Problem Solving section 4 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 4 EXERCISES
The following question based on Problem Solving topic of verbal reasoning
(a) Geeta is the oldest among the three.
(b) Geeta hates to lose the game.
(c) While playing chess with Geeta and Meena, Bipin often loses.
(d) Meena is the youngest of the three.
The correct answers to the above question in:
Answer: (d)
From the given information, we conclude that ; Bipin is older than Geeta and Geeta is older than Meena.
Hence, Meena is the youngest of the three.
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Read more question and answers set 4 Based Verbal Reasoning Questions and Answers
Question : 1
There are five hobby clubs in a college viz, photography yachting, chess, electronics and gardening. The gardening group meets every second day, the electronics group meets every third day, the chess group meets every fourth day, the yachting group meets every fifth day and the photography group meets every sixth day. How many times do all the five groups meet on the same day within 180 days?
a) 5
b) 10
c) 3
d) 18
Answer »Answer: (c)
Take the LCM. of 2, 3, 4, 5, 6 = 60
So every $60^{th}$ day all five hobby clubs meet. So in a period of 180 days they meet thrice i.e. on $60^{th}, 120^{th}$ and $180^{th}$ day.
Question : 2
Five boys took part in a race. Raj finished before Mohit but behind Gaurav. Ashish finished before Sanchit but behind Mohit. Who won the race ?
a) Gaurav
b) Mohit
c) Raj
d) Ashish
Answer »Answer: (a)
Gaurav – Raj – Mohit – Ashish – Sanchit.
Hence Gaurav won the race.
Question : 3
Seven men, A, B, C, D, E, F and G are standing in a queue in that order. Each one is wearing a cap of different colour like violet, indigo, blue green, yellow, orange and red. D is able to see in front of him green and blue, but not violet. E can see violet and yellow, but not red. G can see caps of all colours other than orange. If E is wearing an indigo coloured cap, then the colour of the cap worn by F is
a) Violet
b) Red
c) Blue
d) Orange
Answer »Answer: (b)
The key point is in this question is "A person can see but caps of all persons standing in front of him can't see his own cap and caps of persons standing behind him.
From the given data he can summarise all the information in a table :
Person | Cap |
A/B/C | Green/blue/yellow |
D | Violet |
E | Indigo |
F | Red |
G | Orange |
Question : 4
A, B, C, D and E belong to five different cities P, Q, R, S and T (not necessarily in that order). Each one of them comes from a different city. Further it is given that
- B and C do not belong to Q.
- B and E do not belong to P and R.
- A and C do not belong to R, S and T.
- D and E do not belong to Q and T.
a) D belongs to R
b) A belongs to Q
c) C belongs to P
d) B belongs to S
Answer »Answer: (d)
Cities → Person ↓ | P | Q | R | S | T |
A | x | √ | x | x | x |
B | x | x | x | x | √ |
C | √ | x | x | x | x |
D | x | x | √ | x | x |
E | x | x | x | √ | x |
∴ B belongs to S is not correct.
Directions:
Study the following information carefully and answer the questions given below :
In a building there are thirteen flats on three floors— II, III and IV. Five flats are unoccupied. Three managers, two teachers, two lawyers and one doctor occupy the remaining flats. There are at least three flats on any floor and not more than six flats on any floor. No two persons of the same profession stay on any floor. On the second floor, out of four flats, one occupant is the lawyer and has only one neighhour. One teacher lives one floor below the other teacher. The doctor is not the neighbour of any of the lawyers. No flat is unoccupied on the third floor
Question : 5
What is the combination of occupants on the second floor?
a) Teacher, Doctor
b) Manager, Doctor
c) Lawyer, Manager
d) Manager, Teacher
Answer »Answer: (c)
Total Number of flats = 13; Unoccupied flats = 5
Occupied flats = 8
Number of flats on second floor = 4
Second floor comprises four flats. One occupant is lawyer and since he has only one neighbour, this implies that out of four flats on second floor, two are unoccupied.
Again, since no flat is unoccupied on the third floor, it implies that there are three unoccupied flats on floor IV.
Since there are at least three flats on any floor and no two same profession stay on any floor and the doctor is not the neighbour of any lawyer, then floor III comprises only three flats. Thus, floor IV comprises six flats (3 occupied + 3 unoccupied).
Since there are three managers and no two same profession stay on any floor, therefore, there will be a manager in each floor. Also there are only two occupant in second floor and one of them is lawyer, therefore, second occupant should be manager.
Again, since there are two teachers, there will be a teacher each on floors III and IV. Again, doctor can't be neighbour of a lawyer. Hence, the doctor and lawyer will not reside on same floor. Therefore, on floor III – either Doctor or Lawyer then,
on floor IV – either Lawyer or Doctor.
Floor | Total Flats | Occupied flats | Unoccupied flats | Occupants |
II | 4 | 2 | 2 | Lawyer, Manager |
III | 3 | 3 | 0 | Teacher, Manager, Lawyer or Doctor |
IV | 6 | 3 | 3 | Teacher, Manager, Doctor or Lawyer |
From above table that combination is Lawyer & Manager.
Question : 6
Who among the following is the neighbour of the other lawyer?
a) Teacher
b) Both the Manager and the Teacher
c) Manager
d) Data inadequate
Answer »Answer: (b)
Total Number of flats = 13; Unoccupied flats = 5
Occupied flats = 8
Number of flats on second floor = 4
Second floor comprises four flats. One occupant is lawyer and since he has only one neighbour, this implies that out of four flats on second floor, two are unoccupied.
Again, since no flat is unoccupied on the third floor, it implies that there are three unoccupied flats on floor IV.
Since there are at least three flats on any floor and no two same profession stay on any floor and the doctor is not the neighbour of any lawyer, then floor III comprises only three flats. Thus, floor IV comprises six flats (3 occupied + 3 unoccupied).
Since there are three managers and no two same profession stay on any floor, therefore, there will be a manager in each floor. Also there are only two occupant in second floor and one of them is lawyer, therefore, second occupant should be manager.
Again, since there are two teachers, there will be a teacher each on floors III and IV. Again, doctor can't be neighbour of a lawyer. Hence, the doctor and lawyer will not reside on same floor. Therefore, on floor III – either Doctor or Lawyer then,
on floor IV – either Lawyer or Doctor.
Floor | Total Flats | Occupied flats | Unoccupied flats | Occupants |
II | 4 | 2 | 2 | Lawyer, Manager |
III | 3 | 3 | 0 | Teacher, Manager, Lawyer or Doctor |
IV | 6 | 3 | 3 | Teacher, Manager, Doctor or Lawyer |
Both the manager and the teacher are the neighbour of other lawyer.
GET Problem Solving PRACTICE TEST EXERCISES
Problem Solving section 1 MCQ
Problem Solving section 2 MCQ
Problem Solving section 3 MCQ
Problem Solving section 4 MCQ
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