Practice Comparing two terms - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) A's income is 25% more than B's income. B's income is what per cent of A's income ?
(a)
(b)
(c)
(d)
Let B's income be Rs. 100.
A's income = Rs. 125
Required percent = $(100/125 × 100)$ = 80%
Q-2) Two numbers are less than a third number by 30% and 37% respectively. The per cent by which the second number is less than the first is
(a)
(b)
(c)
(d)
Third number = 100
First number = 70
Second number = 63
Required percentage = $7/70 × 100$ = 10
Q-3) A number when reduced by 10% gives 30. The number is
(a)
(b)
(c)
(d)
Let the number be x
then, $x × 90/100 = 30$
$x = 3000/90 = 100/3= 33{1}/3$
Q-4) Which number is 40% less than 90 ?
(a)
(b)
(c)
(d)
Required number = 60% of 90 = ${90 × 60}/100$ = 54
Q-5) The difference of two numbers is 20% of the larger number. If the smaller number is 20, the larger number is :
(a)
(b)
(c)
(d)
Let the larger number be x
According to question, x – 20 = 20% of x
or, x – 20 =$x/5$ or, x - $x/5$ = 20
or, 5x – x = 20 × 5 or, 4x = 20 × 5
x = 5 × 5 = 25
Q-6) x is 5 times longer than y. The percentage by which y is less than x is :
(a)
(b)
(c)
(d)
Length of Y = 1 foot
Length of X = 5 feet
Required percent = $({5 – 1}/5) × 100 = 80%$
Q-7) Two numbers are respectively 12$1/2$% and 25% more than a third number. The first number as percentage of second number is
(a)
(b)
(c)
(d)
If the third number is 100, then the numbers are $100 + 25/2 = 225/2$ and 125 respectively.
First number as a percentage of the second = $225/{2×125}×100$ = 90
Using Rule 30,
If two numbers are respectively x% and y% more than a third number the first as a per cent of second is ${100 + x}/{100 + y}$ ×100%
Q-8) B got 20% marks less than A. What per cent marks did A got more than B ?
(a)
(b)
(c)
(d)
Using Rule 9,
Required percentage = $20/{100 - 20} × 100$ = 25%
Q-9) How much 66$2/3$% of Rs. 312 exceeds Rs. 200?
(a)
(b)
(c)
(d)
According to the question, Required difference
= Rs.$(312 × 200/3% - 200)$
= Rs.$(312 × 200/300 - 200)$
= Rs.(208 - 200)= Rs.8
Q-10) If x is less than y by 25% then y exceed x by :
(a)
(b)
(c)
(d)
Let y be 100.
x = 75
Required percentage = ${25×100}/75 = 100/3 = 33{1}/3$%
Using Rule 9,
If ‘x' is A% less than ‘y', then y is more than ‘x' by
Required% = $(A/{(100 - A)}×100)%$(increase)
Required percentage = $25/{(100 - 25)} × 100%$
= $25/75 × 100% = 33{1}/3$%