Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
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Top 399+ Trains Based Time and Distance MCQs For BANK SSC »
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New 500+ Aptitude Problems on Train For All BANK SSC Exam »
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Top 499+ Aptitude MCQs on Trains Crossing Bridge/Platform »
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New 500+ Aptitude MCQs on Train Crossing Pole/Post or Man »
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Top 499+ Trains Problems Using Time and Distance For SSC »
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Top 489+ Time And Distance MCQ Problems on Train For BANK »
The following question based on trains topic of quantitative aptitude
(a) 4.5 seconds
(b) 5 seconds
(c) 5.4 seconds
(d) 3.5 seconds
The correct answers to the above question in:
Answer: (a)
Distance covered by train
= Length of train
Speed of train = 60 kmph
= $({60 × 5}/18)$ m./sec.
= $(50/3)$ m./sec.
Required time = $\text"Distance"/ \text"Speed"$
= $(75/{50/3})$ seconds
= ${75 × 3}/50$ seconds = 4.5 seconds
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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A train 150m long passes a telegraphic post in 12 seconds. Find the speed of the train.(in km/hr)
a) 12.5
b) 25
c) 45
d) 50
Answer »Answer: (c)
Distance covered by train in crossing a telegraphic post
= length of train
Speed of train = $\text"Distance"/ \text"Time"$
= $(150/12)$ m./sec.
= $(150/12 × 18/5)$ kmph = 45 kmph
Question : 2
Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?
a) 4 km/hr
b) 5 km/hr
c) 7 km/hr
d) 3 km/hr
Answer »Answer: (b)
Distance covered in 10 minutes at 20kmph
= distance covered in 8 minutes at (20 + x ) kmph
20 × $10/60 = 8/60 (20 + x)$
200 = 160 + 8x
8x = 40 ⇒ $x = 40/8$ = 5 kmph
Question : 3
A train, 120 m long, takes 6 seconds to pass a telegraph post; the speed of train is
a) 62 km/hr
b) 55 km/hr
c) 85 km/hr
d) 72 km/hr
Answer »Answer: (d)
Using Rule 1,
Speed of train
= $\text"Length of train"/ \text"Time taken in crossing the pole"$
= $120/6$ = 20 m/sec
= 20 × $18/5$ = 72 kmph
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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