Model 2 Formula method ‘M1D1W1 = M2D2W2’ Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & work topic of quantitative aptitude

Questions : A man and a boy received Rs.800 as wages for 5 days for the work they did together. The man’s efficiency in the work was three times that of the boy. What are the daily wages of the boy ?

(a) Rs.76

(b) Rs.56

(c) Rs.40

(d) Rs.44

The correct answers to the above question in:

Answer: (c)

Man : boy = 3 : 1

Boy's share = $1/4 × 800$ = Rs.200

The daily wages of boy

= Rs.$(200/5)$ = Rs.40

Using Rule 16
If the efficiency to work of A is twice the efficiency to work of B, then, A:B (efficiency) = 2x:x and A:B (time) = t:2t

A:B = 3x:x and A:B = t:3t

Share of boy

= $t/{t + 3t} × 800$ = 200

Daily wages of boy = $200/5$ = Rs.40

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Read more formula method m1d1w1 m2d2w2 Based Quantitative Aptitude Questions and Answers

Question : 1

A certain factory employed 600 men and 400 women and the average wage was Rs.2.55 per day. If a women got 50 paise less than a man, the daily wages of a man and a woman were

a) Man Rs.2.75, Woman Rs.2.25

b) Man Rs.5.30, Woman Rs.2.50

c) Man Rs.3.25, Woman Rs.2.75

d) Man Rs.2.50, Woman Rs.2.00

Answer: (a)

Let daily wages of a man be Rs.x.

Daily wages of a woman

= Rs.$(x - 1/2)$

According to the question,

600x + 400$(x - 1/2)$

= 1000 × 2.55

600x + 400x - 200 = 2550

1000x = 2550 + 200 = 2750

$x = 2750/1000$ = Rs.2.75

Daily wages of a woman

= Rs.(2.75 - 0.5) = Rs.2.25

Question : 2

A daily-wage labourer was engaged for a certain number of days for Rs.5,750; but being absent on some of those days he was paid only Rs.5,000. What was his maximum possible daily wage?

a) Rs.125

b) Rs.250

c) Rs.500

d) Rs.375

Answer: (b)

It is required to find the highest common factor of 5750 and 5000,

because his daily wage is their common factor.

$5750/5000 = 1{750}/5000$

Hence, the daily wage is Rs.250.

Question : 3

A, B and C completed a work costing Rs.1,800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio of 5 : 6 : 4, how much amount will be received by A?

a) Rs.800

b) Rs.600

c) Rs.750

d) Rs.900

Answer: (b)

Using Rule 25,

Ratio of wages of A, B and C respectively

= 5 × 6 : 6 × 4 : 4 × 9

= 30 : 24 : 36 = 5 : 4 : 6

Amount received by A

= $5/{5 + 4 + 6} × 1800$

= $5/15 × 1800$ = Rs.600

Question : 4

A skilled, a half skilled and an unskilled labourer work for 7, 8 and 10 days respectively and they together get Rs.369 for their work. If the ratio of their each day’s work is $1/3 : 1/4 : 1/6$, then how much does the trained labourer get (in rupees) ?

a) 164

b) 102.50

c) 143.50

d) 201.50

Answer: (c)

Using Rule 25,

Skilled : half skilled : unskilled

= $1/3 : 1/4 : 1/6$

= $(1/3 × 12) : (1/4 × 12) : (1/6 × 12)$

= 4 : 3 : 2

Share of the trained labourer

= $28/{7 × 4 + 8 × 3 + 2 × 10} × 369$

= $28/{(28 + 24 + 20)} × 369$

= $28/72 × 369$ = Rs.143.50

Question : 5

If 6 persons working 8 hours a day earn Rs.8400 per week, then 9 persons working 6 hours a day will earn per week

a) Rs.8400

b) Rs.16800

c) Rs.16200

d) Rs.9450

Answer: (d)

More persons, more earning, Less working hours, less earning = Direct proportion

∴ ${6 : 9}/{8 : 6}]$ : : 8400 : x

where x = required earning

Therefore, 6 × 8 × x = 9 × 6 × 8400

or $x ={9 × 6 × 8400}/{6 × 8}$ = Rs.9450

Using Rule 1
If $M_1$ men can finish $W_1$ work in $D_1$ days and $M_2$ men can finish $W_2$ work in $D_2$ days then, Relation is
${M_1D_1}/{W_1} = {M_2D_2}/{W_2}$ and
If $M_1$ men finish $W_1$ work in $D_1$ days, working $T_1$ time each day and $M_2$ men finish $W_2$ work in $D_2$ days, working $T_2$ time each day, then
${M_1D_1T_1}/{W_1} = {M_2D_2T_2}/{W_2}$

Here, $M_1 = 6, T_1$ = 8, wages = x

$M_2 = 9, T_2$ = 6, wages = 8400

6 × 8 × x = 9 × 6 × 8400

$x = {9 × 6 × 8400}/{6 × 8}$ = Rs.9450

Question : 6

A can do a piece of work in 12 days while B alone can do it in 15 days. With the help of C they can finish it in 5 days. If they are paid Rs.960 for the whole work how much money A gets ?

a) Rs.480

b) Rs.240

c) Rs.400

d) Rs.320

Answer: (c)

Rule 2 and Rule 25,

Work done by A and B in 5 days

= $5(1/12 + 1/15) = 5({5 + 4}/60)$

= $9/12 = 3/4$

Time taken by C in doing $1/4$ work = 5 days

C will complete in 20 days.

Ratio of wages = $1/12 : 1/15 : 1/20$ = 5 : 4 : 3

Amount received by A

=$5/12 × 960$ = Rs.400

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