type 1 basic simple interest using formula Section-Wise Topic Notes With Detailed Explanation And Example Questions

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The following question based on simple interest topic of quantitative aptitude

Questions : A man lent Rs.60,000, partly at 5% and the rest at 4% simple interest. If the total annual interest is Rs.2560, the money lent at 4% was

(a) Rs.44000

(b) Rs.40000

(c) Rs.45000

(d) Rs.30000

The correct answers to the above question in:

Answer: (a)

Using Rule 1
Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ or
S.I. = ${\text"P × R × T"/100$
P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$
A = P + S.I. or S.I. = A - P

Let the amount lent at 4% be x

Amount lent at 5% = (60000 - x )

According to the question,

${(60000 - x) × 5 × 1}/100 + {x × 4 × 1}/100$ = 2560

300000 - 5x + 4x = 256000

x = 300000 - 256000 = Rs.44000

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Read more basic problems using formula Based Quantitative Aptitude Questions and Answers

Question : 1

A sum of money at simple interest amounts to Rs.1,012 in 2$1/2$ years and to Rs.1,067.20 in 4 years. The rate of interest per annum is :

a) 3%

b) 2.5%

c) 5%

d) 4%

Answer: (d)

Principal + S.I. for $5/2$ years = Rs.1012 ...(i)

Principal + S.I. for 4 years = Rs.1067.20 ...(ii)

Subtracting equation (i) from (ii)

S.I. for $3/2$ years = Rs.55.20

S.I. for $5/2$ years

= $55.20 × 2/3 × 5/2$ = Rs.92

Principal

= Rs.(1012 - 92) = Rs.920

Rate = ${92 × 100}/{920 × 5/2}$

= ${2 × 92 × 100}/{920 × 5}$ = 4%

Using Rule 12,

R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100

= $({1012 - 1067.20}/{1067.20 × 5/2 - 1012 × 4}) × 100$

= ${- 55.2}/({2668 - 4048}) × 100$

= ${- 55.2}/{- 1380} × 100$ = 4%

Question : 2

A person borrows Rs.5,000 for 2 years at 4% per annum simple interest. He immediately lends it to another person at 6$1/4$% per annum simple interest for 2 years. His gain in the transaction is

a) Rs.450

b) Rs.112.50

c) Rs.150

d) Rs.225

Answer: (d)

Using Rule 1,

Case I :

S.I. = ${5000 × 2 × 4}/100$ = Rs.400

Case II :

S.I. = ${5000 × 25 × 2}/{100 × 4}$ = Rs.625

Gain = Rs.(625 - 400) = Rs.225

Question : 3

In how many years will a sum of Rs.3,000 yield a simple interest of Rs.1,080 at 12% per annum ?

a) 2$1/2$ years

b) 3 years

c) 3$1/2$ years

d) 2 years

Answer: (b)

Using Rule 1,

Time = ${SI × 100}/{\text"Principal × Rate"$

= ${1080 × 100}/{3000 × 12} = 3$ years

Question : 4

A sum of money lent out at simple interest amounts to Rs.720 after 2 years and to Rs.1020 after a further period of 5 years. The sum is :

a) Rs.600

b) Rs.500

c) Rs.710

d) Rs.700

Answer: (a)

Principal + SI for 2 years = Rs.720 .... (i)

Principal + SI for 7 years = Rs.1020 .....(ii)

Subtracting equation (i) from (ii) get,

SI for 5 years

= Rs.(1020 - 720) = Rs.300

SI for 2 years

= Rs.300 × $2/5$ = Rs.120

Principal = Rs.(720 - 120) = Rs.600

Using Rule 12,

P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$

= $({1020 × 2 - 720 × 7}/{2 - 7})$

= $({2040 - 5040}/{- 5})$

= ${- 3000}/{- 5}$ = Rs.600

Question : 5

A sum of money amounts to Rs.5,200 in 5 years and to Rs.5,680 in 7 years at simple interest. The rate of interest per annum is

a) 4%

b) 3%

c) 6%

d) 5%

Answer: (c)

P + S.I. for 5 years = 5200 ..(i)

P + SI for 7 years = 5680 ...(ii)

On subtracting equation (i) from (ii),

SI for 2 years = 480

SI for 1 year = Rs.240

From equation (i),

P + 5 × 240 = 5200

P = 5200 - 1200 = Rs.4000

R = ${SI × 100}/{T × P}$

= ${240 × 100}/{1 × 4000}$ = 6%

Using Rule 12
If certain sum P amounts to Rs. $A_1$ in $t_1$ years at rate of R% and the same sum amounts to Rs. $A_2$ in $t_2$ years at same rate of interest R%. Then,
(i) R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100
(ii) P = $({A_2T_1 - A_1T_2}/{T_1 - T_2})$

R = $({A_1 - A_2}/{A_2T_1 - A_1T_2})$ × 100

= $({5200 - 5680}/{5680 × 5 - 5200 × 7}) × 100$

= ${- 480}/{28400 - 36400}$ × 100

= ${- 480}/{- 8000} × 100$ = 6%

Question : 6

What sum of money must be given as simple interest for six months at 4% per annum in order to earn Rs.150 interest?

a) Rs.7500

b) Rs.5000

c) Rs.15000

d) Rs.10000

Answer: (a)

Using Rule 1
Simple Interest (S.I.)= ${\text"Principal × Rate × Time"/100$ or
S.I. = ${\text"P × R × T"/100$
P = ${\text"S.I." × 100}/\text"R × T"$, R = ${\text"S.I." × 100}/\text"P × T"$, T = ${\text"S.I." × 100}/\text"P × R"$
A = P + S.I. or S.I. = A - P

P = ${150 × 100}/4 × 2/1$ = Rs.7500

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