Model 3 Train Vs Bridge/Platform Section-Wise Topic Notes With Detailed Explanation And Example Questions

Answer: (b)

Speed of train = 54 kmph

= $({54 × 5}/18)$ m/sec.

= 15 m/sec.

Required time

= $\text"Length of train and bridge"/ \text" Speed of train"$

= $({200 + 175}/15)$ seconds

= $(375/15)$ seconds = 25 seconds

Answer: (a)

When a train crosses a railway platform, it travels a distance equal to sum of length of platform and its own length.

Speed = 132 kmph

= $132 × 5/18 = 110/3$ m/sec.

Required time

= ${110 + 165}/{110/3}$ seconds

= ${275 × 3}/110 = 7.5$ seconds

Using Rule 10,

Here, x = 110m, u = 132 km/hr.

= $132 × 5/18 = 110/3$ m/sec

y = 165m, t = ?

using t = ${x + y}/u$

t = ${110 + 165}/{110/3}$

= ${275 × 3}/110 = {25 × 3}/10$

= $15/2$ = 7.5 sec

Answer: (b)

Let the length of train be x metre Speed = 90 km/hr

= ${90 × 5}/18$ metre /sec. = 25 metre/sec.

Distance covered in 60 sec.

= 25 × 60 = 1500 metres

Now, according to question,

2x = 1500 ⇒ x = 750 metre

Answer: (c)

Using Rule 10,

Let the length of train be x

According to the question,

${x + 600}/30$ = 30

x + 600 = 900

x = 900 - 600 = 300 m

Answer: (c)

Using Rule 10,

Speed of train = 90 kmph

= $90 × 5/18$ = 25 m/sec

Distance covered

= 230 + 120 = 350 m

Time taken = $350/25$

= 14 seconds

Answer: (a)

Speed of train

= $\text"Sum of length of both trains"/ \text"Time taken"$

${60 × 5}/18 = {110 + 170}/t = 280/t$

t = ${280 × 18}/{60 × 5}$ = 16.8 seconds.