basic numeracy Model Questions & Answers, Practice Test for ssc cgl tier 1

Answer: (b)

Suppose the number of sweets is = x

∴ $x/{450 - 150} - x/450$ = 3

$x/300 - x/450 = 3$ or ${3x - 2x}/900 = 3$

x = 2700

Number of sweets to each children = $2700/300 = 9$

Answer: (b)

$1.236× 10^15 – 5.23 × 10^14$

= $10^14(12.36 – 5.23) = 7.13 × 10^14$

Answer: (b)

1. Of two consecutive integer is always odd and other is even.

So this is true statement.

2. Each odd no is in the form of (2n – 1) $(2n + 1)^2 = 4x^2 + 1 + 4n$

Answer: (c)

2 + P + R + Q = 11

P + R + Q = 9

For maximum value of Q

P and R be 0 then

Q = 9

Answer: (a)

Let x and y be the number of apples and oranges bought by the person.

5x + 7y = 500

⇒ y = ${500 - 5x}/7 = {5(100 - x)}/7$

for x and y to be integers

For x = (2, 9, 16, 23, 30, 37, 46, 51, 58, 65, 72, 79, 86, 93) y gives integer value

Hence, required number = 14