of incomes of A and B is 5 : 6. If A gets Rs.1,100 less than B, their total income (in rupees) is

(a)

(b)

(c)

(d)

Explanation:

Let the income of A be Rs.5x

and that of B be Rs.6x.

According to the question,

6x - 5x =1100

x = 1100

Total income

= 5x + 6x = Rs.11x

= Rs.(11×1100) = Rs.12100


Q-5)   A man spends a part of his monthly income and saves a part of it. The ratio of his expenditure to his saving is 26 : 3. If his monthly income is Rs.7250, what is the amount of his monthly savings ?

(a)

(b)

(c)

(d)

Explanation:

Let his expenditures be Rs.26x

and savings be Rs.3x.

26x + 3x = 7250

29x = 7250

$x = 7250/29$ =250

Savings = 3x = Rs.750


Q-6)   The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio 8 : 5 : 2. If C spends Rs.2000 and B saves Rs.700, then A saves

(a)

(b)

(c)

(d)

Explanation:

Let the income of A and B be Rs.5x and Rs.3x respectively.

Let the expenses of A, B and C be Rs.8y, Rs.5y and Rs.2y respectively.

Then, 2y = 2000

$y =2000/2 = 1000$

B saves = Rs.700

3x - 5y = 700

3x - 5×1000 = 700

3x = 700 +5000 = 570

$x = 5700/3 = 1900$

A’s saving = Rs.(5x - 8y)

= Rs.(5×1900 - 8×1000)

= Rs.(9500 - 8000) = Rs.1500


Q-7)   A person bought some rice and wheat for Rs.380. The ratio of weight of rice and wheat is 4 : 3 and the price of equal amount of rice and wheat is in the ratio 5 : 6. The rice was bought of worth

(a)

(b)

(c)

(d)

Explanation:

Rice : Wheat

= 4 × 5 : 3 × 6

= 20 : 18 = 10 : 9

Total cost of rice

= $10/19 × 380$ = Rs.200


Q-8)   If the annual income of A, B and C are in the ratio 1 : 3 : 7 and the total annual income of A and C is Rs.8,00,000, then the monthly salary of B (in Rs.) is

(a)

(b)

(c)

(d)

Explanation:

Let Annual Income of A, B and C be x, 3x and 7x

x + 7x = 800000

8x = 800000

x = 100000

B’s monthly income

= ${100000 × 3}/12$ = Rs.25000


Q-9)   Incomes of x and y are in the ratio 4:3. Their expenditures are in the ratio 12:7. Both save Rs.3200 at the end of the month, then the income of x is

(a)

(b)

(c)

(d)

Explanation:

x’s income = Rs.4a

y’s income = Rs.3a

x’s expenditure = Rs.12b

y’s expenditure = Rs.7b

4a - 12b = 3200

a - 3b = 800 ...(i)

Again, 3a - 7b = 3200 ...(ii)

By equation (i) × 7 - (ii) × 3,

7a-21b=5600
9a-21b=9600
-+-
-2a=-4000

a = 2000

x’s income = 4a

= 4 × 2000 = Rs.8000


Q-10)   The incomes of A and B are in the ratio 3 : 2 and their expenditures are in the ratio 5 : 3. If each saves Rs.1000, then A’s income is

(a)

(b)

(c)

(d)

Explanation:

Let incomes of A and B be Rs.3x and Rs.2x respectively.

Let the expenditures of A and B be Rs.5y and Rs.3y respectively.

According to the question,

3x - 5y = Rs. 1000 ... (i)

2x - 3y = Rs. 1000 ... (ii)

By equation (i) × 2 - (ii) × 3,

6x-10y=2000
6x-9y=3000
-+-
-y=-1000

y = 1000

From equation (i),

3x - 5 × 1000 = 1000

3x = 1000 + 5000

= Rs.6000 = A’s income