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ibps so prelims 2023 SYLLABUS WISE SUBJECTS MCQs
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Directions:
Study the following information carefully and answer the below questions.
There are eight persons viz. A, B, C, D, P, Q, R, and S lives in eight floored building numbered 1 to 8 in such a way that the lowermost floor is marked as 1, the floor above it is marked as 2 and so on and the top floor is marked as 8. Each of them has different weight viz. 30, 40, 45, 65, 95, 80, 85 and 90 kg but not necessarily in the same order. Only one person lives on each floor. The person whose weight is 65kg lives on an odd numbered floor at a gap of two floors from D, who doesn't live on the top most floor. S lives on the adjacent floor of the one whose weight is 85kg.
Twice the weight of the person who lives on the floor number 4 is equal to thrice the weight of the person who lives on the floor number 2. Q lives at a gap of one floor from the one whose weight is 85 Kg. Number of floors above C is same as the number of floors below the one whose weight is 40kg. The weight of A is twice the weight of S. A, who neither lives on the lowermost floor nor adjacent to the one whose weight is 65kg, lives at a gap of three floors from S, who neither lives on the top nor his weight is 65kg. P, whose weight is 30kg lives just above the floor of R. Weight of Q is more than that of the one who lives at a gap of one floor above C.
What is the sum of the weight of the one who lives on the floor numbered 7 and the one who lives on the floor numbered 3?
Answer: (a)
Name | Floor | Weight |
A | 8 | 90 |
Q | 7 | 95 |
D | 6 | 40 |
B | 5 | 85 |
S | 4 | 45 |
C | 3 | 65 |
P | 2 | 30 |
R | 1 | 80 |
Explanation:
We have:
• Twice the weight of the person who lives on floor number 4 is equal to thrice the weight of the person who lives on floor number 2.
Let the weight of the person who lives on floor number 4 is X.
Let the weight of the person who lives on floor number 2 is Y.
Thus, 2X = 3Y
X/Y = 3:2
That means, one who lives on floor numbered 2 is 30 kg and one who lives on floor numbered 4 is 45kg.
• The person whose weight is 65kg lives on any odd numbered floor at a gap of two floors from D, that means D lives on even numbered floor and D doesn't live on top floor, that means we have four possibilities, in case (1)the one whose weight is 65kg lives on ground floor, in case (2) the one whose weight is 65kg lives on floor numbered 3 and in case (3) the one whose weight is 65kg lives on floor numbered 5and in case (4) the one whose weight is 65kg lives on floor numbered 7.
• P, whose weight is 30kg lives just above floor of R, that means case (3) is not valid as in case (3) weight of D is 30 kg which is not correct and in case (1) ,case (2)and case (4) R lives on ground floor.
• Based on above given information we get:
Case (1) | Case (2) | Case (3) | Case (4) | ||||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
8 | 8 | 8 | 8 | ||||||||
7 | 7 | 7 | 7 | 65 | |||||||
6 | D | 6 | 6 | 6 | |||||||
5 | 5 | 5 | 65 | 5 | |||||||
D | 4 | 45 | 4 | 45 | 4 | 45 | D | 4 | 45 | ||
3 | 3 | 65 | 3 | 3 | |||||||
P | 2 | 30 | P | 2 | 30 | D | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 | R | 1 |
Again, we have:
• A, who neither lives on the lowermost floor noran immediate neighbour of the one whose weight is 65kg, lives at a gap of three floor from S, who neither lives on the top nor his weight is 65kg. by this condition, case 4 got eliminated. Now case 1 has one more possibility. That means in case 1, S lives on floor numbered 7 in case 1a, S lives on floor numbered 3 and in case 2 , S lives on floor numbered 4.
• S lives on the adjacent floor of the one whose weight is 85kg and the weight of D is not 85kg, now case1 have one more possibility that means, in case 1, the one whose weight is 85 kg lives on top floor in case (1b) A lives on the floor numbered 3 and the one whose weight is 85 kg lives immediately above S, in case (2) A lives on the top floor and the one whose weight is 85kglives on floor numbered 5 .case 1a is not valid.
• Q lives at a gap of one floor from the one whose weight is 85 Kg, which means now case 2 have one more possibility, in case (1) Q lives immediate below S, in case (1b) Q lives on the top floor ,in case 2 ,Q lives on the floor numbered 7 and in case (2a) , Q lives on floor numbered 3.
