time and work Model Questions & Answers, Practice Test for ssc chsl tier 1 2023
ssc chsl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
Powers Surds & Indices
Ratio Proportion & Partnership
Percentages
Profit & Loss
Time & Work
Time & Distance
Simple Interest & Compound Interest
Mensuration: Area & Volumes
A boy rows a boat against a stream flowing at 2 kmph for a distance of 9 km, and then turns round and rows back with the current. If the whole trip occupies 6 hours, find the boy's rowing speed in still water.
Answer: (a)
Let the speed of rowing be x. Then the equation formed
is $9/{x - 2} + 9/{x + 2}$ = 6.
${9(x + 2 + x - 2)}/{x^2 - 4}$ = 6
⇒18x = 6($x^2$ – 4)
⇒$x^2$ – 3x – 4 = 0
⇒(x – 4) (x + 1) = 0
x = 4, –1
Speed of rowing 4 km/h
150 metres long train crosses a bridge of length 250 metres in 30 seconds. Find the time for train to cross a platform of 130 metres.
Answer: (a)
Speed of train = ${150 + 250}/{30} = {400}/{30} = {40}/3$ m/s
∴ Required time = ${150 + 130}/{40/3} = {280 × 3}/{40}$ = 21 sec
'A' can complete a piece of work in 12 days. 'A' and 'B' together can complete the same piece of work in 8 days. In how many days can 'B' alone complete the same piece of work?
Answer: (b)
Number of days = ${12×8}/{12-8}$
= 24 days
A garrison had provision for a certain number of days. After 10 days, $1/5$ of the men desert and it is found that the provisions will now last just as long as before. How long was that ?
Answer: (d)
Initially, let there be x men having food for y days.
After 10 days, x men had food for (y – 10) days. Also,
$(x - x/5)$ men had food for y days.
∴ x(y –10) = ${4x}/5$ × y⇒5xy– 50x = 4xy⇒xy– 50x = 0
⇒ x(y – 50) = 0⇒y – 50 = 0⇒y = 50.
Two persons living in different towns 32 km apart started at 1 pm to see each other at the rate of 3.5 km/h and 4.5 km/h respectively. When will they meet and how many km will each then walk ?
Answer: (d)
Relative speed = (3.5 + 4.5) = 8 kmph.
Time to meet = 32/8 = 4 hours.
So when they meet at 5 pm, one will have walked
3.5 × 4 = 14 km and the other will have walked
4.5 × 4 = 18 km.
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