Model 3 Train Vs Bridge/Platform Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

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The following question based on trains topic of quantitative aptitude

Questions : A moving train passes a platform 50 metre long in 14 seconds and a lamp post in 10 seconds. The speed of the train (in km/h) is :

(a) 36

(b) 40

(c) 45

(d) 24

The correct answers to the above question in:

Answer: (c)

Let the length of train be x metre.

When a train crosses a platform, distance covered by it

= length of train and platform.

Speed of train

= ${x + 50}/14 = x/10$

${x + 50}/7 = x/5$

7x = 5x + 250

7x - 5x = 250

2x = 250 ⇒ x = $250/2$ = 125 metre

Speed of train = $x/10$

= $(125/10)$ m./sec.

= $(125/10 × 18/5)$ kmph = 45 kmph.

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Read more crossing bridge platform Based Quantitative Aptitude Questions and Answers

Question : 1

A train 50 metres long passes a platform of length 100 metres in 10 seconds. The speed of the train in metre/second is

a) 10

b) 15

c) 20

d) 50

Answer: (b)

Using Rule 10,
If a train of length x m crosses a platform/tunnel/bridge of length y m with the speed u m/s in t seconds, then,
t = ${x + y}/u$

Speed of train

= $\text"Length of (train + platform)"/ \text"Time taken in crossing"$

= ${(50 + 100)}/10 = 150/10$ = 15 m/sec

Question : 2

A train of length 500 feet crosses a platform of length 700 feet in 10 seconds. The speed of the train is

a) 85 ft/second

b) 100 ft/second

c) 120 ft/second

d) 70 ft/second

Answer: (c)

Speed of train

= $\text"Lengthof(train + platform)"/ \text"Timetaken tocross"$

= $({500 + 700}/10)$ feet/second

= 120 feet/second

Using Rule 10,

Here, x = 500 feet, y = 700 feet

t = 10 seconds, u = ?

using t = ${x + y}/u$

u = ${500 + 700}/10$

= 120ft/second

Question : 3

If a man running at 15 kmph crosses a bridge in 5 minutes, the length of the bridge is

a) 500 metres

b) 750 metres

c) 1250 metres

d) 1000 metres

Answer: (c)

Using Rule 10,

Time = 5 minutes = $1/12$ hour

Length of bridge = Speed × Time

= 15 × $1/12 = 5/4$ km.

= $(5/4 × 1000)$ metre

= 1250 metre

Question : 4

A train, 500 metre long, running at a uniform speed, passes a station in 35 seconds. If the length of the platform is 221 metre, the speed of the train in km/hr is

a) 74.16

b) 24.76

c) 78.54

d) 72$1/35$

Answer: (a)

Speed of train

= $\text"Length of train and platform"/ \text"Time taken in crossing"$

= $({221 + 500}/35)$ metre/second

= $(721/35)$ metre/second

= $({721 × 18}/{35 × 5})$ kmph

= 74.16 kmph

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