Model 2 Formula method ‘M1D1W1 = M2D2W2’ Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on time & work topic of quantitative aptitude

Questions : Stanie and Paul take a piece of work for Rs.28,800. One alone could do it in 36 days, the other in 48 days. With the assistance of an expert, they finish it in 12 days. How much remuneration the expert should get ?

(a) Rs.10000

(b) Rs.18000

(c) Rs.12000

(d) Rs.16000

The correct answers to the above question in:

Answer: (c)

Expert’s 1 day’s work

= $1/12 - 1/36 - 1/48$

= ${12 - 4 - 3}/144 = 5/144$

Ratio of their respective work for 1 day

= $1/36 : 1/48 : 5/144$ = 4 : 3 : 5

Expert’s share

= $5/12 × 28800$ = 12000

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Read more formula method m1d1w1 m2d2w2 Based Quantitative Aptitude Questions and Answers

Question : 1

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs.3200. With the help of C they completed the work in 3 days. How much is to be paid to C ?

a) Rs.375

b) Rs.400

c) Rs.800

d) Rs.600

Answer: (b)

Using Rule 25,

A’s 1 day’s work = $1/6$

B’s 1 day’s work = $1/8$

(A + B + C)’s 1 day’s work = $1/3$

C’s 1day’s work

= $1/3 - 1/6 - 1/8 = {8 - 4 - 3}/24 = 1/24$

Ratio of their one day’s work respectively

= $1/6 : 1/8 : 1/24$ = 4 : 3 : 1

Sum of the ratios = 4 + 3 + 1 = 8

C’s share = Rs.$1/8$ × 3200 = Rs.400

Question : 2

A sum of money is sufficient to pay A’ s wages for 21 days and B’s wages for 28 days. The same money is sufficient to pay the wages of both for :

a) 12$1/4$ days

b) 14 days

c) 12 days

d) 24$1/2$ days

Answer: (c)

A's 1 day's work = $1/21$

B's 1 day's work = $1/28$

Total work done by both

= $1/21 + 1/28 = {4 + 3}/84 = 1/12$

Amount is sufficient to pay 12 days wages of both.

Using Rule 2
If A completes a piece of work in 'x' days, and B completes the same work in 'y' days, then,
Work done by A in 1 day = $1/x$, Work done by B in 1 day = $1/y$
Work done by A and B in 1 day = $1/x + 1/y = {x + y}/{xy}$
Total time taken to complete the work by A and B both = $({xy}/{x + y})$

Here, x = 21, y = 28

Required days

= ${xy}/{x + y}= {21 × 28}/{21 + 28}$

= ${21 × 28}/49$ = 12 days

Question : 3

Suman can do a work in 3 days. Sumati can do the same work in 2 days. Both of them finish the work together and get Rs.150. What is the share of Suman ?

a) Rs.30

b) Rs.60

c) Rs.75

d) Rs.70

Answer: (b)

Ratio of Suman’s and Sumati’s 1 day’s work

= $1/3 : 1/2 = 2 : 3$

Sum of the ratios = 2 + 3 = 5

Suman’s share = $2/5 × 150$ = Rs.60

Using Rule 24
A can do a work in 'm' days and B can do the same work in 'n' days. If they work together and total wages is R, then.
Part of A = $n/{m + n} × R$
Part of B = $m/{m + n} × R$

Here, m = 3, n = 2, R = 150

Share of suman = $n/{m + n} × R$

= $2/{3 + 2} × 150 = 2/5 × 150$ = 60

Question : 4

A, B and C are employed to do a piece of work for Rs.575. A and C are supposed to finish $19/23$ of the work together. Amount shall be paid to B is

a) Rs.210

b) Rs.100

c) Rs.475

d) Rs.200

Answer: (b)

Work done by B

= $1 - 19/23 = {23 - 19}/23 = 4/23$

(A + C) : B = $19/23 : 4/23$ = 19 : 4

Sum of ratios = 19 + 4 = 23

B’s share = $4/23 × 575$ = Rs.100

Question : 5

A, B and C can work together for Rs. 550. A and B together are to do $7/11$ of the work. The share of C should be

a) Rs.200

b) Rs.300

c) Rs.450

d) Rs.400

Answer: (a)

Part of work done by C

= $1 - 7/11 = 4/11$

Total amount received = Rs.550

C’s share

= Rs.$(4/11 × 550)$ = Rs.200

Question : 6

A can do a work in 12 days while B can do it in 15 days. They undertake to complete it together for Rs.450. what will be the share of A in this amount of money ?

a) Rs.200

b) Rs.240

c) Rs.300

d) Rs.250

Answer: (d)

Ratio of A’s and B’s 1 day’s work

= $1/12 : 1/15$ = 15 : 12 = 5 : 4

Sum of the terms of ratio

= 5 + 4 = 9

A’s share

= Rs.$(5/9 × 450)$ = Rs.250

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