Practice Model question set 2 - non verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1)
(a)
(b)
(c)
(d)
Q-2)
(a)
(b)
(c)
(d)
The figure in question looks like as shown below after labelling it.
Smallest Triangles = ΔGAH, ΔHFL, ΔLCI, Δ IDJ ΔJBK, ΔKEG = 6
Largest Triangles = ΔABC, ΔEFD = 2
∴ Total Triangles = 6 + 2 = 8
Q-3)
(a)
(b)
(c)
(d)
The figure may be labelled as shown
The Simplest triangles are ABF, BFG, BCG, CGH, GHD, GED, EFG and AFE i.e., 8 in number.
The triangles composed of two components each are ABG, BGE, AGE, ABE and GCD i.e., 5 in number.
The triangles composed of three components each are BCD, CDE, BED and BCE i.e., 4 in number.
Thus, there are 8 + 5 + 4 = 17 triangles in the given figure.
Q-4)
(a)
(b)
(c)
(d)
We shall join the centres of all the circles by horizontal and vertical lines and then label the resulting figure as shown.
The simplest squares are ABED, BCFE, DEHG, EFIH, GHKJ and HILK i.e., 6 in number.
The squares composed of four simple squares are ACIG and DFLJ i.e., 2 in number.
Thus, 6 + 2 = 8 squares will be formed.
Q-5)
(a)
(b)
(c)
(d)
Given figure can be labelled as follows
In the above figure, triangles formed by single units are ΔABE, ΔAEO, ΔAOF, ΔAFC, ΔDEB, ΔDOE, ΔDFO and ΔDCF i.e., 8 triangles.
Triangles formed by Combining 2 units are ΔABO, ΔAEF, ΔAOC, ΔBOD, ΔDEF, ΔDOC, ΔAED and ΔADF i.e., 8 triangles.
Triangles formed by Combining 3 units are ΔABF, ΔAEC, ΔBDF and ΔEDC i.e., 4 triangles.
Triangles formed by Combining 4 units are ΔABC, ΔBCD, ΔABD and ΔACD i.e., 4 triangles.
∴ Total number of Triangles = 8 + 8 + 4 + 4 = 24
Q-6)
(a)
(b)
(c)
(d)
We may the label the figure as shown
The Simplest triangles are AEI, AIH, BEJ, BJF, CFK, CKG, DGL, DLH, EOJ, FOJ, FOG, LOG, HOL and HOE i.e.,14 in number.
The triangles composed of two components each are EAH, FBE, BEO, EOF, BFO, FCG, GDH, HOD, HOG and GOD i.e.,10 in number.
The triangles composed of three components each are EFH, EHG, FGH and EFG i.e.,4 in number.
Thus, there are 14 + 10 + 4 = 28. triangles in the given figure.
Q-7)
(a)
(b)
(c)
(d)
Naming the figure
Names of the squares are
| □ABA'X, | □DEFB', | □C'D'T'S', | □D'V'E'T', |
| □WYP'V, | □S'T'W'Q', | □T'E'U'W', | □G'GHH', |
| □TO'RS, | □M'L'OP, | □L'K'NO, | □I'JKL, |
| □ACT'W, | □CEGT' | □WT'OS, | □T'GKO, |
| □AEKS, | □C'V'U'Q', | □WZN'U. | □ZT'R'N' |
| □T'F'J'R', | □F'GIJ', | □UN'QS, | □N'R'OQ |
| □R'J'MO, | □J'IKM, | □ZF'MQ, |
Hence, there are 27 squares in this figure.
Q-8)
(a)
(b)
(c)
(d)
Horizontal lines = AB, EF, GH, CD, LM, PQ, ON = 7
Vertical lines = AC, EG, FH, BD, LO, MN = 6
∴ Total number of straight lines = 7 + 6 = 13
Q-9)
(a)
(b)
(c)
(d)
The figure may be labelled as shown
The horizontal lines are DF and BC i.e., 2 in number
The vertical lines are DG, AH and FI i.e., 3 in number
The slanting lines are AB, AC, BF and DC i.e., 4 in number
Thus, there are 2 + 3 + 4 = 9 straight lines in the figure.
Now, we shall count the number of triangles in the figure.
The Simplest triangles are ADE, AEF, DEK, EFK, DJK, FLK, DJB, FLC, BJG and LIC i.e.,10 in number.
The triangles composed of two components each are ADF, AFK, DFK, ADK, DKB, FCK, BKH, KHC, DGB and FIC i.e.,10 in number.
The triangles composed of three components each are DFJ and DFL i.e.,2 in number.
The triangles composed of four components each are ABK, ACK, BFI, CDG, DFB, DFC and BKC i.e.,7 in number.
The triangles composed of six components each are ABH, ACH, ABF, ACD, BFC and CDB i.e.,6 in number.
There is only one triangle i.e., ABC composed of twelve components.
Thus, there are 10 + 10 + 2 + 7 + 6 +1 = 36 triangles in the given figure.
Q-10)
(a)
(b)
(c)
(d)
Smallest hexagons = KBCMHI, LCDNGH = 2
Largest hexagons = KBDNGI = 1
∴ Total hexagons = 2 + 1 = 3