Model 2 Formula method ‘M1D1W1 = M2D2W2’ Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & work topic of quantitative aptitude

Questions : A, B and C completed a work costing Rs.1,800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio of 5 : 6 : 4, how much amount will be received by A?

(a) Rs.800

(b) Rs.600

(c) Rs.750

(d) Rs.900

The correct answers to the above question in:

Answer: (b)

Using Rule 25,

Ratio of wages of A, B and C respectively

= 5 × 6 : 6 × 4 : 4 × 9

= 30 : 24 : 36 = 5 : 4 : 6

Amount received by A

= $5/{5 + 4 + 6} × 1800$

= $5/15 × 1800$ = Rs.600

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Read more formula method m1d1w1 m2d2w2 Based Quantitative Aptitude Questions and Answers

Question : 1

If there is a reduction in the number of workers in a factory in the ratio 15 : 11 and an increment in their wages in the ratio 22 : 25, then the ratio by which the total wages of the workers should be decreased is

a) 6 : 5

b) 5 : 6

c) 3 :5

d) 3 : 7

Answer: (a)

Using Rule 25,

Required ratio

= 15 × 22 : 11 × 25 = 6 : 5

Question : 2

A and B were assigned to do a job for an amount of Rs.1,200. A alone can do it in 15 days, while B can do it in 12 days. With the help of C, they can finish in 5 days. The share of amount that C earns is

a) Rs.300

b) Rs.400

c) Rs.600

d) Rs.500

Answer: (a)

Using Rule 25,

According to the question,

$1/15 + 1/12 + 1/C = 1/5$

Let C's work in day be $1/C$

$1/C = 1/5 - 1/15 - 1/12$

= ${12 - 4 - 5}/60 = 1/20$

A : B : C = $1/15 : 1/12 : 1/20$ = 4 : 5 : 3

C’s share= $3/12 × 1200$ = Rs.300

Question : 3

Three persons undertake to complete a piece of work for Rs.1,200. The first person can complete the work in 8 days, second person in 12 days and third person in 16 days. They complete the work with the help of a fourth person in 3 days. What does the fourth person get?

a) Rs.180

b) Rs.200

c) Rs.250

d) Rs.225

Answer: (d)

Rule 3 and Rule 25,

If the fourth person completes the work in x days, then

$3/8 + 3/12 + 3/16 + 3/x = 1$

$1/x = 1/3 - 1/8 - 1/12 - 1/16$

= ${16 - 6 - 4 - 3}/48 = 1/16$ ⇒ x = 16

Ratio of wages

= $1/8 : 1/12 : 1/16 : 1/16$

= 6 : 4 : 3 : 3

Sum of ratios = 6 + 4 + 3+3 = 16

Fourth person’s share

= $3/16 × 1200$ = Rs.225

Question : 4

A daily-wage labourer was engaged for a certain number of days for Rs.5,750; but being absent on some of those days he was paid only Rs.5,000. What was his maximum possible daily wage?

a) Rs.125

b) Rs.250

c) Rs.500

d) Rs.375

Answer: (b)

It is required to find the highest common factor of 5750 and 5000,

because his daily wage is their common factor.

$5750/5000 = 1{750}/5000$

Hence, the daily wage is Rs.250.

Question : 5

A certain factory employed 600 men and 400 women and the average wage was Rs.2.55 per day. If a women got 50 paise less than a man, the daily wages of a man and a woman were

a) Man Rs.2.75, Woman Rs.2.25

b) Man Rs.5.30, Woman Rs.2.50

c) Man Rs.3.25, Woman Rs.2.75

d) Man Rs.2.50, Woman Rs.2.00

Answer: (a)

Let daily wages of a man be Rs.x.

Daily wages of a woman

= Rs.$(x - 1/2)$

According to the question,

600x + 400$(x - 1/2)$

= 1000 × 2.55

600x + 400x - 200 = 2550

1000x = 2550 + 200 = 2750

$x = 2750/1000$ = Rs.2.75

Daily wages of a woman

= Rs.(2.75 - 0.5) = Rs.2.25

Question : 6

A man and a boy received Rs.800 as wages for 5 days for the work they did together. The man’s efficiency in the work was three times that of the boy. What are the daily wages of the boy ?

a) Rs.76

b) Rs.56

c) Rs.40

d) Rs.44

Answer: (c)

Man : boy = 3 : 1

Boy's share = $1/4 × 800$ = Rs.200

The daily wages of boy

= Rs.$(200/5)$ = Rs.40

Using Rule 16
If the efficiency to work of A is twice the efficiency to work of B, then, A:B (efficiency) = 2x:x and A:B (time) = t:2t

A:B = 3x:x and A:B = t:3t

Share of boy

= $t/{t + 3t} × 800$ = 200

Daily wages of boy = $200/5$ = Rs.40

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