Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 3 seconds
(b) 5 seconds
(c) 7 seconds
(d) 1 second
The correct answers to the above question in:
Answer: (a)
Speed of train = 120 kmph.
= $({120 × 5}/18)$ m./sec. = $100/3$ m./sec.
Required time = $\text"Length of train"/ \text"Speed of train"$
= $(100/{100/3})$ seconds
= $(100/100 × 3)$ seconds = 3 seconds
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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A train 240 metres in length crosses a telegraph post in 16 seconds. The speed of the train is
a) 52 km/hr
b) 54 km/hr
c) 56 km/hr
d) 50 km/hr
Answer »Answer: (b)
When a train crosses a pole it travels a distance equal to its length.
Speed of train
= $240/16$ = 15 m./sec.
= $(15 × 18/5)$ kmph = 54 kmph.
Question : 2
A train is 125 m long. If the train takes 30 seconds to cross a tree by the railway line, then the speed of the train is :
a) 15 km/hr
b) 16 km/hr
c) 12 km/hr
d) 14 km/hr
Answer »Answer: (a)
Using Rule 1,
Speed = $\text"Distance"/ \text"Time"$
=$125/30$ = 41.6 m/s
4.16 m/s = 4.16 × $18/5$ = 15 km/hr
Question : 3
A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?
a) 15 seconds
b) 17 seconds
c) 18 seconds
d) 20 seconds
Answer »Answer: (d)
Using Rule 1,
Speed of train = 54 kmph
= $({54 × 5}/18)$ m/sec = 15 m/sec
Required time = $\text"Length of trains"/ \text"Speedof train"$
= $300/15$ = 20 seconds
Question : 4
A train 150m long passes a km stone in 30 seconds and another train of the same length travelling in opposite direction in 10 seconds. The speed ot the second train is :
a) 125 km/hr
b) 25 km/hr
c) 75 km/hr
d) 90 km/hr
Answer »Answer: (d)
Speed of train A
= $150/30$ = 5 m/sec.
Speed of train B = x m/sec.
Relative speed = (5+x) m/sec.
Length of both trains
= Relative speed × Time
300 = (5 + x) × 10
5 + x = $300/10$ = 30
x = 30 - 5 = 25 m/sec.
= $({25 × 18}/5)$ kmph. = 90 kmph.
Question : 5
A train 100 metres long meets a man going in opposite direction at 5 km/hr and passes him in 7$1/5$ seconds. What is the speed of the train (in km/hr) ?
a) 60 km/hr
b) 55 km/hr
c) 50 km/hr
d) 45 km/hr
Answer »Answer: (d)
Using Rule 6,
Let speed of train be x kmph
Relative speed = (x + 5) kmph
Length of train
= $100/1000$ km = $1/10$ km
${1/10}/{x + 5} = 36/{5 × 60 × 60}$
$1/{10(x + 5)} = 1/500$
x + 5 = 50 ⇒ x = 45 kmph
Question : 6
A train is running at 36 km/hr. If it crosses a pole in 25 seconds, its length is
a) 250 m
b) 255 m
c) 260 m
d) 248 m
Answer »Answer: (a)
Using Rule 1,
Speed of train = 36 kmph
= $({36 × 5}/18)$ m/sec = 10 m/sec.
Length of train = Speed × time
= 10 × 25 = 250 metre
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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