Based on above given information we get 4 possibilities:
Case (1) | ||
Name | Floor | Weight |
8 | 85 | |
S | 7 | |
Q | 6 | |
5 | ||
D | 4 | 455 |
A | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1 a) | ||
Name | Floor | Weight |
8 | ||
A | 7 | |
6 | ||
5 | ||
D | 4 | 45 |
S | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1b) | Case (2) | Case (2a) | ||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
Q | 8 | A | 8 | A | 8 | |||
S | 7 | Q | 7 | 7 | ||||
6 | 85 | D | 6 | D | 6 | |||
5 | 5 | 85 | 5 | 85 | ||||
D | 4 | 45 | S | 4 | 45 | S | 4 | 45 |
A | 3 | 3 | 65 | Q | 3 | 65 | ||
P | 2 | 30 | P | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 |
Again, we have:
• Number of floors above C is same as the number of floors below the one whose weight is 40 kg, which means case (1),case 2aare not valid, in case (1b) C lives on floor numbered 6 and in case (2) C lives on floor numbered 3.
• Weight of A is twice the weight of S, that means case (1b) is not valid as weight of A doesn't follow given condition and in case (2) weight of A must be 90kg.
• Weight of Q is more than that of the one who
Who lives immediately above the floor of S?
Answer: (b)
Name | Floor | Weight |
A | 8 | 90 |
Q | 7 | 95 |
D | 6 | 40 |
B | 5 | 85 |
S | 4 | 45 |
C | 3 | 65 |
P | 2 | 30 |
R | 1 | 80 |
Explanation:
We have:
• Twice the weight of the person who lives on floor number 4 is equal to thrice the weight of the person who lives on floor number 2.
Let the weight of the person who lives on floor number 4 is X.
Let the weight of the person who lives on floor number 2 is Y.
Thus, 2X = 3Y
X/Y = 3:2
That means, one who lives on floor numbered 2 is 30 kg and one who lives on floor numbered 4 is 45kg.
• The person whose weight is 65kg lives on any odd numbered floor at a gap of two floors from D, that means D lives on even numbered floor and D doesn't live on top floor, that means we have four possibilities, in case (1)the one whose weight is 65kg lives on ground floor, in case (2) the one whose weight is 65kg lives on floor numbered 3 and in case (3) the one whose weight is 65kg lives on floor numbered 5and in case (4) the one whose weight is 65kg lives on floor numbered 7.
• P, whose weight is 30kg lives just above floor of R, that means case (3) is not valid as in case (3) weight of D is 30 kg which is not correct and in case (1) ,case (2)and case (4) R lives on ground floor.
• Based on above given information we get:
Case (1) | Case (2) | Case (3) | Case (4) | ||||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
8 | 8 | 8 | 8 | ||||||||
7 | 7 | 7 | 7 | 65 | |||||||
6 | D | 6 | 6 | 6 | |||||||
5 | 5 | 5 | 65 | 5 | |||||||
D | 4 | 45 | 4 | 45 | 4 | 45 | D | 4 | 45 | ||
3 | 3 | 65 | 3 | 3 | |||||||
P | 2 | 30 | P | 2 | 30 | D | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 | R | 1 |
Again, we have:
• A, who neither lives on the lowermost floor noran immediate neighbour of the one whose weight is 65kg, lives at a gap of three floor from S, who neither lives on the top nor his weight is 65kg. by this condition, case 4 got eliminated. Now case 1 has one more possibility. That means in case 1, S lives on floor numbered 7 in case 1a, S lives on floor numbered 3 and in case 2 , S lives on floor numbered 4.
• S lives on the adjacent floor of the one whose weight is 85kg and the weight of D is not 85kg, now case1 have one more possibility that means, in case 1, the one whose weight is 85 kg lives on top floor in case (1b) A lives on the floor numbered 3 and the one whose weight is 85 kg lives immediately above S, in case (2) A lives on the top floor and the one whose weight is 85kglives on floor numbered 5 .case 1a is not valid.
• Q lives at a gap of one floor from the one whose weight is 85 Kg, which means now case 2 have one more possibility, in case (1) Q lives immediate below S, in case (1b) Q lives on the top floor ,in case 2 ,Q lives on the floor numbered 7 and in case (2a) , Q lives on floor numbered 3.
Based on above given information we get 4 possibilities:
Case (1) | ||
Name | Floor | Weight |
8 | 85 | |
S | 7 | |
Q | 6 | |
5 | ||
D | 4 | 455 |
A | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1 a) | ||
Name | Floor | Weight |
8 | ||
A | 7 | |
6 | ||
5 | ||
D | 4 | 45 |
S | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1b) | Case (2) | Case (2a) | ||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
Q | 8 | A | 8 | A | 8 | |||
S | 7 | Q | 7 | 7 | ||||
6 | 85 | D | 6 | D | 6 | |||
5 | 5 | 85 | 5 | 85 | ||||
D | 4 | 45 | S | 4 | 45 | S | 4 | 45 |
A | 3 | 3 | 65 | Q | 3 | 65 | ||
P | 2 | 30 | P | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 |
Again, we have:
• Number of floors above C is same as the number of floors below the one whose weight is 40 kg, which means case (1),case 2aare not valid, in case (1b) C lives on floor numbered 6 and in case (2) C lives on floor numbered 3.
