lcm and hcf questions answers pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Answer: (c)

(x + 4) is HCF, so it will be common in both expression.

x = – 4 will make each one zero.

∴ 2 $(– 4)^2$ + k (– 4) – 12 = 0

and $(– 4)^2$ + (– 4) – 2k – 2 = 0

⇒32 – 12 = 4k

and 16 – 6 = 2k

∴ k = 5

Answer: (a)

Multiply by 100

3.0 = 300

1 . 2 = 120

0.06 = 6

Now, HCF of (300, 120, 6) = 6

So, HCF (3.0, 1.2, 0.06) = 0.06

Answer: (a)

0.00$\ov7$ + 17.$\ov{83}$ + 310.020$\ov2$

= $7/{900} + {1783 - 17}/{99} + {3100202 - 310020}/{9000}$

= $7/{900} + {1766}/{99} + {2790182}/{9000}$

= ${770 + 1766000 + 30692002}/{99000}$

= ${32458772}/{99000}$ = 327.866$\ov38$

Answer: (c)

Given that, three planets revolves the Sun once in 200, 250, 300 days,.

∴ Required time = LCM of (200, 250, 300) = 3000 days

Now, after 3000 days they all come relatively to the same position as at a certain point of time in their orbits.

Answer: (a)

We find out the LCM of given numbers.

∴ LCM (5, 6, 7, 8) = LCM (5, 2 × 3, 7, 2 × 4)

= 2 × 5 × 3 × 7 × 4 = 840

∴ Required number = 840 + 3 = 843