Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 15 km/hr
(b) 16 km/hr
(c) 12 km/hr
(d) 14 km/hr
The correct answers to the above question in:
Answer: (a)
Using Rule 1,
Speed = $\text"Distance"/ \text"Time"$
=$125/30$ = 41.6 m/s
4.16 m/s = 4.16 × $18/5$ = 15 km/hr
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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?
a) 15 seconds
b) 17 seconds
c) 18 seconds
d) 20 seconds
Answer »Answer: (d)
Using Rule 1,
Speed of train = 54 kmph
= $({54 × 5}/18)$ m/sec = 15 m/sec
Required time = $\text"Length of trains"/ \text"Speedof train"$
= $300/15$ = 20 seconds
Question : 2
If a train, with a speed of 60 km/ hr, crosses a pole in 30 seconds, the length of the train (in metres) is :
a) 900
b) 750
c) 500
d) 1000
Answer »Answer: (c)
Using Rule 1,
Speed of train = 60 kmph
= 60 × $5/18 = 50/3$ m/sec
Length of train = Speed × Time
= $50/3 × 30$ = 500 m
Question : 3
A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :
a) 9
b) 5
c) 18
d) 10
Answer »Answer: (c)
Using Rule 1,
Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$
= $250/50$ = 5 m/sec.
= $(5 × 18/5)$ kmph = 18 kmph
Question : 4
A train 240 metres in length crosses a telegraph post in 16 seconds. The speed of the train is
a) 52 km/hr
b) 54 km/hr
c) 56 km/hr
d) 50 km/hr
Answer »Answer: (b)
When a train crosses a pole it travels a distance equal to its length.
Speed of train
= $240/16$ = 15 m./sec.
= $(15 × 18/5)$ kmph = 54 kmph.
Question : 5
A train 100 metre long is running at a speed of 120 km/hr. The time taken to pass a person standing near the line is
a) 3 seconds
b) 5 seconds
c) 7 seconds
d) 1 second
Answer »Answer: (a)
Speed of train = 120 kmph.
= $({120 × 5}/18)$ m./sec. = $100/3$ m./sec.
Required time = $\text"Length of train"/ \text"Speed of train"$
= $(100/{100/3})$ seconds
= $(100/100 × 3)$ seconds = 3 seconds
Question : 6
A train 150m long passes a km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. The speed ot the second train is :
a) 125 km/hr
b) 25 km/hr
c) 75 km/hr
d) 90 km/hr
Answer »Answer: (d)
Speed of train A
= $150/30$ = 5 m/sec.
Speed of train B = x m/sec.
Relative speed = (5+x) m/sec.
Length of both trains
= Relative speed × Time
300 = (5 + x) × 10
5 + x = $300/10$ = 30
x = 30 - 5 = 25 m/sec.
= $({25 × 18}/5)$ kmph. = 90 kmph.
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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