Practice Question and answers set 4 - verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1) There are five hobby clubs in a college viz, photography yachting, chess, electronics and gardening. The gardening group meets every second day, the electronics group meets every third day, the chess group meets every fourth day, the yachting group meets every fifth day and the photography group meets every sixth day. How many times do all the five groups meet on the same day within 180 days?
(a)
(b)
(c)
(d)
Take the LCM. of 2, 3, 4, 5, 6 = 60
So every $60^{th}$ day all five hobby clubs meet. So in a period of 180 days they meet thrice i.e. on $60^{th}, 120^{th}$ and $180^{th}$ day.
Directions:
Study the following information and answer questions that follow :
Bankatlal works x hours a day and rests y hours a day. This pattern continues for 1 week, with an exactly opposite pattern next week, and so on for four weeks. Every fifth week he has a different pattern. When he works longer than he rests, his wage per hour is twice what he earns per hour when he rests longer than he works. The following are his daily working hours for the weeks numbered 1 to 13
| 1st week | 5th week | 9th week | 13th week | |
| Rest | 2 | 3 | 4 | - |
| Work | 5 | 7 | 6 | 8 |
A week consist of six days and a month consists of 4 weeks
Q-2) The new manager Khushaldas stipulated that Rs 5 be deducted for every hour of rest and Rs 25 be paid per hour starting 9th week, then what will be the change in Bankatlal's salary for the 3rd month? (Hourly deductions and salaries are constant for all weeks starting 9th week)
(a)
(b)
(c)
(d)
Under new scheme salary for 9th and 11th week
= 2 (25 × 6 – 5 × 4 ) × 6 = Rs 1560
Now salary for 10th and 12th week = 2( 25 × 4 – 5 × 6 ) × 6
= Rs 840
Total salary for 3rd month = 1560 + 840 = Rs 2400
Under previous scheme total salary for 3rd month
= Rs 1920
Difference = 2400 – 1920 = Rs 480
Directions:
Study the following information carefully and answer the questions given below :
In a building there are thirteen flats on three floors— II, III and IV. Five flats are unoccupied. Three managers, two teachers, two lawyers and one doctor occupy the remaining flats. There are at least three flats on any floor and not more than six flats on any floor. No two persons of the same profession stay on any floor. On the second floor, out of four flats, one occupant is the lawyer and has only one neighhour. One teacher lives one floor below the other teacher. The doctor is not the neighbour of any of the lawyers. No flat is unoccupied on the third floor
Q-3) How many flats are there on the third floor?
(a)
(b)
(c)
(d)
Total Number of flats = 13; Unoccupied flats = 5
Occupied flats = 8
Number of flats on second floor = 4
Second floor comprises four flats. One occupant is lawyer and since he has only one neighbour, this implies that out of four flats on second floor, two are unoccupied.
Again, since no flat is unoccupied on the third floor, it implies that there are three unoccupied flats on floor IV.
Since there are at least three flats on any floor and no two same profession stay on any floor and the doctor is not the neighbour of any lawyer, then floor III comprises only three flats. Thus, floor IV comprises six flats (3 occupied + 3 unoccupied).
Since there are three managers and no two same profession stay on any floor, therefore, there will be a manager in each floor. Also there are only two occupant in second floor and one of them is lawyer, therefore, second occupant should be manager.
Again, since there are two teachers, there will be a teacher each on floors III and IV. Again, doctor can't be neighbour of a lawyer. Hence, the doctor and lawyer will not reside on same floor. Therefore, on floor III – either Doctor or Lawyer then,
on floor IV – either Lawyer or Doctor.
| Floor | Total Flats | Occupied flats | Unoccupied flats | Occupants |
| II | 4 | 2 | 2 | Lawyer, Manager |
| III | 3 | 3 | 0 | Teacher, Manager, Lawyer or Doctor |
| IV | 6 | 3 | 3 | Teacher, Manager, Doctor or Lawyer |
Clearly, there are three flats.
