Arithmetical Reasoning section 2 MCQ Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 2 EXERCISES
The following question based on Arithmetical Reasoning topic of verbal reasoning
(a) 68 paise
(b) 35 paise
(c) 89 paise
(d) 40 paise
The correct answers to the above question in:
Answer: (d)
4x + 10 y = 1.69 ...(i)
3x + 7y = 1.26 ...(ii)
12x + 30y = 5.07
12x + 28y = 5.04
2y = 0.03
∴ y = ${0.03}/2$ .015
Putting the value of y in eqn. (i)
4x + 10 × 0.015 = 1.69
4x = 1.69 – 0.15 = 1.54
∴ x = ${1.54}/4$ = 0.385
1 × 0.385 + 0.015
= 0.385 + 0.015 = 0.400
= 40 paise
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Read more question and answers set 2 Based Verbal Reasoning Questions and Answers
Question : 1
The total number of digits used in numbering the pages of a book having 366 pages is
a) 1098
b) 732
c) 990
d) 1305
Answer »Answer: (c)
Total number of digits
= (No. of digits in 1- digit page nos. + No. of digits in 2-digit page nos. + No. of digits in 3- digit page nos.)
= (1 × 9 + 2 × 90 + 3 × 267) = (9 + 180 + 801) = 990.
Question : 2
In a family, each daughter has the same number of brothers as she has sisters and each son has twice as many sisters as he has brothers. How many sons are there in the family ?
a) 4
b) 2
c) 3
d) 5
Answer »Answer: (c)
Let d and s represent the number of daughters and sons respectively.
Then, we have :
d – 1 = s and 2 (s – 1) = d.
Solving these two equations, we get: d = 4, s = 3.
Question : 3
A box contains five sets of balls while there are 3 balls in each set. Each set of balls has one color which is different from every other set, what is the least number of balls that must be removed from the box in order to claim with certainty that a pair of balls of the same colour has been removed?
a) 8
b) 6
c) 7
d) 9
Answer »Answer: (b)
| Set | 1 | 2 | 3 | 4 | 5 |
| Balls | 1 | 1 | 1 | 1 | 1 |
Now, any further removal of balls from any set will ensure that removed ball is of the same colour as one of the already removed balls, thus constituting a pair of the removed balls of the same colour.
| Set | 1 | 2 | 3 | 4 | 5 |
| Balls | 1 + 1 | 1 | 1 | 1 | 1 |
Hence, minimum no. of removed balls = 6
GET Arithmetical Reasoning PRACTICE TEST EXERCISES
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