model 1 Basic formula of LCM & HCF Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : The product of two numbers is 4107. If the H.C.F. of the numbers is 37, the greater number is

(a) 111

(b) 185

(c) 101

(d) 107

The correct answers to the above question in:

Answer: (a)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

LCM = ${Product of two numbers}/ {HCF}$ = $4107/37$ = 111

Obviously, numbers are 111 and 37 which satisfy the given condition.

Hence, the greater number = 111

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Read more finding lcm Based Quantitative Aptitude Questions and Answers

Question : 1

The HCF of two numbers is 15 and their LCM is 225. If one of the number is 75, then the other number is :

a) 90

b) 105

c) 45

d) 60

Answer: (c)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

First number × Second number = HCF × LCM

⇒ 75 × Second number = 15 × 225

∴ Second number = ${15 × 225}/75$ = 45

Question : 2

The product of two numbers is 2160 and their HCF is 12. Number of such possible pairs is

a) 2

b) 1

c) 4

d) 3

Answer: (a)

HCF = 12

Numbers = 12x and 12y

where x and y are prime to each other.

∴ 12x × 12y = 2160

⇒ xy = $2160/{12 × 12} $

= 15 = 3 × 5, 1 × 15

Possible pairs = (36, 60) and (12, 180)

Question : 3

The H.C.F. and L.C.M. of two 2- digit numbers are 16 and 480 respectively. The numbers are :

a) 60, 72

b) 40, 48

c) 80, 96

d) 64, 80

Answer: (c)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

H.C.F. of the two 2-digit numbers = 16

Hence, the numbers can be expressed as 16x and 16y, where x and y are prime to each other.

Now,

First number × second number = H.C.F. × L.C.M.

⇒ 16x × 16y = 16 × 480

⇒ xy = ${16× 480}/{16 ×16}$ = 30

The possible pairs of x and y, satisfying the condition xy = 30 are : (3, 10), (5, 6), (1, 30), (2, 15)

Since the numbers are of 2-digits each.

Hence, admissible pair is (5, 6)

∴ Numbers are : 16 × 5 = 80 and 16 × 6 = 96

Question : 4

Product of two co-prime numbers is 117. Then their L.C.M. is

a) 9

b) 117

c) 39

d) 13

Answer: (b)

HCF of two-prime numbers = 1

∴ Product of numbers = their LCM = 117

117 = 13 × 9 where 13 & 9 are co-prime. L.C.M (13,9) = 117.

Question : 5

LCM of two numbers is 2079 and their HCF is 27. If one of the number is 189, the other number is

a) 584

b) 297

c) 216

d) 189

Answer: (b)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

Second number = ${H.C.F.× L.C.M.}/{First Number}$

= ${27 × 2079}/189$ = 297

Question : 6

The H.C.F and L.C.M of two numbers are 12 and 336 respectively. If one of the number is 84, the other is

a) 48

b) 36

c) 96

d) 72

Answer: (a)

Using Rule 1 :

1st number × 2nd number = L.C. M. × H.C.F,

First number × second number = HCF × LCM

⇒ 84 × second number = 12 × 336

∴ Second number = ${12 × 336}/84$ = 48

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