Time And Work Mcq Pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Answer: (e)

(7 × 12) men can complete the work in 1 day.

∴ 1 man's 1 day's work = $1/{84}$.

7 men's 5 days' work = $(1/12 × 5) = 5/{12}$.

Remaining work = $(1-{5/12}) = 7/12$.

5 men's 1 day's work = $(1/84 × 5) = 5/{84}$.

$5/{84}$ work is done by them in 1 day.

$7/{12}$ work is done by them in

$({84}/5 × 7/{12}) = {{49}/5} days = 9{4/5}$ days

Answer: (a)

The factors by which the expenses change are = 8/9 × 7/12 × 3/5 × 16380 = 5096 for 7 months.

Answer: (c)

Given (6 M + 8 B) ×10=(26 M + 48 B)×2

⇒60M+80B=52M+96B

⇒8M=16B

⇒1M=2B

∴15M+20B=30B+20B=50B

6M+8B=12B+8B=20B

Now

∴ X = ${20 ×10}/{50}$ = 4days

Answer: (a)

Here $M_1 D_1 = M_2 D_2$

$M_1 = 76 Ladies, M_2$ = x Let

$D_1 = 33 days D_2$ = 44 days

⇒76 × 33 = x × 44

∴ x = 57 days

no. of ladies who did not Report

for work = 76 – 57 = 19.

Answer: (c)

(2M + 7C)'s 1 day's work = $1/4$

⇒ work will be completed by 4 (2M + 7C) = 8 M + 28 C

Again, (4M + 4C)'s 1 day's work = $1/3$

i.e. 12M + 12C will complete the work.

⇒8M + 28C = 12M + 12C or M = 4C

Therefore, 4M + 4C = 5M

Since 5M complete a work in 3 days,

1 M will complete it in 15 days.