Arithmetical Reasoning section 2 MCQ Detailed Explanation And More Example

MOST IMPORTANT verbal reasoning - 2 EXERCISES

Top 10,000+ Verbal Memory Based Exercises

The following question based on Arithmetical Reasoning topic of verbal reasoning

Questions : A fibres 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed

(a) 72 birds

(b) 30 birds

(c) 60 birds

(d) 90 birds

The correct answers to the above question in:

Answer: (b)

Let the total number of shots be x. then,

Shots fired by A = $5/8$ x ; Shots fired by B = $3/8$ x

Killing shots by A = $1/3$ of $5/8 x = {5x}/{24}$ ;

Shots missed by B = $1/2$ of $3/8 x = {3x}/{16}$ .

∴ ${3x}/{16}$ = 27 or x = $({27 × 16}/3)$ = 144

Birds killed by A = ${5x}/{24} = (5/{24} × 144)$ = 30

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Read more question and answers set 2 Based Verbal Reasoning Questions and Answers

Question : 1

In three coloured boxes - red, green and blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

a) 45

b) 18

c) 36

d) None of these

Answer: (d)

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2 × 2R = 4R or G = 3R. Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore number of balls in green box = G = 3R = (3 × 18) = 54.

Question : 2

If every 2 out of 3 ready made shirts need alterations in the sleeves, and every 4 out of 5 need it in the body, how many alterations will be required for 60 shirts?

a) 133

b) 88

c) 123

d) 143

Answer: (a)

Number of alterations required in 1 shirt

= $(2/3 + 3/4 + 4/5) = {133}/{60}$

∴ Number of alterations required in 60 shirts

= $({133}/{60} × 60)$ = 133

Question : 3

If the last four letters of the word 'CONCENTRATION' are written in reverse order followed by next two in the reverse order and next three in the reverse order and then followed by the first four in the reverse order, counting from the end which letter would be eighth in the new arrangement ?

a) E

b) N

c) T

d) R

Answer: (d)

The new letter sequence is NOITARTNECNOC

The eighth letter from the end is R.

Question : 4

The letters L, M, N, O, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N?

a) 4

b) 7

c) 5

d) 6

Answer: (d)

  6 4   9
LMNOPQRST

difference between P & T is 5 i.e., T = 5 + 4 = 9

difference between N & T is 3 i.e., N = 9 – 3 = 6

So, integer assigned to N = 6

Question : 5

There are 3 societies A, B, C having some tractors each. A gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. After some days C gives A and B as many tractors as they have. Finally each has 24 tractors. What is the original No. of tractors each had in the beginning?

a) A-21, B-12, C-29

b) A-29, B-21, C-12

c) A-39, B-21, C-12

d) A-21, B-12, C-39

Answer: (c)

According to the question, A gives B as many tractors that they already have

Number of tractors with A is greater than number of tractors with B and C. Only option (c) fulfill the statement.

Question : 6

First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is

a) 12

b) 9

c) 10

d) 15

Answer: (d)

Let the number of bananas in the second bunch be x

Then, number of bananas in the first bunch

= x + $1/4 x = 5/4 x$

So, $5/4$ x - x = 3 ⇔ 5x - 4x = 12 ⇔ x = 12

∴ Number of bananas in the first bunch

= $(5/4 × 12)$ = 15

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