Directions:
Study the following information and answer questions that follow :
Bankatlal works x hours a day and rests y hours a day. This pattern continues for 1 week, with an exactly opposite pattern next week, and so on for four weeks. Every fifth week he has a different pattern. When he works longer than he rests, his wage per hour is twice what he earns per hour when he rests longer than he works. The following are his daily working hours for the weeks numbered 1 to 13
| 1st week | 5th week | 9th week | 13th week | |
| Rest | 2 | 3 | 4 | - |
| Work | 5 | 7 | 6 | 8 |
A week consist of six days and a month consists of 4 weeks
Q-4) Referring to the data given in previous question, Bankatlal's average monthly salary at the end of the first four months will be
(a)
(b)
(c)
(d)
Salary for 5th and 7th week = 2 × 7 × 20 × 6 = Rs 1680
Salary for 6th and 8th week = 2 × 3 × 10 × 6 = Rs 360
Salary for 2nd month = 1680 + 360 = Rs 2040
Similarly salary for 3rd month
= 2(6 × 20 × 6) + 2 ( 4 × 10 × 6)
= 1440 + 480 = Rs 1920
Salary for 4th month = 2(8 × 20 × 6) + 2 (0) = Rs 1920
Salary at the end of 4 months
= 1440 + 2040 + 1920 + 1920
= Rs 7320
∴ Average monthly salary = ${7320}/4$ = Rs 1830
Directions:
Study the following information and answer questions that follow :
Bankatlal works x hours a day and rests y hours a day. This pattern continues for 1 week, with an exactly opposite pattern next week, and so on for four weeks. Every fifth week he has a different pattern. When he works longer than he rests, his wage per hour is twice what he earns per hour when he rests longer than he works. The following are his daily working hours for the weeks numbered 1 to 13
| 1st week | 5th week | 9th week | 13th week | |
| Rest | 2 | 3 | 4 | - |
| Work | 5 | 7 | 6 | 8 |
A week consist of six days and a month consists of 4 weeks
Q-5) If Bankatlal is paid Rs. 20 per working hour in the 1st week, what is his salary for the 1st month?
(a)
(b)
(c)
(d)
Salary in the first week = Rs 20 per working hour
As the working pattern changes next week, so wage/hr for the 2nd and fourth week = ${20}/2$ = 10
Work and Rest hrs/day for the 2nd and 4th weeks respectively are 2 and 5 hrs.
A week consist of 6 days and a month of 4 week
Salary from 1st and 3rd week = 20 × 5 × 2 × 6 = Rs 1200
Salary for 2nd and 4th week = 2 × 10 × 6 × 2 = Rs 240
Salary for 1st month = 1200 + 240 = Rs 1440
Directions:
Study the following information and answer questions that follow :
Bankatlal works x hours a day and rests y hours a day. This pattern continues for 1 week, with an exactly opposite pattern next week, and so on for four weeks. Every fifth week he has a different pattern. When he works longer than he rests, his wage per hour is twice what he earns per hour when he rests longer than he works. The following are his daily working hours for the weeks numbered 1 to 13
| 1st week | 5th week | 9th week | 13th week | |
| Rest | 2 | 3 | 4 | - |
| Work | 5 | 7 | 6 | 8 |
A week consist of six days and a month consists of 4 weeks
Q-6) Using the data in the previous questions, what will be the total earning of Bankatlal at the end of sixteen weeks
(a)
(b)
(c)
(d)
According to conditions salary for first 3 months
= 1440 + 2040 + 2400 = Rs 5880
Salary for 4th month (13th to 16th week)
= 2(25 × 8 × 6) + 2(0 - 8 × 5 × 6) = 2400 – 480 = Rs 1920
Total salary for 16 weeks = 5880 + 1920 = Rs 7800
Directions:
Study the following information carefully and answer the questions given below :
In a building there are thirteen flats on three floors— II, III and IV. Five flats are unoccupied. Three managers, two teachers, two lawyers and one doctor occupy the remaining flats. There are at least three flats on any floor and not more than six flats on any floor. No two persons of the same profession stay on any floor. On the second floor, out of four flats, one occupant is the lawyer and has only one neighhour. One teacher lives one floor below the other teacher. The doctor is not the neighbour of any of the lawyers. No flat is unoccupied on the third floor
Q-7) How many flats are occupied on the fourth floor?
