Practice Profit and loss - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) If the cost price is 95% of the selling price, what is the profit per cent ?
(a)
(b)
(c)
(d)
If the cost price be Rs.x, then
S.P. = $100/95x = Rs.20/19x$
Gain = ${20x}/19 - x = Rs.x/19$
Gain per cent = ${x/19}/x × 100 = 5.26%$
Using Rule 3,
Here C.P. = $95/100$ S.P.
C.P. = S.P.$(100/{100 + Profit%})$
$95/100$ S.P.
= S.P.$(100/{100 + Profit%})$
9500 + 95 profit% = 10000
Profit % = $500/95$ = 5.26%
Q-2) A man bought an old typewriter for Rs.1200 and spent Rs.200 on its repair. He sold it for Rs.1680. His profit per cent is :
(a)
(b)
(c)
(d)
Using Rule 1,
Total cost of typewriter = Rs. (1200 + 200) = Rs.1400
S.P. = Rs.1680
Profit = Rs. (1680 - 1400) = Rs.280
Profit % = $280/1400 × 100 = 20%$
Q-3) If a shirt costs Rs.64 after 20% discount is allowed, what was its original price in Rs.?
(a)
(b)
(c)
(d)
If the original cost of shirt be x, then
$x × 80/100 = 64$
$x = {64 × 100}/80$ = Rs.80
Q-4) If the cost price of an article is 80% of its selling price, the profit per cent is :
(a)
(b)
(c)
(d)
Using Rule 1,
S.P. = Rs.100; C.P. = Rs.80
Gain = Rs.20
∴ Gain per cent = $20/80 ×100$ = 25%
Q-5) By selling 33 metres of cloth, a person gains the cost of 11 metres. Find his gain%.
(a)
(b)
(c)
(d)
Gain per cent
= $11/33 × 100 = 100/3 = 33{1}/3$%
Q-6) A milkman bought 70 litres of milk for Rs.630 and added 5 litres of water. If he sells it at Rs.9.00 per litre, his profit per centage is
(a)
(b)
(c)
(d)
CP of 75 litres of mixture of milk and water = Rs.630
SP of 75 litres of mixture of milk
and water = 9 × 75 = Rs.675
Gain = 675 - 630 = Rs.45
Gain per cent = $45/630 × 100 = 50/7 = 7{1}/7$%
Q-7) The ratio of cost price and selling price is 5 : 4, the loss per cent is :
(a)
(b)
(c)
(d)
According to the question
$\text"Cost price"/ \text"Selling price" = 5/4$
Selling price = $4/5$ × Cost price
Loss = Cost price - Selling price
= Cost price - $4/5$ Cost price = $1/5$ Cost price
Loss % = ${{1/5}\text"Cost price" × 100}/\text"Cost price" = 100/5 = 20%$
Method 2 : Simple Approach
Rs.1 is loss on Rs.5.
loss % = $1/5$ × 100 = 20%
Using Rule 2
If C.P > S.P., then there will be Loss
Loss = C.P. - S.P., Loss% = ${Loss × 100}/{C.P.}$
Here, C.P. = 5x, S.P. = 4x
Loss% = $\text"Loss"/ \text"C.P."$ × 100
= ${5x - 4x}/{5x}$ × 100 = 20%
Q-8) A man buys a cycle for Rs.1400 and sells it at a loss of 15%. What is the selling price of the cycle?
(a)
(b)
(c)
(d)
Using Rule 3,If an object is sold on r% Profit.
then,S.P. = C.P$[{100 + \text"Profit%"}/100]$orC.P. = S.P$[100/{100 + \text"Profit%"}]$
Similarly, If an object is sold on r% loss, then
S.P. = C.P.$[{100 - \text"Loss%"}/100]$orC.P. = S.P$[100/{100 - \text"Loss%"}]$
Selling price = $1400 × {100 - 15}/100$
= $1400 × 85/100$ = Rs.1190
Q-9) The ratio of cost price and selling price of an article is 8 : 9. The profit per cent is
(a)
(b)
(c)
(d)
Using Rule 1,
If S.P > C.P. then there will be profit
Profit = S.P. - C.P.