• Weight of A is twice the weight of S, that means case (1b) is not valid as weight of A doesn't follow given condition and in case (2) weight of A must be 90kg.
• Weight of Q is more than that of the one who
How many persons live between A and the one whose weight is 40 kg?
Answer: (d)
Name | Floor | Weight |
A | 8 | 90 |
Q | 7 | 95 |
D | 6 | 40 |
B | 5 | 85 |
S | 4 | 45 |
C | 3 | 65 |
P | 2 | 30 |
R | 1 | 80 |
Explanation:
We have:
• Twice the weight of the person who lives on floor number 4 is equal to thrice the weight of the person who lives on floor number 2.
Let the weight of the person who lives on floor number 4 is X.
Let the weight of the person who lives on floor number 2 is Y.
Thus, 2X = 3Y
X/Y = 3:2
That means, one who lives on floor numbered 2 is 30 kg and one who lives on floor numbered 4 is 45kg.
• The person whose weight is 65kg lives on any odd numbered floor at a gap of two floors from D, that means D lives on even numbered floor and D doesn't live on top floor, that means we have four possibilities, in case (1)the one whose weight is 65kg lives on ground floor, in case (2) the one whose weight is 65kg lives on floor numbered 3 and in case (3) the one whose weight is 65kg lives on floor numbered 5and in case (4) the one whose weight is 65kg lives on floor numbered 7.
• P, whose weight is 30kg lives just above floor of R, that means case (3) is not valid as in case (3) weight of D is 30 kg which is not correct and in case (1) ,case (2)and case (4) R lives on ground floor.
• Based on above given information we get:
Case (1) | Case (2) | Case (3) | Case (4) | ||||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
8 | 8 | 8 | 8 | ||||||||
7 | 7 | 7 | 7 | 65 | |||||||
6 | D | 6 | 6 | 6 | |||||||
5 | 5 | 5 | 65 | 5 | |||||||
D | 4 | 45 | 4 | 45 | 4 | 45 | D | 4 | 45 | ||
3 | 3 | 65 | 3 | 3 | |||||||
P | 2 | 30 | P | 2 | 30 | D | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 | R | 1 |
Again, we have:
• A, who neither lives on the lowermost floor noran immediate neighbour of the one whose weight is 65kg, lives at a gap of three floor from S, who neither lives on the top nor his weight is 65kg. by this condition, case 4 got eliminated. Now case 1 has one more possibility. That means in case 1, S lives on floor numbered 7 in case 1a, S lives on floor numbered 3 and in case 2 , S lives on floor numbered 4.
• S lives on the adjacent floor of the one whose weight is 85kg and the weight of D is not 85kg, now case1 have one more possibility that means, in case 1, the one whose weight is 85 kg lives on top floor in case (1b) A lives on the floor numbered 3 and the one whose weight is 85 kg lives immediately above S, in case (2) A lives on the top floor and the one whose weight is 85kglives on floor numbered 5 .case 1a is not valid.
• Q lives at a gap of one floor from the one whose weight is 85 Kg, which means now case 2 have one more possibility, in case (1) Q lives immediate below S, in case (1b) Q lives on the top floor ,in case 2 ,Q lives on the floor numbered 7 and in case (2a) , Q lives on floor numbered 3.
Based on above given information we get 4 possibilities:
Case (1) | ||
Name | Floor | Weight |
8 | 85 | |
S | 7 | |
Q | 6 | |
5 | ||
D | 4 | 455 |
A | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1 a) | ||
Name | Floor | Weight |
8 | ||
A | 7 | |
6 | ||
5 | ||
D | 4 | 45 |
S | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1b) | Case (2) | Case (2a) | ||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
Q | 8 | A | 8 | A | 8 | |||
S | 7 | Q | 7 | 7 | ||||
6 | 85 | D | 6 | D | 6 | |||
5 | 5 | 85 | 5 | 85 | ||||
D | 4 | 45 | S | 4 | 45 | S | 4 | 45 |
A | 3 | 3 | 65 | Q | 3 | 65 | ||
P | 2 | 30 | P | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 |
Again, we have:
• Number of floors above C is same as the number of floors below the one whose weight is 40 kg, which means case (1),case 2aare not valid, in case (1b) C lives on floor numbered 6 and in case (2) C lives on floor numbered 3.
