lcm and hcf questions answers pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024
ibps rrb so officer sclae 2 3 single exam 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Lcm & Hcf
Ratio & Proportion
Percentage
Time & Work
Mensuration
Advance Math
Trigonometric Ratios & Identities
Average
Profit & Loss
Alligation & Mixtures
Compound Interest
Amit, Sucheta and Neeti start running around a circular track and complete one round in 18, 24 and 32 seconds respectively. In how many seconds will the three meet again at the starting point if they all have started running at the same time ?
Answer: (d)
Time taken
| 2 | 18, | 24, | 32 |
| 2 | 9, | 12, | 16 |
| 2 | 9, | 6, | 8 |
| 3 | 9, | 3, | 4 |
| 3, | 1, | 4 |
2 × 2 × 2 × 3 × 3 × 4 = 288 sec
What greatest number can be subtracted from 10,000 so that the remainder may be divisible by 32, 36, 48 and 54 ?
Answer: (c)
LCM of 32, 36, 48, 54 = 864
∴ the required greatest number = 10,000 – 864 = 9, 136
If 3 $4/5$ is subtracted from 6 $3/5$ and difference is multiplied by 355 then what will be the final number ?
Answer: (b)
$(6{3/5}-3{4/5}) × 355 = (33/5 - 19/5) × 355$
= $({33-19}/5) × 355 = ({14 × 355}/5)=994$
The HCF and LCM of two polynomials are (x + y) and $(3x^5 + 5x^4y + 2x^3y^2 – 3x^2y^3 – 5xy^4 –2y^5)$ respectively. If one of the polynomials is ($x^2 – y^2$), then the other polynomial is 2015-I]
Answer: (b)
HCF × LCM = $1^{st} polynomial × 2^{nd} polynomial$
⇒$2^{nd} polynomial = {HCF × LCM}/{1^{st} Polynomial}$
= ${(x + y)(3x^5 + 5x^4y + 2x^3y^2 - 3x^2y^3 - 5xy^4 - 2y^5)}/{(x^2 - y^2)}$
= $3x^4 + 8x^3 y + 10x^2y^2 + 7xy^3 + 2y^4$
The product of HCF and LCM of 18 and 15 is
Answer: (d)
HCF of 18 and 15 = 3
LCM of 18 and 15 = 2 × 3 × 3 × 5 = 90
∴ Product of HCF and LCM of both numbers
= 3 × 90 = 270
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