Profit% = ${\text"Profit" × 100}/{\text"C.P."}$
Let the CP = 8x and SP = 9x
Profit = (9x - 8x) = x
Profit % = $x/{8x} × 100 = 25/2 =12.5%$
Q-10) The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is
(a)
(b)
(c)
(d)
Let the CP of 1 orange = Rs.1
SP of 10 oranges = Rs.13
Gain percent = ${13 - 10}/10 × 100$ = 30%
Using Rule 8,
Here, x = 13, y = 10
Profit % = $({x - y}/y) × 100$
= $({13 - 10}/10) × 100 = 300/10$ = 30%
Q-11) A shopkeeper offers a discount of 10% on his articles. The marked price of the article is Rs.450. The selling price should be
(a)
(b)
(c)
(d)
S.P. of article = ${450 × 90}/100$ = Rs.405
Q-12) A shopkeeper allows a rebate of 12% on the marked price of an article such that the selling price is Rs.440. Then the marked price of the article is
(a)
(b)
(c)
(d)
Marked price of article = Rs.x
x × (100 - 12)% = 440
$x × 88/100$ = 440
$x ={440 × 100}/88$ = Rs.500
Q-13) A sells an article to B making a profit of 1 5 of his outlay. B sells it to C, gaining 20%. If C sells it for Rs.600 and incurs a loss of 1 6 of his outlay, the cost price of article for A is
(a)
(b)
(c)
(d)
If the C.P. for A be Rs.x, then
$x × (1 +1/5) × 120/100 × (1 - 1/6)$ = 600
$x × 6/5 × 6/5 × 5/6 = 600$
$x = {600 × 5}/6$ = Rs.500
Q-14) A saleable article passes successively in the hands of three traders. Each trader sold it further at a gain of 25% of the cost price. If the last trader sold it for Rs.250 then what was the cost price for the first trader ?
(a)
(b)
(c)
(d)
Let the actual C.P. be Rs.x
$x × 125/100 × 125/100 × 125/100 = 250$
x = Rs.128
Q-15) A sells an article to B at a gain of 10%, B sells it to C at a gain of 5%. If C pays Rs.462 for it, what did it cost to A ?
(a)
(b)
(c)
(d)
Let the C.P. for A be Rs.x, then
$x × 110/100 × 105/100 = 462$
$x = {462 × 100 × 100}/{110 × 105}$ = Rs.400
Using Rule 15,
Here, $r_1 = 10%, r_2$ = 5%
C.P. for C = C.P. for A
$(1 + r_1/100)(1 + r_2/100)$
462 = C.P. for A
$(1 + 10/100)(1 + 5/100)$
C.P. for A = ${462 × 100 × 100}/{110 × 105}$ = Rs.400
Q-16) A sells a suitcase to B at 10% profit. B sells it to C at 30% profit. If C pays Rs.2,860 for it, then the price at which A bought it is
(a)
(b)
(c)
(d)
Using Rule 15,
Let the C.P. of the suitcase for A be Rs.x, then
$x × 110/100 × 130/100$ = 2860
$x = {2860 × 100 × 100}/{110 × 130}$ = Rs.2000
Q-17) A book seller sells a book at a profit of 10%. If he had bought it at 4% less and sold it for Rs.6 more, he would have gained 18$3/4%$. The cost price of the book is
(a)
(b)
(c)
(d)
Let the CP of the book be Rs.x.
Initial SP = $110/100 × x = 1.1 x$
New CP = 0.96 x
New SP = $(100 + 75/4)%$ of 0.96x
=$475/400 × 0.96x = 1.14 x$
Therefore, 1.14 x –1.1x = 6
0.04 x = 6
$x = 6/{0.04} = 600/4 = 150$
CP = Rs.150
Q-18) On selling an almirah for Rs.2576, a person got a profit of 12%. Had it been bought for Rs.100 less, the profit per cent would have been
(a)
(b)
(c)
(d)
CP of the article
= $(100/112 × 2576)$ = Rs.2300
New CP = Rs.2200
Gain per cent
= ${2576 - 2200}/2200 × 100 = 17{1}/11$
Q-19) A man sells his typewriter at 5% loss. If he sells it for Rs.80 more, he will gain 5%. The cost price of the typewriter is
(a)
(b)
(c)
(d)
Let the CP of the typewriter be Rs.x.
At 5% loss, SP = ${95x}/100$
Now, ${95x}/100 + 80 = {105x}/100$
${105x}/100 - {95x}/100 = 80$
${105x - 95x}/100 = 80$
$x = 8000/10$ = Rs.800
Using Rule 11,
Here, x = 5%, R = 80, y = 5%
C.P. = ${R × 100}/{y + x}$
= ${80 × 100}/{5 + 5}$ = Rs.800
Q-20) A T.V was sold at a profit of 5%. If it had been sold at a profit of 10%, the profit would have been Rs.1000 more. What is its cost price ?
(a)
(b)
(c)
(d)
Let the C.P. of television be Rs.x.
According to the question,
(10 - 5)% of x = 1000
x × $5/100$ = 1000
$x = {1000 × 100}/5$ = Rs.20000