type 6 fractions based ratio & proportion problems Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on ratio & proportion topic of quantitative aptitude

Questions : Two numbers are in the ratio 1$1/2 : 2 2/3$, when each of these is increased by 15, they are in the ratio 1$2/3 : 2 1/2$ . The greater of the numbers

(a) 48

(b) 64

(c) 36

(d) 27

The correct answers to the above question in:

Answer: (a)

First number = ${3x}/2$

and second number = ${8x}/3$

According to the question,

${{3x}/2 + 15}/{{8x}/3 + 15}= {5/3}/{5/2}$

${{3x+ 30}/2}/{{8x + 45}/3} = 5/3 × 2/5 = 2/3$

${(3x + 30)× 3}/{(8x + 45) × 2} = 2/3$

32x + 180 = 27x + 270

32x - 27x = 270 - 180

5x = 90

$x = 90/5$ = 18

Larger number = ${8x}/3$

= ${8 × 18}/3$ = 48

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Read more fractions based ratio and proportion problems Based Quantitative Aptitude Questions and Answers

Question : 1

If x : y = 3 : 4 and y : z = 3 : 4, then ${x + y + z}/{3z}$ is equal to

a) $73/84$

b) $37/48$

c) $1/2$

d) $13/27$

Answer: (b)

x : y = 3 : 4 = 9 : 12

y : z = 3 : 4 = 12 : 16

x : y : z = 9 : 12 : 16

${x + y + z}/{3z} - {9k +12k +16k}/{3 × 16k} = 37/48$

Question : 2

If 177 is divided into 3 parts in the ratio $1/2 : 2/3 : 4/5$, then the second part is

a) 72

b) 60

c) 45

d) 75

Answer: (b)

Ratio of division

= $1/2 : 2/3 : 4/5$

= $1/2 × 30 : 2/3 × 30 : 4/5$ × 30

[LCM of 2, 3 and 5 = 30]

= 15 : 20 : 24

Sum of the terms of ratio

= 15 + 20 + 24 = 59

Second part

= Rs.$(20/59 × 177)$ = Rs.60

Question : 3

To get the ratio p : q (for p ≠ q), one has to add a number to each term of the ratio x : y, the number is

a) ${px - qy}/{p - q}$

b) ${py - qx}/{p - q}$

c) ${qx - py}/{p - q}$

d) ${px + qy}/{p - q}$

Answer: (c)

Let the number to be added be z.

${x +z}/{y +z} = p/q$

qx + zq = py + zp

zp - zq = qx - py

z (p - q) = qx - py

z =${qx - py}/{p - q}$

Question : 4

If $x/y = 3/4$, the ratio of (2x + 3y) and (3y - 2x) is

a) 1 : 1

b) 3 : 1

c) 3 : 2

d) 2 : 1

Answer: (b)

$x/y = 3/4$ (Given)

${2x + 3y}/{3y - 2x} = {2x/y +{3y}/y}/{{3y}/y-{2x}/y}$

(Dividing numerator and denominator by y)

= ${2x/y+3}/{3 - 2 x/y} = {2× 3/4+3}/{3-2× 3/4}$

= ${3/2 + 3}/{3 - 3/2}$

= ${3 + 6}/{6 - 3}= 9/3$ = 3 : 1

Question : 5

A and B together have Rs. 6300. If $5/19$ th of A’s amount is equal to $2/5$ th of B’s amount. The amount of ‘B’ is

a) Rs.2300

b) Rs.4000

c) Rs.3800

d) Rs.2500

Answer: (d)

According to the question,

${5A}/19 = {2B}/5$

$5A = {19 × 2B}/5$

A = ${38 × B}/{5× 5}$

A : B = 38 : 25

Sum of the terms of ratio

= 38 + 25 = 63

B’s share = Rs.$(25/63 × 6300)$

= Rs.2500

Question : 6

If x : y = 3 : 4, then the value of (4x - y) : (2x + 3y) is

a) 4 : 3

b) 8 : 3

c) 8 : 9

d) 4 : 9

Answer: (d)

$x/y = 3/4$

${4x - y}/{2x +3y} ={4x/y-1}/{2x/y+3}$

= ${4 × 3/4 - 1}/{2× 3/4+ 3}$

= $2/{3/2+ 3} = {2× 2}/9 = 4 : 9$

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