quadratic equations mcq pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024
ibps rrb so officer sclae 2 3 single exam 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Lcm & Hcf
Ratio & Proportion
Percentage
Time & Work
Mensuration
Advance Math
Trigonometric Ratios & Identities
Average
Profit & Loss
Alligation & Mixtures
Compound Interest
Linear Equations
Quadratic Equations
For what value of c the quadratic equation $x^2$ – (c + 6) x + 2(2c – 1) = 0 has sum of the roots as half of their product?
Answer: (a)
(c + 6) = 1/2 × 2(2c – 1) ⇒ c + 6 = 2c – 1 ⇒c = 7
Which is not true?
Answer: (d)
(a) is clearly true.
(b) $x^2$ + 1 is a quadratic polynomial which has no real value of x for which $x^2$ + 1 is zero.
[∴ $x^2 ≥ 0 ⇒ x^2$ + 1 > 0 for all real x]
∴ (b) is true.
(c) The quadratic polynomial
$x^2 – 2x + 1 = (x – 1)^2$ has only one zero i.e. 1
∴ (c) is true.
[∵ $(x – 1)^2$ > 0 at x ≠ 1 and for x = 1, $(x – 1)^2$ = 0]
(d) is false [∵ of (b), (c)]
Hence (d) holds.
If $√{3x^2 + x + 5} = x – 3$, then the given equator has ...... solution/solutions.
Answer: (d)
Square both sides, we shall get x = – 4, $1/2$.
But both of them do not satisfy the given equation.
Solve the simultaneous equations $√{x/y} + √{y/x} = 5/2$; x + y = 10
Answer: (b)
We have $√{x/y} + √{y/x} = 5/2$ ...(1)
and x + y = 10 ...(2)
Now, $√{x/y} + √{y/x} - 5/2 ⇒ {x + y}/√{xy} = 5/2$
⇒ $10/√{xy} = 5/2$ [using eq. (2)]
⇒ $√{xy}$ = 4 ⇒ xy = 16
Thus, the given system of simultaneous equations reduces to
x + y = 10 and xy = 16
⇒ y = 10 – x
and xy = 16
⇒ x(10 – x) = 16
⇒ $x^2$ – 10x + 16 = 0
⇒ (x – 2) (x – 8) = 0 ⇒ x = 2 or x = 8
Now, x = 2 and x + y = 10 ⇒ y = 8
and x = 8 and x + y = 10 ⇒ y = 2
Hence, the required solution are x = 2, y = 8
and x = 8, y = 2
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