Arithmetical Reasoning section 2 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) 4
(b) 7
(c) 5
(d) 6
The correct answers to the above question in:
Answer: (d)
6 | 4 | 9 | ||||||
L | M | N | O | P | Q | R | S | T |
difference between P & T is 5 i.e., T = 5 + 4 = 9
difference between N & T is 3 i.e., N = 9 – 3 = 6
So, integer assigned to N = 6
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Read more question and answers set 2 Based Verbal Reasoning Questions and Answers
Question : 1
A fibres 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed
a) 72 birds
b) 30 birds
c) 60 birds
d) 90 birds
Answer »Answer: (b)
Let the total number of shots be x. then,
Shots fired by A = $5/8$ x ; Shots fired by B = $3/8$ x
Killing shots by A = $1/3$ of $5/8 x = {5x}/{24}$ ;
Shots missed by B = $1/2$ of $3/8 x = {3x}/{16}$ .
∴ ${3x}/{16}$ = 27 or x = $({27 × 16}/3)$ = 144
Birds killed by A = ${5x}/{24} = (5/{24} × 144)$ = 30
Question : 2
In three coloured boxes - red, green and blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
a) 45
b) 18
c) 36
d) None of these
Answer »Answer: (d)
Let R, G and B represent the number of balls in red, green and blue boxes respectively.
Then, R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2 × 2R = 4R or G = 3R. Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 6R = 108 R = 18.
Therefore number of balls in green box = G = 3R = (3 × 18) = 54.
Question : 3
If every 2 out of 3 ready made shirts need alterations in the sleeves, and every 4 out of 5 need it in the body, how many alterations will be required for 60 shirts?
a) 133
b) 88
c) 123
d) 143
Answer »Answer: (a)
Number of alterations required in 1 shirt
= $(2/3 + 3/4 + 4/5) = {133}/{60}$
∴ Number of alterations required in 60 shirts
= $({133}/{60} × 60)$ = 133
Question : 4
There are 3 societies A, B, C having some tractors each. A gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. After some days C gives A and B as many tractors as they have. Finally each has 24 tractors. What is the original No. of tractors each had in the beginning?
a) A-21, B-12, C-29
b) A-29, B-21, C-12
c) A-39, B-21, C-12
d) A-21, B-12, C-39
Answer »Answer: (c)
According to the question, A gives B as many tractors that they already have
Number of tractors with A is greater than number of tractors with B and C. Only option (c) fulfill the statement.
Question : 5
First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is
a) 12
b) 9
c) 10
d) 15
Answer »Answer: (d)
Let the number of bananas in the second bunch be x
Then, number of bananas in the first bunch
= x + $1/4 x = 5/4 x$
So, $5/4$ x - x = 3 ⇔ 5x - 4x = 12 ⇔ x = 12
∴ Number of bananas in the first bunch
= $(5/4 × 12)$ = 15
Question : 6
Three ducks can be arranged as shown above to satisfy all the three given conditions. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
a) 14
b) 10
c) 12
d) 16
Answer »Answer: (a)
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5x = 70 or x = 14.
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