Arithmetical Reasoning section 2 MCQ Detailed Explanation And More Example

MOST IMPORTANT verbal reasoning - 2 EXERCISES

Top 10,000+ Verbal Memory Based Exercises

The following question based on Arithmetical Reasoning topic of verbal reasoning

Questions : First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is

(a) 12

(b) 9

(c) 10

(d) 15

The correct answers to the above question in:

Answer: (d)

Let the number of bananas in the second bunch be x

Then, number of bananas in the first bunch

= x + $1/4 x = 5/4 x$

So, $5/4$ x - x = 3 ⇔ 5x - 4x = 12 ⇔ x = 12

∴ Number of bananas in the first bunch

= $(5/4 × 12)$ = 15

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Read more question and answers set 2 Based Verbal Reasoning Questions and Answers

Question : 1

There are 3 societies A, B, C having some tractors each. A gives B and C as many tractors as they already have. After some days B gives A and C as many tractors as they have. After some days C gives A and B as many tractors as they have. Finally each has 24 tractors. What is the original No. of tractors each had in the beginning?

a) A-21, B-12, C-29

b) A-29, B-21, C-12

c) A-39, B-21, C-12

d) A-21, B-12, C-39

Answer: (c)

According to the question, A gives B as many tractors that they already have

Number of tractors with A is greater than number of tractors with B and C. Only option (c) fulfill the statement.

Question : 2

The letters L, M, N, O, P, Q, R, S and T in their order are substituted by nine integers 1 to 9 but not in that order. 4 is assigned to P. The difference between P and T is 5. The difference between N and T is 3. What is the integer assigned to N?

a) 4

b) 7

c) 5

d) 6

Answer: (d)

  6 4   9
LMNOPQRST

difference between P & T is 5 i.e., T = 5 + 4 = 9

difference between N & T is 3 i.e., N = 9 – 3 = 6

So, integer assigned to N = 6

Question : 3

A fibres 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed

a) 72 birds

b) 30 birds

c) 60 birds

d) 90 birds

Answer: (b)

Let the total number of shots be x. then,

Shots fired by A = $5/8$ x ; Shots fired by B = $3/8$ x

Killing shots by A = $1/3$ of $5/8 x = {5x}/{24}$ ;

Shots missed by B = $1/2$ of $3/8 x = {3x}/{16}$ .

∴ ${3x}/{16}$ = 27 or x = $({27 × 16}/3)$ = 144

Birds killed by A = ${5x}/{24} = (5/{24} × 144)$ = 30

Question : 4

Three ducks can be arranged as shown above to satisfy all the three given conditions. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?

a) 14

b) 10

c) 12

d) 16

Answer: (a)

Let number of horses = number of men = x.

Then, number of legs = 4x + 2 x (x/2) = 5x.

So, 5x = 70 or x = 14.

Question : 5

I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?

a) 54

b) 25

c) 37

d) 65

Answer: (b)

The required number will be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5. Such a number is 25 among options

Question : 6

David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time. Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross?

a) 30

b) 19

c) 28

d) 37

Answer: (a)

Suppose their paths cross after x minutes.

Then, 11 + 57x = 51 – 63 x ⇔ 120 x = 10 ⇔ x = $1/3$

Number of floors covered by David in $1/3$ min

= $(1/3 × 57)$ = 19.

So, their paths cross at (11 + 19)th i.e., 30th floor.

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