Arithmetical Reasoning section 2 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) 30
(b) 19
(c) 28
(d) 37
The correct answers to the above question in:
Answer: (a)
Suppose their paths cross after x minutes.
Then, 11 + 57x = 51 – 63 x ⇔ 120 x = 10 ⇔ x = $1/3$
Number of floors covered by David in $1/3$ min
= $(1/3 × 57)$ = 19.
So, their paths cross at (11 + 19)th i.e., 30th floor.
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Read more question and answers set 2 Based Verbal Reasoning Questions and Answers
Question : 1
I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute ?
a) 54
b) 25
c) 37
d) 65
Answer »Answer: (b)
The required number will be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5. Such a number is 25 among options
Question : 2
Three ducks can be arranged as shown above to satisfy all the three given conditions. A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
a) 14
b) 10
c) 12
d) 16
Answer »Answer: (a)
Let number of horses = number of men = x.
Then, number of legs = 4x + 2 x (x/2) = 5x.
So, 5x = 70 or x = 14.
Question : 3
First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch is
a) 12
b) 9
c) 10
d) 15
Answer »Answer: (d)
Let the number of bananas in the second bunch be x
Then, number of bananas in the first bunch
= x + $1/4 x = 5/4 x$
So, $5/4$ x - x = 3 ⇔ 5x - 4x = 12 ⇔ x = 12
∴ Number of bananas in the first bunch
= $(5/4 × 12)$ = 15
Question : 4
Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many least number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side ?
a) 7
b) 3
c) 5
d) This cannot be achieved
Answer »Answer: (b)
Question : 5
In a cricket team, three batsman Ricky, Sachin and Brian are the top three run-scorers in any order. Each of them gives two replies to any question, one of which is true and the other is false, again, in any order. When asked about who the top scorer was, following were the replies they gave :
Sachin : I got the top score. Ricky was second.
Brain : I got the top score. Sachin was second
Ricky : I got the top score. Sachin was third.
Which of the following is the correct order of batsmen who got the top score, second best and third best score respectively?
a) Ricky, Sachin, Brain
b) Brain, Ricky, Sachin
c) Brain, Sachin, Ricky
d) Sachin, Brain, Ricky
Answer »Answer: (b)
Only one of 1st replies given by all three can be true as top score can be taken by only one. Similarly, only two of 2nd replies given by all three can be true as maximum true replies are three. Now, consider the each of replies. Suppose Sachin's 1st reply is true and Brain's and Ricky's 2nd reply is true. Then Brain's and Ricky's 1st reply will be false. Then,
Sachin | Brain | Ricky | |
I | Sachin: | ||
II | Brain | Sachin | |
III | Ricky | Sachin |
Hence, it is not possible.
Now, suppose Brain's 1st reply is true and Sachin's and Ricky's 2nd reply is true. Then
Brain | Sachin | Ricky | |
I | Brain | ||
II | Ricky | Ricky | |
III | Sachin | Sachin |
Hence, it is clear that option (b) is correct.
Question : 6
A box contains five sets of balls while there are 3 balls in each set. Each set of balls has one color which is different from every other set, what is the least number of balls that must be removed from the box in order to claim with certainty that a pair of balls of the same colour has been removed?
a) 8
b) 6
c) 7
d) 9
Answer »Answer: (b)
Set | 1 | 2 | 3 | 4 | 5 |
Balls | 1 | 1 | 1 | 1 | 1 |
Now, any further removal of balls from any set will ensure that removed ball is of the same colour as one of the already removed balls, thus constituting a pair of the removed balls of the same colour.
Set | 1 | 2 | 3 | 4 | 5 |
Balls | 1 + 1 | 1 | 1 | 1 | 1 |
Hence, minimum no. of removed balls = 6
GET Arithmetical Reasoning PRACTICE TEST EXERCISES
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