lcm and hcf questions answers pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Question :11

There are 48 cricket balls, 72 hockey balls and 84 tennis balls and they have to be arranged in several rows in such a way that every row contains the same number balls of balls of one type. What is the minimum number of rows required for this to happen ?

Answer: (b)

HCF of 48, 72 and 84 = $2^2$ × 3 = 12

minimum number of rows = ${48}/{12} + {72}/{12} + {84}/{12}$

= 4 + 6 + 7 = 17

Question :12

What is the HCF of the polynomials $x^4 – 3x + 2, x^3 – 3x^2 + 3x – 1$ and $x^4$ – 1?

Answer: (c)

Let $f_1 (x) = x^4 – 3x + 2 = (x – 1)(x^3 + x^2$ + x – 2)

$f_2 (x) = x^3 – 3x^2 + 3x – 1 = (x – 1)^3$

and $f_3 (x) = x^4 – 1 = (x – 1) (x + 1) (x^2$ + 1)

∴ HCF of $f_1(x), f_2(x), f_3(x)$ = x – 1

Question :13

The numbers 11284 and 7655, when divided by a certain number of three digits, leave the same remainder. Find that number of three digits.

Answer: (b)

The required number must be a factor of (11284 – 7655) or 3629.

Now, 3629 = 19 × 191

∴ 191 is the required number.

Question :14

If (x + k) is the HCF of ($x^2$ + ax + b) and ($x^2$ + cx + d), then what is the value of k ?

Answer: (d)

(x + k) is the HCF of ($x^2$ + ax + b) and ($x^2$ + cx + d).

∴ $(–k)^2$ + a (– k) + b = 0

= $(–k)^2$ + c (– k) + d

⇒(a – c) k = (b – d)

⇒k = ${b - d}/{a - c}$

Question :15

The HCF and LCM of two numbers are 44 and 264 respectively. If the first number is devided by 2, the quotient is 44. What is the other number?

Answer: (b)

The first number = 2 × 44 = 88

∴ The second number = ${HCF × LCM}/88$ = ${44 × 264}/88$ = 132

ibps rrb so officer sclae 2 3 single exam 2024 IMPORTANT QUESTION AND ANSWERS

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