(a)
(b)
(c)
(d)
Total Number of flats = 13; Unoccupied flats = 5
Occupied flats = 8
Number of flats on second floor = 4
Second floor comprises four flats. One occupant is lawyer and since he has only one neighbour, this implies that out of four flats on second floor, two are unoccupied.
Again, since no flat is unoccupied on the third floor, it implies that there are three unoccupied flats on floor IV.
Since there are at least three flats on any floor and no two same profession stay on any floor and the doctor is not the neighbour of any lawyer, then floor III comprises only three flats. Thus, floor IV comprises six flats (3 occupied + 3 unoccupied).
Since there are three managers and no two same profession stay on any floor, therefore, there will be a manager in each floor. Also there are only two occupant in second floor and one of them is lawyer, therefore, second occupant should be manager.
Again, since there are two teachers, there will be a teacher each on floors III and IV. Again, doctor can't be neighbour of a lawyer. Hence, the doctor and lawyer will not reside on same floor. Therefore, on floor III – either Doctor or Lawyer then,
on floor IV – either Lawyer or Doctor.
| Floor | Total Flats | Occupied flats | Unoccupied flats | Occupants |
| II | 4 | 2 | 2 | Lawyer, Manager |
| III | 3 | 3 | 0 | Teacher, Manager, Lawyer or Doctor |
| IV | 6 | 3 | 3 | Teacher, Manager, Doctor or Lawyer |
There are three flats occupied
Q-8) My son adores chocolates. He likes biscuits. But he hates apples. I told him that he can buy as many chocolates he wishes. But then he must have biscuits twice the number of chocolates and apples more than biscuits and chocolates together. Each chocolate costs Re. 1. The cost of apple is twice of chocolate and four biscuits are worth of one apple. Then which of the following can be the amount that I spent on that evening on my son?
(a)
(b)
(c)
(d)
If number of chocolates is NC then those of biscuits
$N_B = 2N_C$
and number of apples i.e $N_A > 3N_C$
also, total amount spent
= $2N_A + N_C + 1/4 (2N_B) = 2N_A + 2N_C$
(note that amount of money spent is even number)
option (b) 33 = 8 + 24 + 1
but 2$N_A$ ≠ 25
option (c) is not possible
So, option (a) 34 = 8+ 24 + 2
$↙{even}2N_A, [N_A > 3N_C also]↙{satisfied}$
So, option (c) is correct
Q-9) Five boys took part in a race. Raj finished before Mohit but behind Gaurav. Ashish finished before Sanchit but behind Mohit. Who won the race ?
(a)
(b)
(c)
(d)
Gaurav – Raj – Mohit – Ashish – Sanchit.
Hence Gaurav won the race.
Q-10) Seven men, A, B, C, D, E, F and G are standing in a queue in that order. Each one is wearing a cap of different colour like violet, indigo, blue green, yellow, orange and red. D is able to see in front of him green and blue, but not violet. E can see violet and yellow, but not red. G can see caps of all colours other than orange. If E is wearing an indigo coloured cap, then the colour of the cap worn by F is
(a)
(b)
(c)
(d)
The key point is in this question is "A person can see but caps of all persons standing in front of him can't see his own cap and caps of persons standing behind him.
From the given data he can summarise all the information in a table :
| Person | Cap |
| A/B/C | Green/blue/yellow |
| D | Violet |
| E | Indigo |
| F | Red |
| G | Orange |