average Model Questions & Answers, Practice Test for ibps clerk prelims

ibps clerk prelims SYLLABUS WISE SUBJECTS MCQs

Number System

Average

Profit & Loss

Question :6

A batsman in his 12th innings makes a score of 63 runs and there by increases his average scores by 2. What is his average after the 12th innings?

Answer: (c)

Avg. after 11 innings = x

Total score after 12

innings = 11x + 63.

Avg. after 12 innings = x + 2

${11x + 63}/12 = x + 2$

11x + 63 = 12x + 24

63 – 24 = 12x – 11x = x = 39.

Avg. after 12th innings

= 39 + 2 = 41

Question :7

We write down all the digits from 1-9 side by side. Now we put '+' between as many digits as we wish to, so that the sum of numbers become 666. It is explained below1 2 3 4 5 6 7 8 9 = 666Now suppose we put plus signs at following places.12 + 345 + 67 + 89 = 513Since there are four numbers, so the average can be calculated by dividing the sum by 4. What is the average if the sum is 666?

Answer: (d)

We can get the sum 666 in two ways:

1 + 2 + 3 + 4 + 567 + 89 = 666

or 123 + 456 + 78 + 9 = 666

So, average cannot be uniquely determined.

Question :8

There are 100 students in 3 sections A, B and C of a class. The average marks of all the 3 sections was 84. The average of B and C was 87.5 and the average marks of A is 70. The number of students in A was

Answer: (a)

Total marks of all three sections = 84 × 100 = 8400

total marks of (B + C) = 87.5 $(n_2 + n_3)$

total marks of A = 70 × $n_1$

$n_1 + n_2 + n_3$ = 100 ...(1)

$70n_1 + 87.5 n_2 + 87.5 n_3$ = 8400 ...(2)

Multiplying equation (1) by 87.5 and subtract from equation (2)

We get 17.5 $n_1$ = 350 ⇒ $n_1$ = 20

Question :9

In an Entrance Examination Ritu scored 56 percent marks, Smita scored 92 percent marks and Rina scored 634 marks. The maximum marks of the examination are 875. What are the average marks scored by all the three girls together?

Answer: (d)

Marks scored by Ritu = 875 × $56/100$ = 490

Marks scored by Smita = 875 × $92/100$ = 805

∴ Average marks scored by all the three together

= ${490 + 805 + 634}/3 = 1929/3$ = 643

Question :10

The ratio of Rita’s age to the age of her mother is 3 : 11. The difference of their ages is 24 yrs. What will be the ratio of their ages after 3 yrs?

Answer: (a)

Difference in ratios = 8

Then 8 ≡ 24 ∴ 1 ≡ 3

i.e., value of 1 in ratio is equivalent to 3 yrs

Thus, Rita's age = 3 × 3 = 9 yrs

Mother's age = 11 × 3 = 33 yrs.

After 3 years, the ratio = 12 : 36 = 1 : 3

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