• Weight of A is twice the weight of S, that means case (1b) is not valid as weight of A doesn't follow given condition and in case (2) weight of A must be 90kg.
• Weight of Q is more than that of the one who
Which of the following statement is not true?
Answer: (b)
Name | Floor | Weight |
A | 8 | 90 |
Q | 7 | 95 |
D | 6 | 40 |
B | 5 | 85 |
S | 4 | 45 |
C | 3 | 65 |
P | 2 | 30 |
R | 1 | 80 |
Explanation:
We have:
• Twice the weight of the person who lives on floor number 4 is equal to thrice the weight of the person who lives on floor number 2.
Let the weight of the person who lives on floor number 4 is X.
Let the weight of the person who lives on floor number 2 is Y.
Thus, 2X = 3Y
X/Y = 3:2
That means, one who lives on floor numbered 2 is 30 kg and one who lives on floor numbered 4 is 45kg.
• The person whose weight is 65kg lives on any odd numbered floor at a gap of two floors from D, that means D lives on even numbered floor and D doesn't live on top floor, that means we have four possibilities, in case (1)the one whose weight is 65kg lives on ground floor, in case (2) the one whose weight is 65kg lives on floor numbered 3 and in case (3) the one whose weight is 65kg lives on floor numbered 5and in case (4) the one whose weight is 65kg lives on floor numbered 7.
• P, whose weight is 30kg lives just above floor of R, that means case (3) is not valid as in case (3) weight of D is 30 kg which is not correct and in case (1) ,case (2)and case (4) R lives on ground floor.
• Based on above given information we get:
Case (1) | Case (2) | Case (3) | Case (4) | ||||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
8 | 8 | 8 | 8 | ||||||||
7 | 7 | 7 | 7 | 65 | |||||||
6 | D | 6 | 6 | 6 | |||||||
5 | 5 | 5 | 65 | 5 | |||||||
D | 4 | 45 | 4 | 45 | 4 | 45 | D | 4 | 45 | ||
3 | 3 | 65 | 3 | 3 | |||||||
P | 2 | 30 | P | 2 | 30 | D | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 | R | 1 |
Again, we have:
• A, who neither lives on the lowermost floor noran immediate neighbour of the one whose weight is 65kg, lives at a gap of three floor from S, who neither lives on the top nor his weight is 65kg. by this condition, case 4 got eliminated. Now case 1 has one more possibility. That means in case 1, S lives on floor numbered 7 in case 1a, S lives on floor numbered 3 and in case 2 , S lives on floor numbered 4.
• S lives on the adjacent floor of the one whose weight is 85kg and the weight of D is not 85kg, now case1 have one more possibility that means, in case 1, the one whose weight is 85 kg lives on top floor in case (1b) A lives on the floor numbered 3 and the one whose weight is 85 kg lives immediately above S, in case (2) A lives on the top floor and the one whose weight is 85kglives on floor numbered 5 .case 1a is not valid.
• Q lives at a gap of one floor from the one whose weight is 85 Kg, which means now case 2 have one more possibility, in case (1) Q lives immediate below S, in case (1b) Q lives on the top floor ,in case 2 ,Q lives on the floor numbered 7 and in case (2a) , Q lives on floor numbered 3.
Based on above given information we get 4 possibilities:
Case (1) | ||
Name | Floor | Weight |
8 | 85 | |
S | 7 | |
Q | 6 | |
5 | ||
D | 4 | 455 |
A | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1 a) | ||
Name | Floor | Weight |
8 | ||
A | 7 | |
6 | ||
5 | ||
D | 4 | 45 |
S | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1b) | Case (2) | Case (2a) | ||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
Q | 8 | A | 8 | A | 8 | |||
S | 7 | Q | 7 | 7 | ||||
6 | 85 | D | 6 | D | 6 | |||
5 | 5 | 85 | 5 | 85 | ||||
D | 4 | 45 | S | 4 | 45 | S | 4 | 45 |
A | 3 | 3 | 65 | Q | 3 | 65 | ||
P | 2 | 30 | P | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 |
Again, we have:
• Number of floors above C is same as the number of floors below the one whose weight is 40 kg, which means case (1),case 2aare not valid, in case (1b) C lives on floor numbered 6 and in case (2) C lives on floor numbered 3.
• Weight of A is twice the weight of S, that means case (1b) is not valid as weight of A doesn't follow given condition and in case (2) weight of A must be 90kg.
