Practice Formula method m1d1w1 m2d2w2 - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) A labourer was appointed by a contractor on the condition that he would be paid Rs.75 for each day of his work but would be fined at the rate of Rs.15 per day for his absence, apart from losing his wages, After 20 days, the contractor paid the labourer Rs.1140. The number of days the labourer abstained from work was
(a)
(b)
(c)
(d)
Total salary for 20 days
= Rs.(75 × 20) = Rs.1500
Actual salary received = Rs.1140
Difference = Rs.(1500 - 1140) = Rs.360
Money deducted for 1 day’s absence from work
=Rs.(15 + 75) = Rs.90
Number of days he was absent
= $360/90 = 4$ days
Q-2) A skilled, a half skilled and an unskilled labourer work for 7, 8 and 10 days respectively and they together get Rs.369 for their work. If the ratio of their each day’s work is $1/3 : 1/4 : 1/6$, then how much does the trained labourer get (in rupees) ?
(a)
(b)
(c)
(d)
Using Rule 25,
Skilled : half skilled : unskilled
= $1/3 : 1/4 : 1/6$
= $(1/3 × 12) : (1/4 × 12) : (1/6 × 12)$
= 4 : 3 : 2
Share of the trained labourer
= $28/{7 × 4 + 8 × 3 + 2 × 10} × 369$
= $28/{(28 + 24 + 20)} × 369$
= $28/72 × 369$ = Rs.143.50
Q-3) Suman can do a work in 3 days. Sumati can do the same work in 2 days. Both of them finish the work together and get Rs.150. What is the share of Suman ?
(a)
(b)
(c)
(d)
Ratio of Suman’s and Sumati’s 1 day’s work
= $1/3 : 1/2 = 2 : 3$
Sum of the ratios = 2 + 3 = 5
Suman’s share = $2/5 × 150$ = Rs.60
Using Rule 24A can do a work in 'm' days and B can do the same work in 'n' days. If they work together and total wages is R, then.Part of A = $n/{m + n} × R$Part of B = $m/{m + n} × R$
Here, m = 3, n = 2, R = 150
Share of suman = $n/{m + n} × R$
= $2/{3 + 2} × 150 = 2/5 × 150$ = 60
Q-4) A man and a boy received Rs.800 as wages for 5 days for the work they did together. The man’s efficiency in the work was three times that of the boy. What are the daily wages of the boy ?
(a)
(b)
(c)
(d)
Man : boy = 3 : 1
Boy's share = $1/4 × 800$ = Rs.200
The daily wages of boy
= Rs.$(200/5)$ = Rs.40
Using Rule 16If the efficiency to work of A is twice the efficiency to work of B, then, A:B (efficiency) = 2x:x and A:B (time) = t:2t
A:B = 3x:x and A:B = t:3t
Share of boy
= $t/{t + 3t} × 800$ = 200
Daily wages of boy = $200/5$ = Rs.40
Q-5) If there is a reduction in the number of workers in a factory in the ratio 15 : 11 and an increment in their wages in the ratio 22 : 25, then the ratio by which the total wages of the workers should be decreased is
(a)
(b)
(c)
(d)
Using Rule 25,
Required ratio
= 15 × 22 : 11 × 25 = 6 : 5
Q-6) A, B and C together earn Rs.150 per day while A and C together earn Rs.94 and B and C together earn Rs.76. The daily earning of ‘C’ is
(a)
(b)
(c)
(d)
The daily earning of ‘C’
= Daily earning of (A + C) and (B + C) - Daily earning of (A + B + C)
= 94 + 76 - 150 = Rs.20
Q-7) A and B undertake a piece of work for Rs. 250. A alone can do that work in 5 days and B alone can do that work in 15 days. With the help of C, they finish the work in 3 days. If every one gets paid in proportion to work done by them, the amount C will get is :
(a)
(b)
(c)
(d)
Let C alone complete the work in x days.
According to the question,
$1/5 + 1/15 + 1/x = 1/3$
$1/x = 1/3 - 1/5 - 1/15$
= ${5 - 3 - 1}/15 = 1/15$
x = 15 days = Time taken by C alone.
Ratio of the 1 day’s work of A, B and C
= $1/5 : 1/15 : 1/15$ = 3 : 1 : 1
Sum of the terms of ratio
= 3 + 1 + 1 = 5
C’s share
= Rs.$(1/5 × 250)$ = Rs.50
Q-8) Two men undertake a job for Rs.960. They can complete it in 16 days and 24 days respectively. They work along with a third man and take 8 days to complete it. Then the share of the third man should be
(a)
(b)
(c)
(d)
Using Rule 25,
Work done by the third person in 1 day
= $1/8 - 1/16 - 1/24 = {6 - 3 - 2}/48 = 1/48$
Ratio of their 1 day’s work
= $1/16 : 1/24 : 1/48$ = 3 : 2 : 1
Share of the third person
= $1/(3 + 2 + 1) × 960 = 960/6$ = Rs.160
Q-9) A can do a piece of work in 12 days while B alone can do it in 15 days. With the help of C they can finish it in 5 days. If they are paid Rs.960 for the whole work how much money A gets ?
(a)
(b)
(c)
(d)
Rule 2 and Rule 25,
Work done by A and B in 5 days
= $5(1/12 + 1/15) = 5({5 + 4}/60)$
= $9/12 = 3/4$
Time taken by C in doing $1/4$ work = 5 days
C will complete in 20 days.
Ratio of wages = $1/12 : 1/15 : 1/20$ = 5 : 4 : 3
Amount received by A
=$5/12 × 960$ = Rs.400
Q-10) A daily-wage labourer was engaged for a certain number of days for Rs.5,750; but being absent on some of those days he was paid only Rs.5,000. What was his maximum possible daily wage?
(a)
(b)
(c)
(d)
It is required to find the highest common factor of 5750 and 5000,
because his daily wage is their common factor.
$5750/5000 = 1{750}/5000$
Hence, the daily wage is Rs.250.