Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
MOST IMPORTANT quantitative aptitude - 6 EXERCISES
-
Top 399+ Trains Based Time and Distance MCQs For BANK SSC »
-
New 500+ Aptitude Problems on Train For All BANK SSC Exam »
-
Top 499+ Aptitude MCQs on Trains Crossing Bridge/Platform »
-
New 500+ Aptitude MCQs on Train Crossing Pole/Post or Man »
-
Top 499+ Trains Problems Using Time and Distance For SSC »
-
Top 489+ Time And Distance MCQ Problems on Train For BANK »
The following question based on trains topic of quantitative aptitude
(a) 14 seconds
(b) 13.5 seconds
(c) 15.5 seconds
(d) 12 seconds
The correct answers to the above question in:
Answer: (b)
Using Rule 1,
Speed of train (in m/s)
= 20 × $5/18 = 50/9$ m/sec
Required time = $75/50 × 9$
= 13.5 seconds
Discuss Form
Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is
a) 15 sec
b) 18 sec
c) 20 sec
d) 10 sec
Answer »Answer: (c)
Using Rule 5,Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t
Relative speed of train
= (36 - 9) kmph = 27 kmph
= ${27 × 5}/18$ m/sec = $15/2$ m/sec
Required time
= $\text"Length of the train"/ \text"Relative speed"$
= ${150 × 2}/15 = 20$ seconds
Question : 2
A train passes an electrical pole in 20 seconds and passes a platform 250 m long in 45 seconds. Find the length of the train.
a) 200m
b) 300m
c) 250m
d) 400m
Answer »Answer: (a)
Using Rule 1,
If the length of train be x metre, then speed of train
= $x/20 = {x + 250}/45$
$x/4 = {x + 250}/9$
9x = 4x + 1000
9x - 4x = 1000
5x = 1000
x = $1000/5$ = 200 metre
Question : 3
A train 180 m long moving at the speed of 20 m/sec. over-takes a man moving at a speed of 10m/ sec in the same direction. The train passes the man in :
a) 9 sec
b) 18 sec
c) 27 sec
d) 6 sec
Answer »Answer: (b)
Using Rule 5,Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t
Relative speed of man and train
= 20 - 10 = 10m/sec.
Required time = $180/10$ = 18 seconds
Question : 4
A train, 240 m long crosses a man walking along the line in opposite direction at the rate of 3 kmph in 10 seconds. The speed of the train is
a) 75 kmph
b) 83.4 kmph
c) 86.4 kmph
d) 63 kmph
Answer »Answer: (b)
Using Rule 6,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in the opposite direction of train with the speed of 'y' m/s. Then, time taken by the train to cross the man = $(a/{(x + y)})$seconds.
If the speed of train be x kmph then,
Its relative speed = (x + 3) kmph
Time = $\text"Length of the train"/ \text"Relative speed"$
$10/3600 = {240/1000}/{(x + 3)} = 240/{1000(x + 3)}$
x + 3 = 86.4 ⇒ x = 83.4 kmph
Question : 5
If a man walks at the rate of 5 km/hour, he misses a train by 7 minutes. However if he walks at the rate of 6 km/hour, he reaches the station 5 minutes before the arrival of the train. The distance covered by him to reach the station is
a) 7 km
b) 6.25 km
c) 4 km
d) 6 km
Answer »Answer: (d)
Let the required distance be x km.
Difference of time = 7 + 5 = 12
minutes = $1/5$ hour
Time = $\text"Distance"/ \text"Speed"$
According to the question,
$x/5 - x/6 = 1/5$
${6x - 5x}/30 = 1/5$
$x/30 = 1/5$ ⇒ $x = 30/5$ = 6 km.
Question : 6
A train, 300m long, passed a man, walking along the line in the same direction at the rate of 3 km/hr in 33 seconds. The speed of the train is
a) 32 km/h
b) 32$8/11$ km/h
c) 35$8/11$ km/h
d) 30 km/h
Answer »Answer: (c)
Using Rule 5,
If the speed of the train be x kmph,
then relative speed = (x - 3) kmph.
or (x - 3) × $5/18$ m/sec
$300/{(x - 3) × 5/18 = 33$
5400 = 33 × 5 (x - 3)
360 = 11 (x - 3)
11x - 33 = 360
$x = 393/11 = 35{8}/11$ kmph
trains Shortcuts and Techniques with Examples
-
Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
Verbal Reasoning
Question & Answer Quiz
Non Verbal Reasoning
Question & Answer Quiz
Quantitative Aptitude
Question & Answer Quiz
Computer MCQ
Question & Answer Quiz
General English
Question & Answer Quiz
History GK
Question & Answer Quiz
Polity GK
Question & Answer Quiz
Geography GK
Question & Answer Quiz
Economy GK
Question & Answer Quiz
General Awareness GK
Question & Answer Quiz
Recently Added Subject & Categories For All Competitive Exams
New 100+ Compound Interest MCQ with Answers PDF for IBPS
Compound Interest verbal ability questions and answers solutions with PDF for IBPS RRB PO. Aptitude Objective MCQ Practice Exercises all competitive exams
Continue Reading »
100+ Mixture and Alligation MCQ Questions PDF for IBPS
Most importantly Mixture and Alligation multiple choice questions and answers with PDF for IBPS RRB PO. Aptitude MCQ Practice Exercises all Bank Exams
Continue Reading »
IBPS Profit and Loss Questions Solved Problems with PDF
Most important Profit and Loss multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Aptitude MCQ Practice Exercises all competitive exams
Continue Reading »
100+ Average Aptitude Questions Answers solutions MCQ PDF
New Average multiple choice questions and answers with PDF for IBPS RRB PO. 100+ Quantitative Aptitude MCQ Practice Exercises all competitive exams
Continue Reading »