• Weight of Q is more than that of the one who
Which of the following combination of name, floor and weight is true?
Answer: (e)
Name | Floor | Weight |
A | 8 | 90 |
Q | 7 | 95 |
D | 6 | 40 |
B | 5 | 85 |
S | 4 | 45 |
C | 3 | 65 |
P | 2 | 30 |
R | 1 | 80 |
Explanation:
We have:
• Twice the weight of the person who lives on floor number 4 is equal to thrice the weight of the person who lives on floor number 2.
Let the weight of the person who lives on floor number 4 is X.
Let the weight of the person who lives on floor number 2 is Y.
Thus, 2X = 3Y
X/Y = 3:2
That means, one who lives on floor numbered 2 is 30 kg and one who lives on floor numbered 4 is 45kg.
• The person whose weight is 65kg lives on any odd numbered floor at a gap of two floors from D, that means D lives on even numbered floor and D doesn't live on top floor, that means we have four possibilities, in case (1)the one whose weight is 65kg lives on ground floor, in case (2) the one whose weight is 65kg lives on floor numbered 3 and in case (3) the one whose weight is 65kg lives on floor numbered 5and in case (4) the one whose weight is 65kg lives on floor numbered 7.
• P, whose weight is 30kg lives just above floor of R, that means case (3) is not valid as in case (3) weight of D is 30 kg which is not correct and in case (1) ,case (2)and case (4) R lives on ground floor.
• Based on above given information we get:
Case (1) | Case (2) | Case (3) | Case (4) | ||||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
8 | 8 | 8 | 8 | ||||||||
7 | 7 | 7 | 7 | 65 | |||||||
6 | D | 6 | 6 | 6 | |||||||
5 | 5 | 5 | 65 | 5 | |||||||
D | 4 | 45 | 4 | 45 | 4 | 45 | D | 4 | 45 | ||
3 | 3 | 65 | 3 | 3 | |||||||
P | 2 | 30 | P | 2 | 30 | D | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 | R | 1 |
Again, we have:
• A, who neither lives on the lowermost floor noran immediate neighbour of the one whose weight is 65kg, lives at a gap of three floor from S, who neither lives on the top nor his weight is 65kg. by this condition, case 4 got eliminated. Now case 1 has one more possibility. That means in case 1, S lives on floor numbered 7 in case 1a, S lives on floor numbered 3 and in case 2 , S lives on floor numbered 4.
• S lives on the adjacent floor of the one whose weight is 85kg and the weight of D is not 85kg, now case1 have one more possibility that means, in case 1, the one whose weight is 85 kg lives on top floor in case (1b) A lives on the floor numbered 3 and the one whose weight is 85 kg lives immediately above S, in case (2) A lives on the top floor and the one whose weight is 85kglives on floor numbered 5 .case 1a is not valid.
• Q lives at a gap of one floor from the one whose weight is 85 Kg, which means now case 2 have one more possibility, in case (1) Q lives immediate below S, in case (1b) Q lives on the top floor ,in case 2 ,Q lives on the floor numbered 7 and in case (2a) , Q lives on floor numbered 3.
Based on above given information we get 4 possibilities:
Case (1) | ||
Name | Floor | Weight |
8 | 85 | |
S | 7 | |
Q | 6 | |
5 | ||
D | 4 | 455 |
A | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1 a) | ||
Name | Floor | Weight |
8 | ||
A | 7 | |
6 | ||
5 | ||
D | 4 | 45 |
S | 3 | |
P | 2 | 30 |
R | 1 | 65 |
Case (1b) | Case (2) | Case (2a) | ||||||
Name | Floor | Weight | Name | Floor | Weight | Name | Floor | Weight |
Q | 8 | A | 8 | A | 8 | |||
S | 7 | Q | 7 | 7 | ||||
6 | 85 | D | 6 | D | 6 | |||
5 | 5 | 85 | 5 | 85 | ||||
D | 4 | 45 | S | 4 | 45 | S | 4 | 45 |
A | 3 | 3 | 65 | Q | 3 | 65 | ||
P | 2 | 30 | P | 2 | 30 | P | 2 | 30 |
R | 1 | 65 | R | 1 | R | 1 |
Again, we have:
• Number of floors above C is same as the number of floors below the one whose weight is 40 kg, which means case (1),case 2aare not valid, in case (1b) C lives on floor numbered 6 and in case (2) C lives on floor numbered 3.
• Weight of A is twice the weight of S, that means case (1b) is not valid as weight of A doesn't follow given condition and in case (2) weight of A must be 90kg.
• Weight of Q is more than that of the one who
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