percentages Model Questions & Answers, Practice Test for ssc chsl tier 1 2023
ssc chsl tier 1 2023 SYLLABUS WISE SUBJECTS MCQs
Number System
Simplification
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Ratio Proportion & Partnership
Percentages
Profit & Loss
Time & Work
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Simple Interest & Compound Interest
Mensuration: Area & Volumes
The difference between 58% of a number and 39% of the same number is 247. What is 62% of that number ?
Answer: (a)
According to the question,
(58 – 39)% of x = 247
or, number = ${247 × 100}/19 = 1300$
62% of 1300 = $1300 × 62/100 = 806$
Mr. Davar spends 38% of his monthly income on food, 25% on children's education and 12% on transport and the remaining amount of Rs.5,800 he saves. What is Mr. Davar's monthly income ?
Answer: (b)
Percentage savings of Mr. Davar
= 100 – (38 + 25 + 12) = 25%
Let his monthly income be x
25% of x = 5800
$x = 5800 × 100/25$ = 23, 200
If the numerator of a fraction is increased by 200% and the denominator is increased by 160%, the resultant fraction is $7/13$. What is the original fraction?
Answer: (c)
Let the original fraction = $x/y$
According to the question,
${{300x}/100}/{{260y}/100} = 7/13$
or ${30x}/{26y} = 7/13$
$x/y = 7/13 × 26/30 = 7/15$
Bovina spent Rs. 44,668 on her air tickets, Rs. 56,732 on buying gifts for the family members and the remaining 22% of the total amount she had as cash with her. What was the total amount?
Answer: (a)
Total expenditure = 44668 + 56732 = 101400
Total percentage expenditure = 100 – 22 = 78 %
Total amount = ${101400 × 100}/78$ = Rs. 130000
A = 10% of x, B = 10% of y, C = 10% of x + 10% of y. On the basis of the above equalities, what is true in the following?
Answer: (d)
The given information gives no indication regarding the comparison of x and y.
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