model 2 find lcm of numbers Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on LCM & HCF topic of quantitative aptitude

Questions : The least number, which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is

(a) 14400

(b) 6400

(c) 3600

(d) 1600

The correct answers to the above question in:

Answer: (c)

The smallest number divisible by 16, 20 and 24

= LCM of 16, 20 and 24

216,2024
28,10,12,
24,5,6,
 2,5,3

∴LCM = 2×2×2×2×5×3

= $2^2$ × $2^2$ × 5 × 3

∴Required complete square number =$2^2$ × $2^2$ × $5^2$ × $3^2$ = 3600

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Read more find lcm using formula Based Quantitative Aptitude Questions and Answers

Question : 1

The smallest number, which, when divided by 12 or 10 or 8, leaves remainder 6 in each case, is

a) 66

b) 126

c) 186

d) 246

Answer: (b)

Using Rule 5,

When a number is divided by P, Q or R leaving remainders X, Y or Z respectively such that the difference between divisor and remainder in each case is same i.e., (P – X) = (Q – Y) = (R – Z) = T (say) then that (least) number must be in the form of (K – T), where K is LCM of P, Q and R

The smallest number divisible by 12 or 10 or 8

= LCM of 12, 10 and 8 = 120

⇒ Required number =120 + 6 = 126

Question : 2

The least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder is

a) 3363

b) 2523

c) 1683

d) 1677

Answer: (c)

The LCM of 5, 6, 7 and 8 = 840

∴ Required number = 840 k + 3 which is exactly divisible by 9 for some value of k.

Now, 840 k + 3 = 93 × 9 k + (3k + 3)

When k = 2, 3k + 3 = 9, which is divisible by 9.

∴ Required number = 840 × 2 + 3 = 1683

Question : 3

The smallest number, which when increased by 5 is divisible by each of 24,32, 36 and 564, is

a) 427

b) 4320

c) 859

d) 869

Answer: (c)

Required number = (LCM of 24, 32, 36 and 54) – 5

Now,

224,32,36,54
212,16,18,27
26,8,9,27
33,4,9,27
31,4,3,9
 1,4,1,3

LCM = 2 × 2 × 2 × 3 × 3 × 3 × 4 = 864

∴ Required number = 864 – 5

= 859

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