Practice Coins and rupees based problems - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) A box contains 56 in the form of coins of one rupee, 50 paise and 25 paise. The number of 50 paise coins is double the number of 25 paise coins and four times the number of one rupee coins. How many 50 paise coins are there in the box?
(a)
(b)
(c)
(d)
Number of 1-rupee coins = x
Number of 50 paise coins = 4x
Number of 25 paise coins = 2x
Ratio of their values
= $x : {4x}/2 : {2x}/4$ = 2 : 4 : 1
Value of 50-paise coins
= $4/7 × 56$ = Rs.32
Their number = 32 × 2 = 64
(x )(1)+(4x ) $(1/2)+(2x)(1/4)$= 56
x + 2x + $1/2$x =56
$x = 56 × 2/7$ =16
No. of 50p coins
= 4 × 16 = 64.
Q-2) A boy has a few coins of denominations 50 paise, 25 paise and 10 paise in the ratio 1 : 2 : 3. If the total amount of the coins is 6.50, the number of 10 paise coins is
(a)
(b)
(c)
(d)
Ratio of the value of coins
= $1/2 : 2/4 : 3/10$ = 5 : 5 : 3
Value of the 10-paise coins
= Rs.$(3/13 × 6.50)$ = Rs.1.5
Number of 10-paise coins
= 1.5 × 10 = 15
Q-3) A box has 210 coins of denominations one-rupee and fifty paise only. The ratio of their respective values is 13 : 11. The number of one-rupee coins is
(a)
(b)
(c)
(d)
Respective ratio of the number of coins
= 13 : 11 × 2 = 13 : 22
Number of 1 rupee coins
= $13/{13 + 22} × 210$
= $13/35 × 210 = 78$
Q-4) A box contains 280 coins of one rupee, 50-paise and 25-paise. The values of each kind of the coins are in the ratio of 8 : 4 : 3. Then the number of 50-paise coins is
(a)
(b)
(c)
(d)
Ratio of the values of one rupee, 50 paise and 25 paise coins
= 8 : 4 : 3
Ratio of their number
= 8 : 4 × 2 : 3 × 4 = 2 : 2 : 3
Sum of ratios = 2 + 2 + 3 = 7
Number of 50-paise coins
= $2/7$ × 280 = 80
Q-5) A box contains 420 coins in rupee, 50 paise and 20 paise coins. The ratio of their rupee values being 13 : 11 : 7. The number of 50 paise coins is
(a)
(b)
(c)
(d)
Ratio of their values =13:11:7
Ratio of their numbers
= 13 : 22 : 35
13x + 22x + 35x = 420
70x = 420 ⇒ x = 6
Number of 50 paise coins
= 22x = 22 × 6 = 132
Q-6) A box contains 1-rupee, 50-paise and 25-paise coins in the ratio 8 : 5 : 3. If the total amount of money in the box is 112.50, the number of 50-paise coins is
(a)
(b)
(c)
(d)
Ratio of number of 1 rupee, 50-paise and 25 paise coins
= 8 : 5 : 3
Ratio of their respective values
= $8 : 5/2 : 3/4 = 32 : 10 : 3$
Sum of the ratios
= 32 + 10 + 3 = 45
Value of 50 paise coins
= Rs.$(10/45 × 112.5)$= Rs.25
Number of 50 paise coins
= 25 × 2 = 50
Q-7) In a bag, there are three types of coins — 1-rupee, 50 paise and 25-paise in the ratio of 3 : 8 : 20. Their total value is 372. The total number of coins is
(a)
(b)
(c)
(d)
Ratio of the number of coins of Re. 1, 50 paise and 25 paise
= 3 : 8 : 20
Ratio of the values of these coins
= $3 : 8/2 : 20/4$ = 3 : 4 : 5
Value of 1 rupee coins
= $3/12 × $372 = Rs.93
Value of 50 paise coins
= $4/12 × 372$ = Rs.124
Value of 25 paise coins
= $5/12$ × 372 = Rs.155
Number of coins
= 93 + 124 × 2 + 155 × 4
= 93 + 248 + 620 = 961
Q-8) A bag contains 90 in coins of denominations of 50 paise, 25 paise and 10 paise. If coins of 50 paise, 25 paise and 10 paise are in the ratio 2 : 3 : 5, then the number of 25 paise coins in the bag is
(a)
(b)
(c)
(d)
Ratio of values of 50 paise, 25 paise and 10 paise coins
= $2/2 : 3/4 : 5/10$
= $1 : 3/4 : 1/2$ = 4 : 3 : 2
Sum of the ratios = 4 + 3 + 2 = 9 Value of 25 paise coins
= $3/9 × 90$ = Rs.30
Number of 25 paise coins
= 30 × 4 = 120
Q-9) There are 225 consisting of one rupee, 50 paise and 25 paise coins. The ratio of their numbers in that order is 8 : 5 : 3. The number of one-rupee coins is :
(a)
(b)
(c)
(d)
Ratio of the number of coins
= 8 : 5 : 3
Ratio of their values
= $8 : 5/2 : 3/4$ = 32 : 10 : 3
Sum of the ratios
= 32 + 10 + 3 = 45
Value of one rupee coins
= $32/45 × 225$ = Rs.160
Number of one rupee coins = 160
Q-10) If 378 coins consist of rupees, 50 paise and 25 paise coins, whose values are in the ratio of 13 : 11 : 7, the number of 50 paise coins will be :
(a)
(b)
(c)
(d)
The ratio of values of rupee, 50 paise and 25 paise coins
= 13 : 11 : 7
Ratio of their numbers
= 13 × 1 : 11 × 2 : 7 × 4
= 13 : 22 : 28
Sum of the ratios
= 13 + 22 + 28 = 63
Required number of 50 paise coins
= $22/63 × 378$ = 132