model 1 Basic formula of LCM & HCF Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 5 EXERCISES

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : The product of two numbers is 216. If the HCF is 6, then their LCM is

(a) 60

(b) 72

(c) 36

(d) 48

The correct answers to the above question in:

Answer: (c)

Let the numbers be 6x and 6y where x and y are prime to each other.

∴ 6x × 6y = 216

⇒ xy = $216/{6 × 6}$ = 6

∴ LCM = 6xy = 6 × 6 = 36

Practice LCM & HCF (model 1 Basic formula of LCM & HCF) Online Quiz

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Read more finding lcm Based Quantitative Aptitude Questions and Answers

Question : 1

The product of two numbers is 1280 and their H.C.F. is 8. The L.C.M. of the number will be :

a) 150

b) 160

c) 140

d) 120

Answer: (b)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

HCF × LCM = Product of two numbers

⇒ 8 × LCM = 1280

⇒ LCM = $1280/8$ =160

Question : 2

The HCF and LCM of two numbers are 12 and 924 respectively. Then the number of such pairs is

a) 1

b) 0

c) 3

d) 2

Answer: (d)

Let the numbers be 12x and 12y where x and y are prime to each other.

∴ LCM = 12xy

∴ 12xy = 924

⇒ xy = 77

∴ Possible pairs = (1,77) and (7,11)

Question : 3

The H.C.F. and L.C.M. of two numbers are 8 and 48 respectively. If one of the number is 24, then the other number is

a) 36

b) 48

c) 16

d) 24

Answer: (c)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

First number × second number = HCF × LCM

⇒ 24 × second number = 8 × 48

∴ Second number =${8 × 48}/24$ = 16

Question : 4

The H.C.F. of two numbers is 8. Which one of the following can never be their L.C.M.?

a) 48

b) 24

c) 60

d) 56

Answer: (c)

HCF of two numbers is 8.

This means 8 is a factor common to both the numbers. LCM is common multiple for the two numbers, it is divisible by the two numbers. So, the required answer = 60

Question : 5

The L.C.M. of three different numbers is 120. Which of the following cannot be their H.C.F.?

a) 12

b) 8

c) 35

d) 24

Answer: (c)

LCM = 2 × 2 × 2 × 3 × 5

Hence, HCF = 4, 8, 12 or 24

According to question

35 cannot be H.C.F. of 120.

Question : 6

The HCF and product of two numbers are 15 and 6300 respectively. The number of possible pairs of the numbers is

a) 3

b) 4

c) 1

d) 2

Answer: (d)

Let the number be 15x and 15y, where x and y are co –prime.

∴ 15x × 15y = 6300

⇒ xy = $6300/{15 ×15}$ = 28

So, two pairs are (7, 4) and (14, 2)

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